PAT (Advanced Level) 1041. Be Unique (20)
简单题。
#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#include<map>
#include<queue>
#include<stack>
#include<string>
#include<algorithm>
using namespace std; int n;
int a[+];
int f[+]; int main()
{
memset(f,,sizeof f);
scanf("%d",&n);
for(int i=;i<=n;i++) scanf("%d",&a[i]);
for(int i=;i<=n;i++) f[a[i]]++;
int fail=;
for(int i=;i<=n;i++)
{
if(f[a[i]]==)
{
fail=;
printf("%d\n",a[i]);
break;
}
}
if(fail==) printf("None\n");
return ;
}
PAT (Advanced Level) 1041. Be Unique (20)的更多相关文章
- PAT (Advanced Level) Practice 1035 Password (20 分) 凌宸1642
PAT (Advanced Level) Practice 1035 Password (20 分) 凌宸1642 题目描述: To prepare for PAT, the judge someti ...
- PAT (Advanced Level) Practice 1008 Elevator (20 分) 凌宸1642
PAT (Advanced Level) Practice 1008 Elevator (20 分) 凌宸1642 题目描述: The highest building in our city has ...
- PTA(Advanced Level)1041.Be Unique
Being unique is so important to people on Mars that even their lottery is designed in a unique way. ...
- PAT (Advanced Level) Practice 1035 Password (20 分)
To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem ...
- 【PAT Advanced Level】1008. Elevator (20)
没什么难的,简单模拟题 #include <iostream> using namespace std; int main() { int num; cin>>num; int ...
- PAT (Advanced Level) 1112. Stucked Keyboard (20)
找出一定没问题的字符(即一连串的额字符x个数能被k整除的),剩下的字符都是可能有问题的. #include<cstdio> #include<cstring> #include ...
- PAT (Advanced Level) 1108. Finding Average (20)
简单模拟. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #i ...
- PAT (Advanced Level) 1100. Mars Numbers (20)
简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #in ...
- PAT (Advanced Level) 1096. Consecutive Factors (20)
如果是素数直接输出1与素数,否则枚举长度和起始数即可. #include<cstdio> #include<cstring> #include<cmath> #in ...
随机推荐
- Chapter 2 Open Book——9
When I was finished with that, I took my book bag upstairs. Before starting my homework, I changed i ...
- Chapter 1 First Sight——36
The door opened again, and the cold wind suddenly gusted through the room, rustling the papers on th ...
- Infix expressions 中缀表达式
中缀表达式的计算 利用两个栈来实现,操作数栈,操作符栈 只支持个位数运算 最后必须输入一个'#' #include<iostream> using namespace std; templ ...
- nefu 449 超级楼梯 &&nefu 911 跨楼梯
nefu 449 超级楼梯 Description 有一楼梯共M级,刚开始时你在第一级,若每次只能跨上一级或二级,要走上第M级,共有多少种走法? Input 输入数据首先包含一个整数N,表示测试实例的 ...
- HDU1062:Text Reverse
Problem Description Ignatius likes to write words in reverse way. Given a single line of text which ...
- Linux raid信息 查看
Linux下查看软.硬raid信息的方法. 软件raid:只能通过Linux系统本身来查看 cat /proc/mdstat 可以看到raid级别,状态等信息. 硬件raid: 最佳的办法是通过已安装 ...
- C#输出日历
用C#输出日历,此功能可用于Ajax方式列出计划日程相关的内容,由于是C#控制输出,可以方便加上自己需要的业务处理逻辑. 1.控制台输出: using System; namespace 控制台日历 ...
- Qt Quick里的图形效果:阴影(Drop Shadow)
Qt Quick提供了两种阴影效果: DropShow,阴影.这个元素会根据源图像,产生一个彩色的.模糊的新图像,把这个新图像放在源图像后面,给人一种源图像从背景上凸出来的效果. InnerShado ...
- 笨方法学python--字符串和文本
1print 变量 abc = False joke_string = "Isn't that joke so funny?! %r" print joke_string %abc ...
- 转: Windows下安装Oracle Database 12c Release 1(12.1.0.2.0) - Enterprise Edition
http://www.cnblogs.com/xqzt/p/4395053.html Windows下安装Oracle Database 12c Release 1(12.1.0.2.0) - Ent ...