A proper vertex coloring is a labeling of the graph's vertices with colors such that no two vertices sharing the same edge have the same color. A coloring using at most k colors is called a (proper) k-coloring.

Now you are supposed to tell if a given coloring is a proper k-coloring.

Input Specification:

Each input file contains one test case. For each case, the first line gives two positive integers N and M (both no more than 1), being the total numbers of vertices and edges, respectively. Then M lines follow, each describes an edge by giving the indices (from 0 to N−1) of the two ends of the edge.

After the graph, a positive integer K (≤ 100) is given, which is the number of colorings you are supposed to check. Then Klines follow, each contains N colors which are represented by non-negative integers in the range of int. The i-th color is the color of the i-th vertex.

Output Specification:

For each coloring, print in a line k-coloring if it is a proper k-coloring for some positive k, or No if not.

Sample Input:

10 11
8 7
6 8
4 5
8 4
8 1
1 2
1 4
9 8
9 1
1 0
2 4
4
0 1 0 1 4 1 0 1 3 0
0 1 0 1 4 1 0 1 0 0
8 1 0 1 4 1 0 5 3 0
1 2 3 4 5 6 7 8 8 9

Sample Output:

4-coloring
No
6-coloring
No
Solution:
  这道题很水,就是一个简单的判断图的边的两个顶点是不是同一个颜色,把图的精髓都没考出来,唯一有点考点的就是需要使用一个set来统计有几种颜色。
 #include <iostream>
#include <vector>
#include <unordered_set>
using namespace std;
int main()
{
int n, m, k;
cin >> n >> m;
vector <vector<int>>path(n);
while (m--)
{
int a, b;
cin >> a >> b;
path[a].push_back(b);
path[b].push_back(a);
}
cin >> k;
while (k--)
{
vector<int>color(n, );
unordered_set<int>nums;
for (int i = ; i < n; ++i)
{
cin >> color[i];
nums.insert(color[i]);
}
bool flag = true;
for (int i = ; i < n && flag; ++i)
{
for (auto j : path[i])
{
if (color[i] == color[j])
{
flag = false;
break;
}
}
}
if (flag)
printf("%d-coloring\n", nums.size());
else
printf("No\n");
}
return ;
}

PAT甲级——A1154 VertexColoring【25】的更多相关文章

  1. PAT 甲级 1010 Radix (25)(25 分)进制匹配(听说要用二分,历经坎坷,终于AC)

    1010 Radix (25)(25 分) Given a pair of positive integers, for example, 6 and 110, can this equation 6 ...

  2. PAT 甲级1003 Emergency (25)(25 分)(Dikjstra,也可以自己到自己!)

    As an emergency rescue team leader of a city, you are given a special map of your country. The map s ...

  3. pat 甲级 1010. Radix (25)

    1010. Radix (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given a pair of ...

  4. pat 甲级 1078. Hashing (25)

    1078. Hashing (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue The task of t ...

  5. PAT 甲级 1003. Emergency (25)

    1003. Emergency (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue As an emerg ...

  6. PAT 甲级 1078 Hashing (25 分)(简单,平方二次探测)

    1078 Hashing (25 分)   The task of this problem is simple: insert a sequence of distinct positive int ...

  7. PAT 甲级 1070 Mooncake (25 分)(结构体排序,贪心,简单)

    1070 Mooncake (25 分)   Mooncake is a Chinese bakery product traditionally eaten during the Mid-Autum ...

  8. PAT 甲级 1032 Sharing (25 分)(结构体模拟链表,结构体的赋值是深拷贝)

    1032 Sharing (25 分)   To store English words, one method is to use linked lists and store a word let ...

  9. PAT 甲级 1029 Median (25 分)(思维题,找两个队列的中位数,没想到)*

    1029 Median (25 分)   Given an increasing sequence S of N integers, the median is the number at the m ...

随机推荐

  1. Vue2.0---webpack打包知识点-1

    打包上线或者将项目做成产品的肯定不希望暴露自己源码 在config的index.js中将productionGzip设置为false即可.(使之不生成.map文件). 对Vue-cli的webpack ...

  2. C语言|博客作业12

    一.我学到的内容(整理本课程所学,[用思维导图的方式] 二.我的收获(包括我完成的所有作业的链接+收获)不能只有作业链接,没有收获 作业链接 收获 https://edu.cnblogs.com/ca ...

  3. SpringBoot连接Oracle

    pom.xml <?xml version="1.0" encoding="UTF-8"?> <project xmlns="htt ...

  4. 使用phpexcel导入excel文件种的时期数据时数据导入格式

    在使用phpexcel导入类似于 YYYY-MM-DD HH:ii:ss格式的数据时,导入成功以后会发现导入的数据其实是类似于42085.746516204格式的数据( excel在存储时间类型的数据 ...

  5. Oracle学习笔记<5>

    组函数(多值函数) 数据库中函数的分类:1)单值函数 Single Rows Functions 特点:n条数据参与函数处理,最终得到n条结果.2)多值函数(组函数) Multiple Rows Fu ...

  6. webstorm的下载、破解、与汉化

    其实很简单的事情,都被我弄复杂了倒腾了很久,特做个记录. 说明前提,版本为 webstorm 2018.1.4 一.下载webstorom 下载地址:当然去官网啊  https://www.jetbr ...

  7. RabbitMq--3--案例

      https://blog.csdn.net/hellozpc/article/details/81436980

  8. Java开发中的23种设计模式详解(2)结构型

    我们接着讨论设计模式,上篇文章我讲完了5种创建型模式,这章开始,我将讲下7种结构型模式:适配器模式.装饰模式.代理模式.外观模式.桥接模式.组合模式.享元模式.其中对象的适配器模式是各种模式的起源,我 ...

  9. Java数组遍历

    1.数组声明格式: 数据类型 [] 数组名 = new 数据类型[长度]: 数组长度一旦确定无法更改. 数组里的数据必须是相同类型或自动向上转型后兼容的类型 2.数组遍历 //一维数组 String ...

  10. PHP 遍历数组for foreach while

    以下是使用foreach  while  for 三种循环展示遍历数组的概念 1:foreach( ) <?php $a = array('hank','mike','lucy'); forea ...