B. Rebranding
time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

The name of one small but proud corporation consists of n lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.

For this purpose the corporation has consecutively hired m designers. Once a company hires the i-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters xi by yi, and all the letters yi by xi. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that xi coincides with yi. The version of the name received after the work of the last designer becomes the new name of the corporation.

Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.

Satisfy Arkady's curiosity and tell him the final version of the name.

Input

The first line of the input contains two integers n and m (1 ≤ n, m ≤ 200 000) — the length of the initial name and the number of designers hired, respectively.

The second line consists of n lowercase English letters and represents the original name of the corporation.

Next m lines contain the descriptions of the designers' actions: the i-th of them contains two space-separated lowercase English letters xi and yi.

Output

Print the new name of the corporation.

Sample test(s)
input
6 1
police
p m
output
molice
input
11 6
abacabadaba
a b
b c
a d
e g
f a
b b
output
cdcbcdcfcdc
Note

In the second sample the name of the corporation consecutively changes as follows:

不能暴力搜索,暴力会TLE

将其转化为在26个英文字母表里的序号位置,通过交换位置来实现字母的交换,最终输出对应的字母

#include<stdio.h>
#include<string.h>
#include<algorithm>
#include<math.h> using namespace std; const int N = ; char s[N]; int main()
{
char a[], b[];
int n, m, i, q[];
while(~scanf("%d%d", &n, &m))
{
scanf("%s", s);
for(i = ; i < ; i++)
q[i] = i;
while(m--)
{
scanf("%s%s", a, b);
int x = a[] - 'a';
int y = b[] - 'a';
for(i = ; i < ; i++)
{
if(q[i] == x)
q[i] = y;
else if(q[i] == y)
q[i] = x;
}
}
for(i = ; s[i] != '\0' ; i++)
printf("%c", q[s[i] - 'a'] + 'a');
printf("\n");
}
return ;
}
 

B. Rebranding的更多相关文章

  1. Codeforces Round #327 (Div. 2) B. Rebranding C. Median Smoothing

    B. Rebranding The name of one small but proud corporation consists of n lowercase English letters. T ...

  2. Codeforces Round #327 (Div. 2) B. Rebranding 水题

    B. Rebranding Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/591/problem ...

  3. cf591B Rebranding

    B. Rebranding time limit per test 2 seconds memory limit per test 256 megabytes input standard input ...

  4. codeforces 591B Rebranding (模拟)

    Rebranding Problem Description The name of one small but proud corporation consists of n lowercase E ...

  5. ural 2032 Conspiracy Theory and Rebranding (数学水题)

    ural 2032  Conspiracy Theory and Rebranding 链接:http://acm.timus.ru/problem.aspx?space=1&num=2032 ...

  6. Rebranding(模拟+思维)

    The name of one small but proud corporation consists of n lowercase English letters. The Corporation ...

  7. Rebranding(字母代换)

    个人心得:题目意思就是每次给出可以互换的字母,如果每次命令的时候就执行的话一定会超时. 所以我就是将输入的字母从a到z的数目和路径依次保存,再建立一个book数组表示字母现在所指的字母 ,一开始就直接 ...

  8. Codeforces Round #327 (Div. 2) B. Rebranding 模拟

    B. Rebranding   The name of one small but proud corporation consists of n lowercase English letters. ...

  9. Codeforces 591 B:Rebranding

    B. Rebranding time limit per test 2 seconds memory limit per test 256 megabytes input standard input ...

随机推荐

  1. CSS之剪切横幅

    简述 clip-path属性指定一个应用到元素上的剪切路径.应用在SVG中<clipPath>元素上的属性值可以完全运用在clip-path属性上.还可以使用CSS Shapes模块中的基 ...

  2. 51nod1215 数组的宽度

    傻叉单调栈 #include<cstdio> #include<cstring> #include<cctype> #include<algorithm> ...

  3. mysql约束(自己原先总结的有点不准)

    约束* 约束是添加在列上的,用来约束列的! 1. 主键约束(唯一标识) ****非空*** ****唯一*** ****被引用****(学习外键时) * 当表的某一列被指定为主键后,该列就不能为空,不 ...

  4. Http进行网络通信

    http使用get的方式进行网络通信: package com.testGet; import java.io.BufferedReader; import java.io.IOException; ...

  5. 所在实习公司的JS笔试题

    在班上无聊的时候看到了一份JS笔试题(我是电面进去的,没做过这份题~~),开始还觉得蛮简单......后来觉得还是很有意思的,贴出来一起看看. 题目一: if(!("a" in w ...

  6. mysql同步 小问题

    由于历史遗留问题,我们的MySQL主从库的表结构不一致,主库的某个表tableA比从库表tableA少了一个字段. 当尝试在主库上更改表结构时,这行alter语句会随着binlog同步到从库,如果从库 ...

  7. java jodd框架介绍及使用示例

    Jodd是一个普通开源Java包.你可以把Jodd想象成Java的"瑞士军刀",不仅小,锋利而且包含许多便利的功能.Jodd 提供的功能有:  提供操作Java bean,  可以 ...

  8. 【转】Linux设备驱动之I/O端口与I/O内存

    原文网址:http://www.cnblogs.com/geneil/archive/2011/12/08/2281367.html 一.统一编址与独立编址 该部分来自于:http://blog.ch ...

  9. 基于CentOS与VmwareStation10搭建Oracle11G RAC 64集群环境:2.搭建环境-2.1创建虚拟机

    2.1.创建虚拟机 2.1.1. 创建虚拟机节点1 2.1.2.  创建虚拟机节点2 操作如节点1. 基于CentOS与VmwareStation10搭建Oracle11G RAC 64集群环境所有链 ...

  10. ubuntu 安装AMP环境的笔记 Prefork方式与fast-cgi方法

    具体步骤如下: 系统:ubuntu 8.04 的发行版本 AMP with Prefork(mod-php5)       一.安装APACHE2 # sudo  apt-get  install   ...