Codeforces Gym - 101102B - The Little Match Girl
1 second
256 megabytes
standard input
standard output
Using at most 7 matchsticks, you can draw any of the 10 digits as in the following picture:
The picture shows how many sticks you need to draw each of the digits.
Zaytoonah has a number that consists of N digits. She wants to move some sticks (zero or more) to maximize the number. Note that she doesn’t want to remove any of the sticks, she will only move them from one place to another within the N digits. She also doesn’t want to add new digits as N is her lucky number.
Can you help Zaytoonah maximize her number?
The first line of input contains a single integer T, the number of test cases.
Each test case contains a single integer N (1 ≤ N ≤ 105), followed by a space, then N digits that represent the number Zaytoonah currently has.
For each test case, print on a single line the maximum number Zaytoonah can get.
3
1 3
3 512
3 079
5
977
997
题意:略。
方法:贪心,先求出总的火柴数,再从最大数字开始贪,最后一个单独输出。
代码:
#include<cstdio>
#include<iostream>
#include<algorithm>
using namespace std;
const int N=1e5+;
int a[]={
,,,,,,,,,
};
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
int n;
char s[N];
int sum=;
scanf("%d %s",&n,s);
for(int i=;i<n;i++)
{
sum+=a[s[i]-''];
}
for(int i=;i<n;i++)
{
for(int j=;j>=;j--)
{
int temp=sum-a[j];
if(temp>=*(n-i)&&temp<=*(n-i))
{
cout<<j;
sum-=a[j];
break;
}
}
}
for(int i=;i>=;i--)
{
if(sum==a[i])
{
cout<<i<<endl;
break;
}
}
}
return ;
}
Codeforces Gym - 101102B - The Little Match Girl的更多相关文章
- Gym 101102B The Little Match Girl(贪心+规律)
这个题目的做法不止一种,solve1:每个数字使用的火柴棒都在2~7之间,而且是连续的,就是2-7之前没有空着的数.这样就有一个结论,在下界为l,上界为r的情况下,假设有n个数,那么火柴棒总数一定在n ...
- Codeforces Gym 101252D&&floyd判圈算法学习笔记
一句话题意:x0=1,xi+1=(Axi+xi%B)%C,如果x序列中存在最早的两个相同的元素,输出第二次出现的位置,若在2e7内无解则输出-1. 题解:都不到100天就AFO了才来学这floyd判圈 ...
- Codeforces Gym 101190M Mole Tunnels - 费用流
题目传送门 传送门 题目大意 $m$只鼹鼠有$n$个巢穴,$n - 1$条长度为$1$的通道将它们连通且第$i(i > 1)$个巢穴与第$\left\lfloor \frac{i}{2}\rig ...
- Codeforces Gym 101623A - 动态规划
题目传送门 传送门 题目大意 给定一个长度为$n$的序列,要求划分成最少的段数,然后将这些段排序使得新序列单调不减. 考虑将相邻的相等的数缩成一个数. 假设没有分成了$n$段,考虑最少能够减少多少划分 ...
- 【Codeforces Gym 100725K】Key Insertion
Codeforces Gym 100725K 题意:给定一个初始全0的序列,然后给\(n\)个查询,每一次调用\(Insert(L_i,i)\),其中\(Insert(L,K)\)表示在第L位插入K, ...
- Codeforces gym 101343 J.Husam and the Broken Present 2【状压dp】
2017 JUST Programming Contest 2.0 题目链接:Codeforces gym 101343 J.Husam and the Broken Present 2 J. Hu ...
- codeforces gym 100553I
codeforces gym 100553I solution 令a[i]表示位置i的船的编号 研究可以发现,应是从中间开始,往两边跳.... 于是就是一个点往两边的最长下降子序列之和减一 魔改树状数 ...
- CodeForces Gym 100213F Counterfeit Money
CodeForces Gym题目页面传送门 有\(1\)个\(n1\times m1\)的字符矩阵\(a\)和\(1\)个\(n2\times m2\)的字符矩阵\(b\),求\(a,b\)的最大公共 ...
- Codeforces GYM 100876 J - Buying roads 题解
Codeforces GYM 100876 J - Buying roads 题解 才不是因为有了图床来测试一下呢,哼( 题意 给你\(N\)个点,\(M\)条带权边的无向图,选出\(K\)条边,使得 ...
随机推荐
- Mysql安装错误:Install/Remove of the Service Denied!解决办法
Mysql安装错误:Install/Remove of the Service Denied!解决办法 在windos 的cmd下安装mysql 在mysql的bin目录下面执行: mysqld -- ...
- 20145325张梓靖 《网络对抗技术》 PC平台逆向破解
20145325张梓靖 <网络对抗技术> PC平台逆向破解 学习任务 shellcode注入:shellcode实际是一段代码,但却作为数据发送给受攻击服务器,将代码存储到对方的堆栈中,并 ...
- Codeforces Round #424 (Div. 2, rated, based on VK Cup Finals) Problem F (Codeforces 831F) - 数论 - 暴力
题目传送门 传送门I 传送门II 传送门III 题目大意 求一个满足$d\sum_{i = 1}^{n} \left \lceil \frac{a_i}{d} \right \rceil - \sum ...
- 牛客网数据库SQL实战(21-25)
21.查找所有员工自入职以来的薪水涨幅情况,给出员工编号emp_no以及其对应的薪水涨幅growth,并按照growth进行升序CREATE TABLE `employees` (`emp_no` i ...
- Shell脚本,更改Info.plist中的日期等
#!/bin/bashroot_src=$(dirname $(PWD)) bundle_name='RandomDebbot.bundle' target_path=$root_src/ecovac ...
- Jenkins 总结
步骤: 1,安装Jenkins 2,运行Jenkins: java -jar jenkins.war --httpPort=8888 httpPort指的就是Jenkins所使用的http端口,这里指 ...
- Bootstrap3基础 img-rounded 图片的四个角改成圆角
内容 参数 OS Windows 10 x64 browser Firefox 65.0.2 framework Bootstrap 3.3.7 editor ...
- RPMB分区介绍【转】
本文转载自:https://blog.csdn.net/xiezhi123456/article/details/81479793 RPMB(Replay Protected Memory Block ...
- 【无法使用yum安装软件】使用yum命令安装软件提示No package numactl.x86_64 available.
在安装mysql时需要安装numactl.x86_64 使用yum -y install numactl.x86_64时报错 [root@sdp6 mysql]# yum -y install num ...
- 浅谈循环中setTimeout执行顺序问题
浅谈循环中setTimeout执行顺序问题 (下面有见解一二) 期望:开始输出一个0,然后每隔一秒依次输出1,2,3,4. for (var i = 0; i < 5; i++) { setTi ...