luogu4011 孤岛营救问题 分层图

关键词：分层图 状态压缩 最短路径

分层图：现在要求从起点到终点的最优路线，但受到手里拿着哪些钥匙的影响，最优路线不单纯了。因此，决定一个节点、一条边的存在的数中应当增加一个手中拿有钥匙的状态。这样就相当于把一张图按拿有钥匙的状态数分出了很多层。

状态压缩：手中拿有钥匙的状态可以压缩到一个整数中。

最短路径：手中拿有钥匙的状态固定了，在分层图中我们就不再用得着走回头路了。这样就转化成了最短路径问题。

#include <cstdio>
#include <cassert>
#include <cstring>
#include <algorithm>
#include <cmath>
using namespace std;

const int MAX_X = , MAX_Y = , MAX_KEY = , MAX_S =  << , INF = 0x3f3f3f3f;
int Dist[MAX_X][MAX_Y][MAX_S];
int Key[MAX_X][MAX_Y];
int Gate[MAX_X][MAX_Y][MAX_X][MAX_Y];
int TotX, TotY;
const int xNext[] = { ,-,,, }, yNext[] = { , ,,-, };

struct Queue
{
    int xs[MAX_X*MAX_Y*MAX_S], ys[MAX_X*MAX_Y*MAX_S], ss[MAX_X*MAX_Y*MAX_S];
    int head, tail;
    Queue() { head = tail = ; }
    void push(int x, int y, int s) { xs[tail] = x; ys[tail] = y; ss[tail] = s; tail++; }
    void pop() { head++; }
    bool empty() { return head == tail; }
    int frontX() { return xs[head]; }
    int frontY() { return ys[head]; }
    int frontS() { return ss[head]; }
};

int Bfs()
{
    int ans = INF;
    static Queue q;
    Dist[][][Key[][]] = ;
    q.push(, , Key[][]);
    while (!q.empty())
    {
        int x = q.frontX(), y = q.frontY(), s = q.frontS();
        q.pop();
        Dist[x][y][s | Key[x][y]] = Dist[x][y][s];
        s |= Key[x][y];
        for (int p = ; p <= ; p++)
        {
            int x2 = x + xNext[p], y2 = y + yNext[p];
            if (x2 >=  && x2 <= TotX && y2 >=  && y2 <= TotY &&
                Dist[x2][y2][s]==INF &&
                (Gate[x][y][x2][y2] == - || s&( << Gate[x][y][x2][y2])))
            {
                Dist[x2][y2][s] = Dist[x][y][s] + ;
                q.push(x2, y2, s);
                if (x2 == TotX&&y2 == TotY)
                    ans = min(ans, Dist[x2][y2][s]);
            }
        }
    }
    return ans;
}

int main()
{
#ifdef _DEBUG
    freopen("c:\\noi\\source\\input.txt", "r", stdin);
#endif
    int totObs, totKeySort, x1, x2, y1, y2, gate, totKey, key;
    memset(Gate, -, sizeof(Gate));
    memset(Dist, INF, sizeof(Dist));
    scanf("%d%d%d%d", &TotX, &TotY, &totKeySort, &totObs);
    while (totObs--)
    {
        scanf("%d%d%d%d%d", &x1, &y1, &x2, &y2, &gate);
        Gate[x1][y1][x2][y2] = Gate[x2][y2][x1][y1] = gate;
    }
    scanf("%d", &totKey);
    while (totKey--)
    {
        scanf("%d%d%d", &x1, &y1, &key);
        if (key >= )
            printf("error\n");
        Key[x1][y1] |=  << key;
    }
    int ans = Bfs();
    if (ans == INF)
        printf("-1\n");
    else
        printf("%d\n", ans);
    return ;
}