Description

There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from their hometown, Ivan, Artsem and Konstantin take a flight to the contest and back.

Jinotega's best friends, team Base have found a list of their itinerary receipts with information about departure and arrival airports. Now they wonder, where is Jinotega now: at home or at some competition far away? They know that:

  • this list contains all Jinotega's flights in this year (in arbitrary order),
  • Jinotega has only flown from his hometown to a snooker contest and back,
  • after each competition Jinotega flies back home (though they may attend a competition in one place several times),
  • and finally, at the beginning of the year Jinotega was at home.

Please help them to determine Jinotega's location!

Input

In the first line of input there is a single integer n: the number of Jinotega's flights (1 ≤ n ≤ 100). In the second line there is a string of 3 capital Latin letters: the name of Jinotega's home airport. In the next n lines there is flight information, one flight per line, in form "XXX->YYY", where "XXX" is the name of departure airport "YYY" is the name of arrival airport. Exactly one of these airports is Jinotega's home airport.

It is guaranteed that flights information is consistent with the knowledge of Jinotega's friends, which is described in the main part of the statement.

Output

If Jinotega is now at home, print "home" (without quotes), otherwise print "contest".

Examples
input
4
SVO
SVO->CDG
LHR->SVO
SVO->LHR
CDG->SVO
output
home
input
3
SVO
SVO->HKT
HKT->SVO
SVO->RAP
output
contest
Note

In the first sample Jinotega might first fly from SVO to CDG and back, and then from SVO to LHR and back, so now they should be at home. In the second sample Jinotega must now be at RAP because a flight from RAP back to SVO is not on the list.

题意:告诉我们飞机的航班流程,年初在家,(注意题目说从家里出发是会回来的)最后问我们,他是在home还是contest

解法:既然从家里出发会返回,那么我们只要比较出现家的次数奇偶性就行,偶数就是在家,奇数就是还没有回来

 #include<bits/stdc++.h>
using namespace std;
int n;
char s1[],s2[];
int main()
{
int ans=;
cin>>n;
scanf("%s",s1);
for(int i=;i<n;i++)
{
scanf("%s",s2);
if(strstr(s2,s1)!=NULL)
{
ans++;
}
}
if(ans%)
{
cout<<"contest";
}
else
{
cout<<"home";
}
return ;
}

Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) A的更多相关文章

  1. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) F. Souvenirs 线段树套set

    F. Souvenirs 题目连接: http://codeforces.com/contest/765/problem/F Description Artsem is on vacation and ...

  2. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) E. Tree Folding 拓扑排序

    E. Tree Folding 题目连接: http://codeforces.com/contest/765/problem/E Description Vanya wants to minimiz ...

  3. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) D. Artsem and Saunders 数学 构造

    D. Artsem and Saunders 题目连接: http://codeforces.com/contest/765/problem/D Description Artsem has a fr ...

  4. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) C. Table Tennis Game 2 水题

    C. Table Tennis Game 2 题目连接: http://codeforces.com/contest/765/problem/C Description Misha and Vanya ...

  5. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) B. Code obfuscation 水题

    B. Code obfuscation 题目连接: http://codeforces.com/contest/765/problem/B Description Kostya likes Codef ...

  6. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) A. Neverending competitions 水题

    A. Neverending competitions 题目连接: http://codeforces.com/contest/765/problem/A Description There are ...

  7. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) A B C D 水 模拟 构造

    A. Neverending competitions time limit per test 2 seconds memory limit per test 512 megabytes input ...

  8. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) E. Tree Folding

    地址:http://codeforces.com/contest/765/problem/E 题目: E. Tree Folding time limit per test 2 seconds mem ...

  9. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) D. Artsem and Saunders

    地址:http://codeforces.com/contest/765/problem/D 题目: D. Artsem and Saunders time limit per test 2 seco ...

  10. Codeforces Round #397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined) C - Table Tennis Game 2

    地址:http://codeforces.com/contest/765/problem/C 题目: C. Table Tennis Game 2 time limit per test 2 seco ...

随机推荐

  1. Bestcoder round 18---A题(素数筛+素数打表+找三个素数其和==n)

    Primes Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)To ...

  2. SDUT OJ 之 1571 《人品,有没有?》 字符串的处理问题

    人品,有木有? Time Limit: 1000ms   Memory limit: 32768K  有疑问?点这里^_^ 题目描述 新一届的山东理工大学ACM网络擂台赛就要开始啦!听说晋级的选手有机 ...

  3. VK Cup 2015 - Round 2 E. Correcting Mistakes —— 字符串

    题目链接:http://codeforces.com/contest/533/problem/E E. Correcting Mistakes time limit per test 2 second ...

  4. git比较两个版本,获取所有代码有差别的文件,并拷贝到一个文件夹中

    git diff 3b3855d a024af5 --name-only | xargs -i cp '{}' ./update/ --parents 解释:通过xargs 命令,把git diff  ...

  5. 关于使用response.addHeader下载中文名乱码问题

    介绍下我项目中遇到的问题:在数据库导出Excel文件的过程中,导出文件中文名始终异常,最终结果发现需要在response.addHeader 中的 filename = "xxxx" ...

  6. Vue.js style(内联样式)

    Vue.js style(内联样式) 我们可以在 v-bind:style 直接设置样式: <div id="app"> <div v-bind:style=&q ...

  7. IO多路复用模型之epoll实现机制

    设想一下如下场景:有100万个客户端同时与一个服务器进程保持着TCP连接.而每一时刻,通常只有几百上千个TCP连接是活跃的(事实上大部分场景都是这种情况).如何实现这样的高并发? 在select/po ...

  8. node.js版本管理(Win) --- nvm-window

    目录 1. 安装 2. 使用 1. 安装 去往Git链接:https://github.com/coreybutler/nvm-windows. 点击下载链接: 选择第一个nvm-noinstall. ...

  9. web2py远程开发

    Hyper-v下安装测试环境: CentOS 6.5, 默认的Python 2.6, web2py 主机Win8.1 问题:远程管理显示“管理因不安全通道而关闭”,只能访问网页,不能进入管理界面. 找 ...

  10. Maven下org.junit.Test无法使用

    原文地址: https://blog.csdn.net/allenChenZhiMing/article/details/81412983 我在看Spring in action(第四版)的时候,看到 ...