leetcode16—3 Sum Closet

Given an array nums of n integers and an integer target, find three integers in nums such that the sum is closest to target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

Example:

Given array nums = [-1, 2, 1, -4], and target = 1.

The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

想法：与之前的类似，使用双指针，另外设立一个变量去保存最接近target的值

class Solution {
public:
    int threeSumClosest(vector<int>& nums, int target) {
        int len = nums.size();
         > len)
            ;
        ) + nums.at() + nums.at();
        sort(nums.begin(),nums.end());
         ; i < len- ; i++){
             && nums[i] == nums[i-])
                continue;
            ;
            ;
            while(left < right){
                int sum = nums.at(i) + nums.at(left) + nums.at(right);
                if(sum == target)
                    return sum;
                if(abs(sum - target) < abs(temp - target)){
                    temp = sum;
                }
                if(sum < target){
                    left++;
                }else{
                    right--;
                }
            }
        }
        return temp;
    }
};