ASP.NET Core 1.0中实现文件上传的两种方式(提交表单和采用AJAX)
Bipin Joshi (http://www.binaryintellect.net/articles/f1cee257-378a-42c1-9f2f-075a3aed1d98.aspx)
Uploading files is a common requirement in web applications. In ASP.NET Core 1.0 uploading files and saving them on the server is quite easy. To that end this article shows how to do just that.Begin by creating a new ASP.NET Core project. Then add HomeController to the controllers folder. Then add UploadFiles view to Views > Home folder of the application.
HTML form for uploading files
Open the UploadFiles view and add the following HTML markup in it:
1: <form asp-action="UploadFiles"
2: asp-controller="Home"
3: method="post"
4: enctype="multipart/form-data">
5: <input type="file" name="files" multiple />
6: <input type="submit" value="Upload Selected Files" />
7: </form>
The above markup uses form tag helper of ASP.NET Core MVC. The asp-action attribute indicates that the form will be processed by the UploadFiles action upon submission. The asp-controller attribute specifies the name of the controller containing the action method. The form is submitted using POST method. The enctype attribute of the form is set to multipart/form-data indicating that it will be used for file upload operation.
The form contains an input field of type file. The name attribute of the file input field is set to files and the presence of multiple attribute indicates that multiple files can be uploaded at once. The submit button submits the form to the server.
If you run the application at this stage, the UploadFiles view should look like this:
aaarticlea/png;base64,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" alt="" />
Constructor and UploadFiles() GET action
Now, open the HomeController and add a constructor to it as shown below:
1: public class HomeController : Controller
2: {
3: private IHostingEnvironment hostingEnv;
4: public HomeController(IHostingEnvironment env)
5: {
6: this.hostingEnv = env;
7: }
8: }
The constructor has a parameter of type IHostingEnvironment (Microsoft.AspNet.Hosting namespace). This parameter will be injected by MVC framework into the constructor. You need this parameter to construct the full path for saving the uploaded files. The IHostingEnvironment object is saved into a local variable for later use.
Then add UploadFiles() action for GET requests as shown below:
1: public IActionResult UploadFiles()
2: {
3: return View();
4: }
UploadFiles() POST action
Finally, add UploadFiles() action for handling the POST requests.
1: [HttpPost]
2: public IActionResult UploadFiles(IList<IFormFile> files)
3: {
4: long size = 0;
5: foreach(var file in files)
6: {
7: var filename = ContentDispositionHeaderValue
8: .Parse(file.ContentDisposition)
9: .FileName
10: .Trim('"');
11: filename = hostingEnv.WebRootPath + $@"\{fileName}";
12: size += file.Length;
13: using (FileStream fs = System.IO.File.Create(filename))
14: {
15: file.CopyTo(fs);
16: fs.Flush();
17: }
18: }
19:
20: ViewBag.Message = $"{files.Count} file(s) /
21: {size} bytes uploaded successfully!";
22: return View();
23: }
The UploadFiles() action has a parameter - IList<IFormFile> - to receive the uploaded files. The IFormFile object represents a single uploaded file. Inside, a size variable keeps track of how much data is being uploaded. Then a foreach loop iterates through the files collection.
The client side file name of an uploaded file is extracted using the ContentDispositionHeaderValue class (Microsoft.Net.Http.Headers namespace) and the ContentDisposition property of the IFormFile object. Let's assume that you wish to save the uploaded files into the wwwroot folder. So, to arrive at the full path you use the WebRootPath property of IHostingEnvironment and append the filename to it.
Finally, the file is saved by the code inside the using block. That code basically creates a new FileStream and copies the uploaded file into it. This is done using the Create() and the CopyTo() methods. A message is stored in ViewBag to be displayed to the end user.
The following figure shows a sample successful run of the application:
aaarticlea/png;base64,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" alt="" />
Using jQuery Ajax to upload the files
In the preceding example you used form POST to submit the files to the server. What if you wish to send files through Ajax? You can accomplish the task with a little bit of change to the <form> and the action.
