#include<stdio.h>
#include<string.h>
#include<math.h>
int main()
{
_int64 n,a;
while(scanf("%I64d",&n)!=EOF)
{
_int64 b=,c;
while(n--)
{
scanf("%I64d",&a);
if(b==)
{
c=a;
b++;
}
else
{
if(c==a)
b++;
else
b--;
}
}
printf("%I64d\n",c);
}
return ;
}
Problem Description
"OK, you are not too bad, em... But you can never pass the next test." feng5166 says.
"I will tell you an odd number N, and then N integers. There will be a special integer among them, you have to tell me which integer is the special one after I tell you all the integers." feng5166 says.
"But what is the characteristic of the special integer?" Ignatius asks.
"The integer will appear at least (N+1)/2 times. If you can't find the right integer, I will kill the Princess, and you will be my dinner, too. Hahahaha....." feng5166 says.
Can you find the special integer for Ignatius?
 
Input
The input contains several test cases. Each test case contains two lines. The first line consists of an odd integer N(1<=N<=999999) which indicate the number of the integers feng5166 will tell our hero. The second line contains the N integers. The input is terminated by the end of file.
 
Output
For each test case, you have to output only one line which contains the special number you have found.
 
Sample Input
5
1 3 2 3 3
11
1 1 1 1 1 5 5 5 5 5 5
7
1 1 1 1 1 1 1
 
Sample Output
3
5
1
 

动态规划:Ignatius and the Princess IV的更多相关文章

  1. HDU 1029 Ignatius and the Princess IV (动态规划、思维)

    Ignatius and the Princess IV Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32767 K ( ...

  2. hdu 1029 Ignatius ans the Princess IV

    Ignatius and the Princess IV Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32767 K ( ...

  3. HDU 1029 Ignatius and the Princess IV --- 水题

    HDU 1029 题目大意:给定数字n(n <= 999999 且n为奇数 )以及n个数,找出至少出现(n+1)/2次的数 解题思路:n个数遍历过去,可以用一个map(也可以用数组)记录每个数出 ...

  4. Ignatius and the Princess IV

    Ignatius and the Princess IV Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32767 K ( ...

  5. Ignatius and the Princess IV(乱搞一发竟然过了)

    B - Ignatius and the Princess IV Time Limit:1000MS     Memory Limit:32767KB     64bit IO Format:%I64 ...

  6. HDU 1029 Ignatius and the Princess IV / HYSBZ(BZOJ) 2456 mode(思维题,~~排序?~~)

    HDU 1029 Ignatius and the Princess IV (思维题,排序?) Description "OK, you are not too bad, em... But ...

  7. (Arrays.sort() 或 map) Ignatius and the Princess IV hdu1029

    Ignatius and the Princess IV 链接:http://acm.hdu.edu.cn/showproblem.php?pid=1029 借鉴链接:https://blog.csd ...

  8. HDU 1029 Ignatius and the Princess IV (map的使用)

    传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1029 Ignatius and the Princess IV Time Limit: 2000/10 ...

  9. HDOJ.1029 Ignatius and the Princess IV(map)

    Ignatius and the Princess IV 点我跳转到题面 点我一起学习STL-MAP 题意分析 给出一个奇数n,下面有n个数,找出下面数字中出现次数大于(n+1)/2的数字,并输出. ...

  10. kuangbin专题十二 HDU1029 Ignatius and the Princess IV (水题)

    Ignatius and the Princess IV Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32767 K ( ...

随机推荐

  1. 应用-如何使不同的企业使用独自的数据源。使用ejb3.0+jboss6.2EAP+JPA

    摘要:                如何使不同的企业使用独自的数据源.使用ejb3.0+jboss6.2EAP+JPA10C应用系统被多个企业同时使用,为了提供个性化服务,如何使不同的企业使用独自的 ...

  2. xcode uml 工具

    https://github.com/PaulTaykalo/objc-dependency-visualizer ./generate-objc-dependencies-to-json.rb -d ...

  3. Qt 为QPushButton、QLabel添加鼠标移入移出事件

    QT 为QPushButton.QLabel添加鼠标移入移出事件**要实现的效果:**鼠标移入QPushButton时与移出时按钮变换字体颜色,鼠标移入QLabel时显示上面的文字,移出时不显示.** ...

  4. JS:输出9*9乘法表

    <html> <head> <title>9*9 multiplication table</title> </head> <body ...

  5. 字符串翻转(java)

    1 递归,二分 private static String reverse(String s) { int N = s.length(); if(N <= 1) return s; String ...

  6. 批量下载ts视频文件

    第一步 使用chrome 按F12进入开发模式,拖动视频进度条到视频结束: 然后找到.m3u8以结尾的文件并保存为文本文件. 第二步 点开查看里面是否存在如下以ts结尾的文件内容 ...... /20 ...

  7. postman使用--接口的关联

    前戏 在实际接口测试过程中,接口经常会有关联,比如需要取上一个接口的返回值,然后作为参数传递给下一个接口作为参数,假设我们要获取A接口返回的userid值作为B接口的请求参数 先设置环境,所有接口在一 ...

  8. 第一个WebDriver脚本

    1.cmd下安装selenium,输入pip install selenium 2.下载Firefox浏览器的驱动程序,https://github.com/mozilla/geckodriver/r ...

  9. java对比IO和NIO的文件读写性能测试

    1. NIO采用更接近操作系统执行IO的方式:通道和缓存器:顾名思义,数据源的数据由缓存器通过通道进行传输. 2. 在JDK5之后,原始IO系统底层用NIO进行了优化,这可以通过sun公布的源码中找到 ...

  10. Http请求封装(对HttpClient类的进一步封装,使之调用更方便。另外,此类管理唯一的HttpClient对象,支持线程池调用,效率更高)

    package com.ad.ssp.engine.common; import java.io.IOException; import java.util.ArrayList; import jav ...