【JAVA、C++】 LeetCode 008 String to Integer (atoi)
Implement atoi to convert a string to an integer.
Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.
Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.
解题思路:
本题难度并不大,比较无聊,主要是要考虑到几个边界条件,本人也是提交数次才通过的。
JAVA代码如下:
static public int myAtoi(String str) {
if (str == null )
return 0;
str = str.trim();
if(str.length()==0)
return 0;
boolean isNagetive = false;
if (str.charAt(0) == '-')
isNagetive = true;
long result = 0;
for (int i = 0; i < str.length(); i++) {
if(i==0&&(str.charAt(0)=='-'||str.charAt(0)=='+'))
continue;
int temp = str.charAt(i) - '0';
if (temp >= 0 && temp <= 9)
{
if(isNagetive){
result=result * 10 - temp;
}
else result = result * 10 + temp;
if (result > Integer.MAX_VALUE)
return Integer.MAX_VALUE;
if (result < Integer.MIN_VALUE)
return Integer.MIN_VALUE;
}
else break;
}
return (int) result;
}
C++
#include<algorithm>
using namespace std;
class Solution {
public:
int myAtoi(string str) {
bool isFirstChar = true, isNagetive = false;
long result = ;
for (int i = ; i < str.length(); i++) {
if (isFirstChar&&str[i] == ' ')
continue;
if (isFirstChar&&str[i] == '-') {
isNagetive = true;
isFirstChar = false;
continue;
}
if (isFirstChar&&str[i] == '+') {
isFirstChar = false;
continue;
}
int temp = str[i] - '';
if (temp >= && temp <= )
{
if (isNagetive) {
result = result * - temp;
}
else result = result * + temp;
if (result > INT_MAX)
return INT_MAX; if (result < INT_MIN)
return INT_MIN;
}
else break;
isFirstChar = false;
}
return (int)result;
}
};
【JAVA、C++】 LeetCode 008 String to Integer (atoi)的更多相关文章
- 【JAVA、C++】LeetCode 013 Roman to Integer
Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 t ...
- 【JAVA、C++】LeetCode 005 Longest Palindromic Substring
Given a string S, find the longest palindromic substring in S. You may assume that the maximum lengt ...
- 【JAVA、C++】LeetCode 018 4Sum
Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = tar ...
- 【JAVA、C++】LeetCode 015 3Sum
Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all un ...
- 【JAVA、C++】LeetCode 022 Generate Parentheses
Given n pairs of parentheses, write a function to generate all combinations of well-formed parenthes ...
- 【JAVA、C++】LeetCode 010 Regular Expression Matching
Implement regular expression matching with support for '.' and '*'. '.' Matches any single character ...
- 【JAVA、C++】LeetCode 007 Reverse Integer
Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 解题思路:将数字 ...
- 【JAVA、C++】LeetCode 006 ZigZag Conversion
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like ...
- 【JAVA、C++】LeetCode 003 Longest Substring Without Repeating Characters
Given a string, find the length of the longest substring without repeating characters. For example, ...
随机推荐
- Sublime text 快捷键总结
下述快捷键都是我写C++代码时发现的,是否适用其他格式(扩展名)的文件尚为未知. Basic Editing Ctrl + A 全选 Ctrl + S 保存 Ctrl + C 复制 Ctrl + V ...
- Codeforces 556D Restructuring Company
传送门 D. Restructuring Company time limit per test 2 seconds memory limit per test 256 megabytes input ...
- Bootstrap教程:[4]栅格系统详解
http://jingyan.baidu.com/article/6f2f55a1852aa1b5b83e6c5a.html 们都知道bootstrap3.0使用了四种栅格选项来形成栅格系统,这四种选 ...
- PHP利用Filesystem函数实现操作缓存(生成,获取,删除操作)
<?php class File{ //$key 相当于缓存文件的文件名 //$value 缓存数据 private $_dir;//定义默认路径 const EXT='.txt'; publi ...
- Java初学(六)
一.final(最终)可以修饰类.方法.变量 特点:final修饰类,该类不能被继承 final修饰方法,该方法不能被重写(覆盖.重载.复写) final修饰变量,该变量不能被重新赋值. ...
- Matlab中的括号()[]{}
Matlab中的括号()[]{} Matlab中经常会用到括号去引用某Array或者是cell的内容,但三者有什么具体区别呢?[ ] 中括号用来构建向量(Vectors)或者是矩阵(Matrices) ...
- dedecms网站栏目增加缩略图的方法-测试通过
有时候因为网站功能需求,我们需要为织梦程序的栏目页添加缩略图功能,这里有一个栏目添加缩略图的方法,供大家参考 涉及到文件如下(注意备份): dede/catalog_add.php dede/cata ...
- CSS transition 过渡 详解
transition 过渡 IE10.Firefox.Chrome.Opera 支持 transition 属性. Safari 需要前缀 -webkit-. Chrome 25 以及更早版本需要前缀 ...
- background总结
1. background-position background-position的百分比属性规则是:图片本身(x%,y%)的那个点,与背景区域的(x%,y%)的那个点重合. 具体可参考: http ...
- Serenity框架官方文档翻译3.2(多租户)
3.2多租户 在本教程中我们将把Norhwind变成一个多租户应用程序. 这是一个维基百科的多租户软件定义: 软件多租户是指一个软件架构的一个实例软件运行在一个服务器和多个租户.租户是一组共享一个公共 ...