Modify the <form> to have a plain push button instead of submit button as shown below:
1: <form method="post" enctype="multipart/form-data">
2: <input type="file" id="files"
3: name="files" multiple />
4: <input type="button"
5: id="upload"
6: value="Upload Selected Files" />
7: </form>
Then add a <script> reference to the jQuery library and write the following code to handle the click event of the upload button:
1: $(document).ready(function () {
2: $("#upload").click(function (evt) {
3: var fileUpload = $("#files").get(0);
4: var files = fileUpload.files;
5: var data = new FormData();
6: for (var i = 0; i < files.length ; i++) {
7: data.append(files[i].name, files[i]);
8: }
9: $.ajax({
10: type: "POST",
11: url: "/home/UploadFilesAjax",
12: contentType: false,
13: processData: false,
14: data: data,
15: success: function (message) {
16: alert(message);
17: },
18: error: function () {
19: alert("There was error uploading files!");
20: }
21: });
22: });
23: });
The above code grabs each file from the file field and adds it to a FormData object (HTML5 feature). Then $.ajax() method POSTs the FormData object to the UploadFilesAjax() action of the HomeController. Notice that the contentType and processData properties are set to false since the FormData contains multipart/form-data content. The data property holds the FormData object.
Finally, add UploadFilesAjax() action as follows:
1: [HttpPost]
2: public IActionResult UploadFilesAjax()
3: {
4: long size = 0;
5: var files = Request.Form.Files;
6: foreach (var file in files)
7: {
8: var filename = ContentDispositionHeaderValue
9: .Parse(file.ContentDisposition)
10: .FileName
11: .Trim('"');
12: filename = hostingEnv.WebRootPath + $@"\{filename}";
13: size += file.Length;
14: using (FileStream fs = System.IO.File.Create(filename))
15: {
16: file.CopyTo(fs);
17: fs.Flush();
18: }
19: }
20: string message = $"{files.Count} file(s) /
21: {size} bytes uploaded successfully!";
22: return Json(message);
23: }
The code inside UploadFilesAjax() is quite similar to UploadFiles() you wrote earlier. The main difference is how the files are received. The UploadFilesAjax() doesn't have IList<IFormFile> parameter. Instead it receives the files through the Request.Form.Files property. Secondly, the UploadFilesAjax() action returns a JSON string message to the caller for the sake of displaying in the browser.
That's it for now! Keep coding!!
ASP.NET Core 1.0中实现文件上传的两种方式(提交表单和采用AJAX)的更多相关文章
- curl文件上传有两种方式,一种是post_fileds,一种是infile
curl文件上传有两种方式,一种是POSTFIELDS,一种是INFILE,POSTFIELDS传递@实际地址,INFILE传递文件流句柄! );curl_setopt($ch, CURLOPT_PO ...
- 用VSCode开发一个asp.net core2.0+angular5项目(5): Angular5+asp.net core 2.0 web api文件上传
第一部分: http://www.cnblogs.com/cgzl/p/8478993.html 第二部分: http://www.cnblogs.com/cgzl/p/8481825.html 第三 ...
- Asp.Net Core 2.0 WebUploader FastDfs 文件上传 分段上传
功能点: 1. 使用.net core 2.0 实现文件上传 2. 使用webuploader实现单文件,多文件上传 3. 使用webuploader实现大文件的分段上传. 4. 使用webuploa ...
- 利用Selenium实现图片文件上传的两种方式介绍
在实现UI自动化测试过程中,有一类需求是实现图片上传,这种需求根据开发的实现方式,UI的实现方式也会不同. 一.直接利用Selenium实现 这种方式是最简单的一种实现方式,但是依赖于开发的实现. 当 ...
- ASP.NET Core WEB API 使用element-ui文件上传组件el-upload执行手动文件文件,并在文件上传后清空文件
前言: 从开始学习Vue到使用element-ui-admin已经有将近快两年的时间了,在之前的开发中使用element-ui上传组件el-upload都是直接使用文件选取后立即选择上传,今天刚好做了 ...
