1. MissingInteger 最小遗失整数 Find the minimal positive integer not occurring in a given sequence.
package com.code;
import java.util.Arrays;
public class Test04_1 {
public static int solution(int[] A) {
int size = A.length;
if(size==1){ // handle one element array
if(A[0]==1){
return 2;
}else{
return 1;
}
}
Arrays.sort(A); // sort by JDK
if(A[0]>1){ // handle all elements bigger than 1
return 1;
}
if(A[size-1]<=0){ // handle all elements are negative
return 1;
}
int i=0;
for(i=0;i<size-1;i++){
if(A[i]>=0 && (A[i+1]-A[i]>1)){ // handle no consecutive array which start with 1
return A[i]+1;
}
}
if(i==size-1){ // handle consecutive array , handle negative elements too.
return A[size-1]+1>0?A[size-1]+1:1;
}
return 1;
}
public static void main(String[] args) {
int [] a = {1,1,2,3,4,5};
System.out.println(solution(a));
int [] b = {-4,-2,0,5};
System.out.println(solution(b));
int [] c = {2};
System.out.println(solution(c));
int [] d = {-2,0,100,102,200};
System.out.println(solution(d));
int [] e = {2,4,5,6};
System.out.println(solution(e));
}
}
/**
*
* 1. MissingInteger
Find the minimal positive integer not occurring in a given sequence.
* Write a function:
*
* class Solution { public int solution(int[] A); }
*
* that, given a non-empty zero-indexed array A of N integers, returns the minimal positive integer (greater than 0) that does not occur in A.
*
* For example, given:
*
* A[0] = 1 A[1] = 3 A[2] = 6 A[3] = 4 A[4] = 1 A[5] = 2 the function should return 5.
*
* Assume that:
*
* N is an integer within the range [1..100,000]; each element of array A is an integer within the range [−2,147,483,648..2,147,483,647]. Complexity:
*
* expected worst-case time complexity is O(N); expected worst-case space complexity is O(N),
* beyond input storage (not counting the storage required for input arguments). Elements of input arrays can be modified.
*
*/
1. MissingInteger 最小遗失整数 Find the minimal positive integer not occurring in a given sequence.的更多相关文章
- 【OpenJ_Bailian - 4137】最小新整数 (贪心)
最小新整数 Descriptions: 给定一个十进制正整数n(0 < n < 1000000000),每个数位上数字均不为0.n的位数为m.现在从m位中删除k位(0<k < ...
- Java中最小的整数为什么是-2147483648
Java中最小的整数为什么是-2147483648 假如只有两位来表示数字,第一位是符号位: 00:0 01:1 11:-1,这个是负数,而且是补码,取反为00,加1成为01,就是-1 10:-2,这 ...
- NOI4.6 最小新整数——切山游戏
描述 给定一个十进制正整数n(0 < n < 1000000000),每个数位上数字均不为0.n的位数为m. 现在从m位中删除k位(0<k < m),求生成的新整数最小为多少? ...
- 寻找失踪的整数数组(Find the missing integer)
排列a包含N分子,其元素属于[0,N]之间,且不存在反复的元素.请你找出数组中缺失的元素(由于[0,N]之间有N+1个元素.而数组仅仅能存储N个元素.所以必定缺少一个元素).当中对数组的操作满足下列的 ...
- 为什么实数系里不存在最小正数?(Why the smallest positive real number doesn't exist in the real number system ?)
We define the smallest positive real number as the number which is explicitly greater than zero and ...
- counting elements--codility
lesson 4: counting elements 1. FrogRiverOne 2. PermCheck 3. MissingInteger 4. MaxCounters lesson 4: ...
- hdu 5108(数论-整数分解)
Alexandra and Prime Numbers Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (J ...
- Alexandra and Prime Numbers(思维)
Alexandra and Prime Numbers Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (J ...
- sdut3140 A*B(math)
题目:传送门 题目描述 Your task is to find the minimal positive integer number Q so that the product of digits ...
随机推荐
- Canvas入门笔记-实现极简画笔
今天学习了Html5 Canvas入门,已经有大神写得很详细了http://www.cnblogs.com/tim-li/archive/2012/08/06/2580252.html#8 在学习过后 ...
- 支持多种格式的播放器js代码
FLV需要播放器,其它视频格式直接插入相应的代码即可. ------------------------------------- /** *视频播放 by zhensheng@ *参数说明 ...
- working hard to be a professional coder
1:read 2 : code 3 : 勤奋 4:技术栈 就前端主流技术框架的发展而言,过去的几年里发展极快,在填补原有技术框架空白和不足的同时也渐渐趋于成熟.未来前端在已经趋向成熟的技术方向上面将会 ...
- JavaScript(十)基本包装类
基本包装类都具有对象的基本方法 toString 和 valueOf Number 数字是原始类型,那为啥还有方法? 因为他在执行方法的时候会创建一个对应的包装类对象,这个对象有这种方法, ...
- Android基础TOP7_1:ListView制作列表
结构: Activity: activity_main: <RelativeLayout xmlns:android="http://schemas.android.com/apk/r ...
- java多线程(线程通信-等待换新机制-代码优化)
等待唤醒机制涉及方法: wait():让线程处于冻结状态,被wait的线程会被存储到线程池中. noticfy():唤醒同一个线程池中一个线程(任意也可能是当前wait的线程) notifyAll() ...
- ubuntu部署java环境
一.安装java sudo add-apt-repository ppa:webupd8team/java sudo apt-get update sudo apt-get install oracl ...
- HTML meta信息含义
<meta name="viewport" content="width=device-width,initial-scale=1.0"> cont ...
- HDU_1018_n(1e7)的阶乘的结果的位数
http://acm.hdu.edu.cn/showproblem.php?pid=1018 Big Number Time Limit: 2000/1000 MS (Java/Others) ...
- Explaining difference between automaticallyAdjustsScrollViewInsets, extendedLayoutIncludesOpaqueBars, edgesForExtendedLayout
automaticallyAdjustsScrollViewInsets:在导航栏透明时用到 In your viewDidLoad method, add if([self respondsToSe ...