767A Snacktower
2 seconds
256 megabytes
standard input
standard output
According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time n snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should be at the bottom of the tower, while small snacks should be at the top.
Years passed, and once different snacks started to fall onto the city, and the residents began to build the Snacktower.

However, they faced some troubles. Each day exactly one snack fell onto the city, but their order was strange. So, at some days the residents weren't able to put the new stack on the top of the Snacktower: they had to wait until all the bigger snacks fell. Of course, in order to not to anger miss Fortune again, the residents placed each snack on the top of the tower immediately as they could do it.
Write a program that models the behavior of Ankh-Morpork residents.
The first line contains single integer n (1 ≤ n ≤ 100 000) — the total number of snacks.
The second line contains n integers, the i-th of them equals the size of the snack which fell on the i-th day. Sizes are distinct integers from 1 to n.
Print n lines. On the i-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the i-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty.
3
3 1 2
3
2 1
5
4 5 1 2 3
5 4
3 2 1
In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right after that they placed the snack of size 1 which had fallen before.
#include <string.h>
#include <stdio.h>
#include <iostream>
using namespace std;
#define maxn 1000005
int a[maxn],b[maxn];
int main()
{
int n;
while((scanf("%d",&n))!=EOF)
{
memset(a,,sizeof(a));
memset(b,,sizeof(b));
int t=n;
for(int i=;i<=n;i++)
{
scanf("%d",&a[i]);
b[a[i]]=;
for(;b[t]==;t--)
printf("%d ",t);
printf("\n");
}
}
return ;
}
767A Snacktower的更多相关文章
- codeforces 767A Snacktower(模拟)
A. Snacktower time limit per test:2 seconds memory limit per test:256 megabytes input:standard input ...
- CodeForces - 767A Snacktower
题目大意 一个数可以被输出当且仅当所有比它大的数都已经输出.输入一个1~n的排列,求每次输出的输出序列. 题解 直接用堆模拟 #include <queue> #include <c ...
- 【codeforces 767A】Snacktower
[题目链接]:http://codeforces.com/contest/767/problem/A [题意] 每天掉一个盘子下来;盘子有大小从1..n依次增大n个盘子; 然后让你叠盘子; 最底层为n ...
- Codeforces Round #398 (Div. 2) A. Snacktower 模拟
A. Snacktower 题目连接: http://codeforces.com/contest/767/problem/A Description According to an old lege ...
- CF767 A. Snacktower 暴力
LINK 题意:给出一个序列,如果存的数满足连续递减(第一个必须为n)则输出否则输出空行,并暂存当前数 思路:直接暴力不可行,由于待输出的数的个数满足单调性可以稍微优化,即从上一回输出的最小一个数开始 ...
- 【暴力】Codeforces Round #398 (Div. 2) A. Snacktower
题意不复述. 用个bool数组记录一下,如果某一天,当前剩下的最大的出现了的话,就输出一段. #include<cstdio> using namespace std; int n; bo ...
- Codeforces Round #398 (Div. 2)
Codeforces Round #398 (Div. 2) A.Snacktower 模拟 我和官方题解的命名神相似...$has$ #include <iostream> #inclu ...
- Codeforces Round #398 (div.2)简要题解
这场cf时间特别好,周六下午,于是就打了打(谁叫我永远1800上不去div1) 比以前div2的题目更均衡了,没有太简单和太难的...好像B题难度高了很多,然后卡了很多人. 然后我最后做了四题,E题感 ...
- mac环境破解navicat premium 12.1
1. 下载破解工具 https://github.com/DoubleLabyrinth/navicat-keygen/tree/mac 其中,navicat-keygen为破解器:navicat-p ...
随机推荐
- IIS7根据PID查找对应的站点
runas /user:administrator cmd cd \Windows\System32\inetsrv appcmd.exe list wp
- 常用数据库4 mongodb
知识内容: 1.mongodb介绍与基本使用 2.mongodb操作 一.mongodb介绍与基本使用 1.mongodb介绍 Mongodb是一款强大,灵活,且易于扩展的通用型数据库.它能扩展出非常 ...
- 网站搜索引擎优化SEO策略及相关工具资源
网站优化的十大奇招妙技 1. 选择有效的关键字: 关键字是描述你的产品及服务的词语,选择适当的关键字是建立一个高排名网站的第一步.选择关键字的一个重要的技巧是选取那些常为人们在搜索时所用到的关键字. ...
- C常用问题
linux系统,gcc编译器包含引用的头文件位置
- centos7.3nginx配置二级域名过程
nginx1.10.2 1先检查 /etc/nginx/nginx.conf 是否include conf.d include /etc/nginx/conf.d/*.conf; 默认都是包含的,如 ...
- IOUtils总结
参考:https://www.cnblogs.com/xing901022/p/5978989.html 常用的静态变量 在IOUtils中还是有很多常用的一些变量的,比如换行符等等 public s ...
- Socket IO Web实时推送
1服务器pom.xml引入 <!-- 服务端 --> <dependency> <groupId>com.corundumstudio.socketio</g ...
- 18 subprocess模块(跟操作系统交互)
1.基本概念介绍 我们经常需要通过Python去执行一条系统命令或脚本,系统的shell命令是独立于你的python进程之外的, 每执行一条命令,就是发起一个新进程,通过python调用系统命令或脚本 ...
- ubuntu16.04安装tensorflow-gpu和cuda8.0加速训练
转载请注明出处:http://www.cnblogs.com/buxizhizhoum/p/8086230.html 环境: 系统:ubuntu 16.04 cpu:i5 gpu:gt920m mem ...
- Mysql binlog二进制日志
Mysql binlog日志有三种格式,分别为Statement,MiXED,以及ROW! 1.Statement:每一条会修改数据的实际原sql语句都会被记录在binlog中. 优点:不需要记录每一 ...