- java模拟表单上传文件,java通过模拟post方式提交表单实现图片上传功能实例
java模拟表单上传文件,java通过模拟post方式提交表单实现图片上传功能实例HttpClient 测试类,提供get post方法实例 package com.zdz.httpclient; i ...
- Java文件上传的几种方式
文件上传与文件上传一样重要.在Java中,要实现文件上传,可以有两种方式: 1.通过Servlet类上传 2.通过Struts框架实现上传 这两种方式的根本还是通过Servlet进行IO流的操作. 一 ...
- web 文件上传的几种方式
问题 文件上传在WEB开发中应用很广泛. 文件上传是指将本地图片.视频.音频等文件上传到服务器上,可以供其他用户浏览或下载的过程. 以下总结了常见的文件(图片)上传的方式和要点处理. 表单上传 这是传 ...
- 基础教程:上传/下载ASP.NET Core 2.0中的文件
问题 如何上传和下载ASP.NET Core MVC中的文件. 解 在一个空的项目中,更新 Startup 类以添加MVC的服务和中间件. publicvoid ConfigureServices( ...
随机推荐
- iOS代码规范(OC和Swift)
下面说下iOS的代码规范问题,如果大家觉得还不错,可以直接用到项目中,有不同意见 可以在下面讨论下. 相信很多人工作中最烦的就是代码不规范,命名不规范,曾经见过一个VC里有3个按钮被命名为button ...
- 如何一步一步用DDD设计一个电商网站(六)—— 给购物车加点料,集成售价上下文
阅读目录 前言 如何在一个项目中实现多个上下文的业务 售价上下文与购买上下文的集成 结语 一.前言 前几篇已经实现了一个最简单的购买过程,这次开始往这个过程中增加一些东西.比如促销.会员价等,在我们的 ...
- MVVM模式解析和在WPF中的实现(三)命令绑定
MVVM模式解析和在WPF中的实现(三) 命令绑定 系列目录: MVVM模式解析和在WPF中的实现(一)MVVM模式简介 MVVM模式解析和在WPF中的实现(二)数据绑定 MVVM模式解析和在WPF中 ...
- XStream将java对象转换为xml时,对象字段中的下划线“_”,转换后变成了两个的解决办法
在前几天的一个项目中,由于数据库字段的命名原因 其中有两项:一项叫做"市场价格"一项叫做"商店价格" 为了便于区分,遂分别将其命名为market ...
- 如何在nuget上传自己的包+搭建自己公司的NuGet服务器(新方法)
运维相关:http://www.cnblogs.com/dunitian/p/4822808.html#iis 先注册一个nuget账号https://www.nuget.org/ 下载并安装一下Nu ...
- 转:聊聊mavenCenter和JCenter
Gradle支持从maven中央仓库和JCenter上获取构件,那这两者有什么区别呢? maven中央仓库(http://repo1.maven.org/maven2/)是由Sonatype公司提供的 ...
- Syscall,API,ABI
系统调用(Syscall):Linux2.6之前是使用int0x80(中断)来实现系统调用的,在2.6之后的内核是使用sysentry/sysexit(32位机器)指令来实现的系统调用,这两条指令是C ...
- SQL SERVER导入数据到ORACLE的方法总结
我们偶尔会有将数据从SQL SERVER导入到ORACLE当中的这种需求,那么这种跨数据库导数有那些方法呢?这些方法又有那些利弊呢? 下面比较肤浅的总结了一些可行的方法. 1:生成SQL脚本然后去OR ...
- VS2010 release编译下进行调试,“当前不会命中任何断点,还没有为文档加载”问题解决方案
在release模式下调试程序,经常出现"当前不会命中任何断点,还没有为文档加载"的问题,可尝试以下方法: 1. 属性 → 配置属性 → C/C++ → 常规 → 调试信息格式:选 ...
- 在Ubuntu中搭建.NET开发环境
Mono简介Mono是Xamarin公司C#和CLR的ECMA标准基于开发的一个开源的.NET实现版本,它是Linux平台上开发.NET应用程序首选.同时其也提供了Xamarin.IOS和Xamari ...