181. Employees Earning More Than Their Managers
The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.
+----+-------+--------+-----------+
| Id | Name | Salary | ManagerId |
+----+-------+--------+-----------+
| 1 | Joe | 70000 | 3 |
| 2 | Henry | 80000 | 4 |
| 3 | Sam | 60000 | NULL |
| 4 | Max | 90000 | NULL |
+----+-------+--------+-----------+
Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.
+----------+
| Employee |
+----------+
| Joe |
+----------+ 自连接
找出比其上司挣得更多的员工 MySQL(1686ms):
SELECT e1.Name AS Employee
FROM Employee AS e1 , Employee AS e2
WHERE e1.ManagerId = e2.Id
AND e1.Salary > e2.Salary ;
181. Employees Earning More Than Their Managers的更多相关文章
- Leetcode 181. Employees Earning More Than Their Managers
The Employee table holds all employees including their managers. Every employee has an Id, and there ...
- 【SQL】181. Employees Earning More Than Their Managers
The Employee table holds all employees including their managers. Every employee has an Id, and there ...
- leetcode 181 Employees Earning More Than Their Managers 不会分析的数据库复杂度
https://leetcode.com/problems/employees-earning-more-than-their-managers/description/ 老师上课没分析这些的复杂度, ...
- LeetCode 181. Employees Earning More Than Their Managers (超过经理收入的员工)
题目标签: 题目给了我们一个 员工表,包括经理.员工会有经理的id. 这里可以重复 利用两次 表格,表格a, 表格b,当a 员工的经理id 等于 b员工时候,在从中找到员工工资大于经理的.具体看co ...
- [LeetCode] Employees Earning More Than Their Managers 员工挣得比经理多
The Employee table holds all employees including their managers. Every employee has an Id, and there ...
- LeeCode(Database)-Employees Earning More Than Their Managers
The Employee table holds all employees including their managers. Every employee has an Id, and there ...
- [SQL]LeetCode181. 超过经理收入的员工 | Employees Earning More Than Their Managers
SQL架构 Create table If Not Exists Employee (Id ), Salary int, ManagerId int) Truncate table Employee ...
- [LeetCode] 181. Employees Earning More Than Their Managers_Easy tag: SQL
The Employee table holds all employees including their managers. Every employee has an Id, and there ...
- LeetCode - Employees Earning More Than Their Managers
Description: The Employee table holds all employees including their managers. Every employee has an ...
随机推荐
- JavaScript SandBox沙箱设计模式
沙箱模式常见于YUI3 core,它是一种采用同一构造器(Constructor)生成彼此独立且互不干扰(self-contained)的实例对象,而从避免污染全局对象的方法. 命名空间 JavaSc ...
- nginx基于域名的虚拟主机配置(本地分布式项目域名配置及测试方法)
最有用的虚拟主机配置方式. 一个域名只能绑定一个ip地址,一个ip地址可以被多个域名绑定. 可以修改host文件实现域名访问. 前提:即使我们在nginx中配置基于域名的虚拟主机,也需要域名解析,即n ...
- ACE线程管理机制-并发控制(3)
转载于:http://www.cnblogs.com/TianFang/archive/2006/12/04/581854.html ACE Condition类属 ACE Condition类属(条 ...
- Educational Codeforces Round 6 A
A. Professor GukiZ's Robot time limit per test 0.5 seconds memory limit per test 256 megabytes input ...
- zabbix问题汇总
1. ::110809.577 resuming IPMI checks on host [10.1.3.41]: connection restored :: seconds :: seconds ...
- 南阳ACM 题目811:变态最大值 Java版
变态最大值 时间限制:1000 ms | 内存限制:65535 KB 难度:1 描述 Yougth讲课的时候考察了一下求三个数最大值这个问题,没想到大家掌握的这么烂,幸好在他的帮助下大家算是解决了 ...
- os.fork()
ret = os.fork() if ret == 0: child_suite # 子进程代码 else: parent_suite # 父进程代码 Python中的fork() 函数可以获得系统中 ...
- iOS多线程
iOS开发Demo(示例程序)源代码
本系列所有开发文档翻译链接地址:iOS7开发-Apple苹果iPhone开发Xcode官方文档翻译PDF下载地址(2013年12月29日更新版) iOS程序源代码下载链接:01.大任务.zip22 ...
- Billboard HDU 2795 (线段树)
题目链接 Problem Description At the entrance to the university, there is a huge rectangular billboard of ...
- 初识费用流 模板(spfa+slf优化) 餐巾计划问题
今天学习了最小费用最大流,是网络流算法之一.可以对于一个每条边有一个容量和一个费用(即每单位流的消耗)的图指定一个源点和汇点,求在从源点到汇点的流量最大的前提下的最小费用. 这里讲一种最基础也是最好掌 ...