Path Sum II

Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.

For example:
Given the below binary tree and sum = 22,

              5
/ \
4 8
/ / \
11 13 4
/ \ / \
7 2 5 1

return

[
[5,4,11,2],
[5,8,4,5]
] 这个问题需要返回每条满足sum值的所有路径。思路是:后序遍历,回溯时将当前node.val添加到左右子树的结果中。 递归:
List<List<Int>> path_sum_helper(Treenode node, int current_sum, int depth, int sum_aim):
  if (node is leaf-node):
    r = [[]]
    if (current_sum == sum_aim):
      r_i = []
      r_i[depth] = node.val
      r.add(r_i)
    return r
  else:
    r = [[]]
    if(node.left != null):
      left_ = path_sum_helper(node.left, current_sum + node.left.val, depth + 1, sum_aim)
      if (left_ != null):
        r = left_;
        for(r_ : r):
          r_[level] = node.val
      // similar for right sub-tree
      // need to merge left and right results
    return r
      


[leetcode]Path Sum II的更多相关文章

  1. LeetCode: Path Sum II 解题报告

    Path Sum II Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals ...

  2. [LeetCode] Path Sum II 二叉树路径之和之二

    Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given su ...

  3. [Leetcode] Path Sum II路径和

    Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given su ...

  4. [leetcode]Path Sum II @ Python

    原题地址:https://oj.leetcode.com/problems/path-sum-ii/ 题意: Given a binary tree and a sum, find all root- ...

  5. leetcode: Path Sum II 迭代法

    Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given su ...

  6. LeetCode——Path Sum II

    Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given su ...

  7. [LeetCode] Path Sum II 深度搜索

    Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given su ...

  8. LeetCode Path Sum II (DFS)

    题意: 给一棵二叉树,每个叶子到根的路径之和为sum的,将所有可能的路径装进vector返回. 思路: 节点的值可能为负的.这样子就必须到了叶节点才能判断,而不能中途进行剪枝. /** * Defin ...

  9. LeetCode:Path Sum I II

    LeetCode:Path Sum Given a binary tree and a sum, determine if the tree has a root-to-leaf path such ...

随机推荐

  1. Android 2016新技术

    Android 2016新技术 版权声明:本文为博主原创文章,未经博主允许不得转载. 2016你需要了解Android有以下新兴的技术与框架,有些也许还不成熟,但是你应该去了解下,也许就是未来的方向. ...

  2. cocos2d-x 常用UI

    CCSprite* sprite = CCSprite::create("CloseNormal.png"); sprite->setPosition(ccp(50, 50) ...

  3. 国内app快速生成平台对比

     泰格老虎 2013-03-07 00:39:10 这是海恒CEO高鹏写的一篇国内app快速生成平台对比文章,介绍了国内快速生成APP的平台与自己平台的对比,很有参考价值. 同类网站 安米网 http ...

  4. 微软How old do I Look——初体验

    前段时间微软发布了一个可爱的网站how old.net,着实火了一把,全民体验魔镜魅力. 上传自己的靓照到http://www.how-old.net/,它就可以告诉你性别和年龄,大家还习惯称之为“颜 ...

  5. C#单链表

    顺序表是用地址连续的存储单元顺序存储线性表中的各个数据元素, 逻辑上相邻的数据元素在物理位置上也相邻.因此,在顺序表中查找任何一个位置上的数据元素非常方便, 这是顺序存储的优点. 但是, 在对顺序表进 ...

  6. C++/java之间的Socket通信大小端注意事项

    在一个物联往项目中,需要java云平台与一个客户端做socket定制协议的通信:然而在第一次测试时,并没有按照预想的那样完成解析.查找资料以后是因为客户端的数据读取方式为小端模式,而java默认采用大 ...

  7. python-selenium之firefox、Chrome、Ie运行

    测试脚本是否支持在不同浏览器运行firefox浏览器运行脚本 from selenium import webdriver driver=webdriver.Firefox() driver.get( ...

  8. How to:如何让Installshield显示正确的软件所需空间--网友冰块先生贡献

    软件环境: installshield2010  工程类型:installshield project  现象:当转换目录后所需空间显示不正常. 解决办法:在转换目录地方加上一个TARGETDIR重新 ...

  9. RealProxy实现AOP编程(2)

    稍微变化一下!注意区别. Program.cs class Program { static void Main(string[] args) { User user = " }; var ...

  10. dede currentstyle属性完美解决方案

    问题一.dede让channelartlist标签支持currentstyle属性 完美解决 打开include\taglib\channelartlist.lib.php找到$pv->Fiel ...