LeetCode()Substring with Concatenation of All Words 为什么我的超时呢?找不到原因了!!!
超时代码
class Solution {
public:
vector<int> findSubstring(string s, vector<string>& words) {
map<string,int> coll;
for(auto i:words)
coll[i]++;
vector<int> res;
int len=words[0].size(),sum=words.size();
for(int k=0;k<=s.length()-len*sum;k++)
if(check(s,k,len,sum,coll))
res.push_back(k);
return res;
}
bool check(string s,int start,int len,int sum,map<string,int> coll)
{
for(int i=start;i<=s.length()-len && sum!=0;i+=len)
{
string str=s.substr(i,len);
auto d=coll.find(str);
if(coll[str]>0 && d != coll.end())
{
coll[str]--;
sum--;
}
else
return false;
}
if(sum==0)
return true;
else
return false;
}
};
这个和我的没有什么区别吧?为什么就可以呢?
class Solution {
private:
int wordLen;
public:
vector<int> findSubstring(string S, vector<string> &L) {
unordered_map<string, int>wordTimes;
for(int i = 0; i < L.size(); i++)
wordTimes[L[i]]++;
wordLen = L[0].size();
vector<int> res;
for(int i = 0; i <= (int)(S.size()-L.size()*wordLen); i++)
if(helper(S, i, wordTimes, L.size()))
res.push_back(i);
return res;
}
//判断子串s[index...]的前段是否能由L中的单词组合而成
bool helper(const string &s, int index,
unordered_map<string, int>wordTimes, int wordNum)
{
for(int i = index; wordNum != 0 && i <= (int)s.size()-wordLen; i+=wordLen)
{
string word = s.substr(i, wordLen);
auto ite = wordTimes.find(word);
if(ite != wordTimes.end() && ite->second > 0)
{ite->second--; wordNum--;}
else return false;
}
if(wordNum == 0)return true;
else return false;
}
};
LeetCode()Substring with Concatenation of All Words 为什么我的超时呢?找不到原因了!!!的更多相关文章
- LeetCode: Substring with Concatenation of All Words 解题报告
Substring with Concatenation of All Words You are given a string, S, and a list of words, L, that ar ...
- [LeetCode] Substring with Concatenation of All Words 串联所有单词的子串
You are given a string, s, and a list of words, words, that are all of the same length. Find all sta ...
- LeetCode:Substring with Concatenation of All Words (summarize)
题目链接 You are given a string, S, and a list of words, L, that are all of the same length. Find all st ...
- [leetcode]Substring with Concatenation of All Words @ Python
原题地址:https://oj.leetcode.com/problems/substring-with-concatenation-of-all-words/ 题意: You are given a ...
- Leetcode Substring with Concatenation of All Words
You are given a string, S, and a list of words, L, that are all of the same length. Find all startin ...
- [LeetCode] Substring with Concatenation of All Words(good)
You are given a string, S, and a list of words, L, that are all of the same length. Find all startin ...
- Leetcode:Substring with Concatenation of All Words分析和实现
题目大意是传入一个字符串s和一个字符串数组words,其中words中的所有字符串均等长.要在s中找所有的索引index,使得以s[index]为起始字符的长为words中字符串总长的s的子串是由wo ...
- LeetCode HashTable 30 Substring with Concatenation of All Words
You are given a string, s, and a list of words, words, that are all of the same length. Find all sta ...
- leetcode面试准备: Substring with Concatenation of All Words
leetcode面试准备: Substring with Concatenation of All Words 1 题目 You are given a string, s, and a list o ...
随机推荐
- DB2事务日志已满的解决方法
DB2命令终端输入: db2 update db cfg for <dbname> using LOGPRIMARY 50 db2 update db cfg for <dbname ...
- 端口占用问题——netstat命令
1.查看所有的端口占用情况 C:\>netstat -ano 协议 本地地址 外部地址 状态 PID(进程号) TCP 127.0.0.1:1434 ...
- JS设计模式书籍、原则
圣经书:JavaScript 高级程序设计 设计模式:DesignPatterns by Erich Gamma.Richard Hlem.Ralph Johnson .Jhon Vlissides ...
- php大力力 [025节] 来不及学习和分类的,大力力认为有价值的一些技术文章合集(大力力二叔公)(2015-08-27)
php大力力 [025节] 来不及学习和分类的,大力力认为有价值的一些技术文章合集(大力力二叔公)(2015-08-27) 比较好的模版 免费模板网,提供大量DIV+CSS布局网页模板下载及后台管理 ...
- 转发:在开发机上绕过Chrome同源策略的办法
在开发机上绕过Chrome同源策略的办法 标签: Chrome同源策略跨域 2013-08-21 18:33 4399人阅读 评论(0) 收藏 举报 分类: Chrome扩展(1) 版权声明:本文为博 ...
- 20145210 《Java程序设计》第08周学习总结
第十四章 NIO与NIO2 14.1 认识NIO •NIO概述 •NIO使用频道来衔接数据结点 •在处理数据时,NIO可以让你设定缓冲区容量 •Channel架构与操作 •isOpen():确认Cha ...
- Android点击View显示PopupWindow,再次重复点击View关闭PopupWindow
Android点击View显示PopupWindow,再次重复点击View关闭PopupWindow 这本身是一个看似很简单的问题,但是如果设置不当,就可能导致莫名其妙失效问题.通常在Andro ...
- 重学STM32---(六)DAC+DMA+TIM
这两天复习了DAC,DMA再加上把基本定时器TIM6和TIM7看了一下,打算写一个综合点的程序,,,就在网上找了一些关于DAC,DMA和定时器相关的程序,最终打算写了输出正弦波的程序... 由于没有示 ...
- 如何给magento的产品页面添加返回按钮
如何给magento的产品页面添加返回按钮,最模板提供教程 第一步: 打开 E:\xampp\htdocs\magento\skin\frontend\default\bluescale\css\st ...
- JS删除HTML元素问题
<div id='one'> <div>1</div> <div>2</div> </div> <div id=" ...