浅谈Objeact.clone克隆(纯个人理解,如有错误请指正)
现在先来看一下jdk给出的Object.clone源码和注释
/**
* Creates and returns a copy of this object. The precise meaning
* of "copy" may depend on the class of the object. The general
* intent is that, for any object {@code x}, the expression:
* <blockquote>
* <pre>
* x.clone() != x</pre></blockquote>
* will be true, and that the expression:
* <blockquote>
* <pre>
* x.clone().getClass() == x.getClass()</pre></blockquote>
* will be {@code true}, but these are not absolute requirements.
* While it is typically the case that:
* <blockquote>
* <pre>
* x.clone().equals(x)</pre></blockquote>
* will be {@code true}, this is not an absolute requirement.
* <p>
* By convention, the returned object should be obtained by calling
* {@code super.clone}. If a class and all of its superclasses (except
* {@code Object}) obey this convention, it will be the case that
* {@code x.clone().getClass() == x.getClass()}.
* <p>
* By convention, the object returned by this method should be independent
* of this object (which is being cloned). To achieve this independence,
* it may be necessary to modify one or more fields of the object returned
* by {@code super.clone} before returning it. Typically, this means
* copying any mutable objects that comprise the internal "deep structure"
* of the object being cloned and replacing the references to these
* objects with references to the copies. If a class contains only
* primitive fields or references to immutable objects, then it is usually
* the case that no fields in the object returned by {@code super.clone}
* need to be modified.
* <p>
* The method {@code clone} for class {@code Object} performs a
* specific cloning operation. First, if the class of this object does
* not implement the interface {@code Cloneable}, then a
* {@code CloneNotSupportedException} is thrown. Note that all arrays
* are considered to implement the interface {@code Cloneable} and that
* the return type of the {@code clone} method of an array type {@code T[]}
* is {@code T[]} where T is any reference or primitive type.
* Otherwise, this method creates a new instance of the class of this
* object and initializes all its fields with exactly the contents of
* the corresponding fields of this object, as if by assignment; the
* contents of the fields are not themselves cloned. Thus, this method
* performs a "shallow copy" of this object, not a "deep copy" operation.
* <p>
* The class {@code Object} does not itself implement the interface
* {@code Cloneable}, so calling the {@code clone} method on an object
* whose class is {@code Object} will result in throwing an
* exception at run time.
*
* @return a clone of this instance.
* @throws CloneNotSupportedException if the object's class does not
* support the {@code Cloneable} interface. Subclasses
* that override the {@code clone} method can also
* throw this exception to indicate that an instance cannot
* be cloned.
* @see java.lang.Cloneable
*/
protected native Object clone() throws CloneNotSupportedException;
克隆对象需要继承Cloneable接口并重写Object.clone()方法,看一下bean的代码
public class TestBean implements Cloneable{
private Long id;
private String code;
private String msg;
private TestCloneBean testCloneBean = new TestCloneBean();
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getCode() {
return code;
}
public void setCode(String code) {
this.code = code;
}
public String getMsg() {
return msg;
}
public void setMsg(String msg) {
this.msg = msg;
}
public TestCloneBean getTestCloneBean() {
return testCloneBean;
}
public void setTestCloneBean(TestCloneBean testCloneBean) {
this.testCloneBean = testCloneBean;
}
@Override
protected TestBean clone() throws CloneNotSupportedException {
return (TestBean)super.clone();
}
}
克隆一个全新的对象,接下来看一下原本对象和新的克隆对象有什么区别
public static void main(String[] args) {
try {
TestBean bean = new TestBean();
TestBean copyBean = bean.clone();
System.out.println("==判断:" + (bean == copyBean));
System.out.println("class判断:" + (bean.getClass() == copyBean.getClass()));
System.out.println("hasCode判断:" + (bean.hashCode() == copyBean.hashCode()));
System.out.println("equals判断:" + (bean.equals(copyBean)));
} catch (CloneNotSupportedException e) {
e.printStackTrace();
}
}
看一下结果

除了.getClass()相等,其余皆是不一样的,是一个全新的对象。
-----------------------------------------------------------分割线-----------------------------------------------------------
那克隆对象里面包含对象呢?我们来看一下
public class Test {
public static void main(String[] args) {
try {
TestBean bean = new TestBean();
TestCloneBean testCloneBean = new TestCloneBean(1L,"1","测试");
bean.setTestCloneBean(testCloneBean);
TestBean copyBean = (TestBean) bean.clone();
System.out.println("==判断:" + (bean.getTestCloneBean() == copyBean.getTestCloneBean()));
System.out.println("class判断:" + (bean.getTestCloneBean().getClass() == copyBean.getTestCloneBean().getClass()));
System.out.println("hasCode判断:" + (bean.getTestCloneBean().hashCode() == copyBean.getTestCloneBean().hashCode()));
System.out.println("equals判断:" + (bean.getTestCloneBean().equals(copyBean.getTestCloneBean())));
System.out.println("bean:{"+bean.getTestCloneBean().toString()+"}");
System.out.println("bean:{"+copyBean.getTestCloneBean().toString()+"}");
} catch (CloneNotSupportedException e) {
e.printStackTrace();
}
}
}
#1 属性testCloneBean未重写clone方法,结果是

#2 当对象属性也重写了clone方法后
@Override
public TestCloneBean clone() throws CloneNotSupportedException {
return (TestCloneBean) super.clone();
}
结果是

很诧异,还是原来的地址,说明对象属性是没有被克隆的,那是不是对象没有序列化呢?等我加上序列化试一下
额~事实证明,序列化还是一样的,被克隆的对象属性是一样的!
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