[POJ] #1005# I Think I Need a Houseboat : 浮点数运算
| Time Limit: 1000MS | Memory Limit: 10000K | |
| Total Submissions: 97512 | Accepted: 42430 |
Description
After doing more research, Fred has learned that the land that is
being lost forms a semicircle. This semicircle is part of a circle
centered at (0,0), with the line that bisects the circle being the X
axis. Locations below the X axis are in the water. The semicircle has an
area of 0 at the beginning of year 1. (Semicircle illustrated in the
Figure.)
Input
first line of input will be a positive integer indicating how many data
sets will be included (N). Each of the next N lines will contain the X
and Y Cartesian coordinates of the land Fred is considering. These will
be floating point numbers measured in miles. The Y coordinate will be
non-negative. (0,0) will not be given.
Output
each data set, a single line of output should appear. This line should
take the form of: “Property N: This property will begin eroding in year
Z.” Where N is the data set (counting from 1), and Z is the first year
(start from 1) this property will be within the semicircle AT THE END OF
YEAR Z. Z must be an integer. After the last data set, this should
print out “END OF OUTPUT.”
Sample Input
2
1.0 1.0
25.0 0.0
Sample Output
Property 1: This property will begin eroding in year 1.
Property 2: This property will begin eroding in year 20.
END OF OUTPUT.
Hint
2.This problem will be judged automatically. Your answer must match
exactly, including the capitalization, punctuation, and white-space.
This includes the periods at the ends of the lines.
3.All locations are given in miles.
Source
- 河水以每年50平方为单位,呈半圆形扩张侵蚀土地
- 以半圆中心点(0, 0), 建立坐标系
- 给出坐标(x, y),输出该点土地在哪一年会被侵蚀
三. 分析
- 算法核心: 题目较为简单,只需知道基本的求圆面积的几何公式
- 实现细节:
- 圆面积公式
- 结果输出的条件判断
- 浮点类型运算
四. 题解
#include <stdio.h>
#define PI 3.1415927 int main()
{
int area, year, i, count;
float x, y; scanf("%d\n", &count);
for (i = ; i <= count; i++) {
scanf("%f %f\n", &x, &y); area = ; year = ;
while () {
area += ;
if (area > (PI * (x * x + y * y) / )) break;
year++;
}
printf("Property %d: This property will begin eroding in year %ld.\n", i, year);
} printf("END OF OUTPUT.\n");
return ;
}
[POJ] #1005# I Think I Need a Houseboat : 浮点数运算的更多相关文章
- POJ. 1005 I Think I Need a Houseboat(水 )
POJ. 1005 I Think I Need a Houseboat(水 ) 代码总览 #include <cstdio> #include <cstring> #incl ...
- OpenJudge/Poj 1005 I Think I Need a Houseboat
1.链接地址: http://bailian.openjudge.cn/practice/1005/ http://poj.org/problem?id=1005 2.题目: I Think I Ne ...
- [POJ 1005] I Think I Need a Houseboat C++解题
I Think I Need a Houseboat Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 81874 ...
- poj 1005:I Think I Need a Houseboat(水题,模拟)
I Think I Need a Houseboat Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 85149 Acce ...
- poj 1005 I Think I Need a Houseboat
#include <iostream> using namespace std; const double pi = 3.1415926535; int main() { ;; doubl ...
- I Think I Need a Houseboat POJ - 1005
I Think I Need a Houseboat POJ - 1005 解题思路:水题 #include <iostream> #include <cstdio> #inc ...
- I Think I Need a Houseboat POJ - 1005(数学)
题目大意 在二维坐标内选定一个点,问你当洪水以半圆形扩散且每年扩散50单位,哪一年这个点被被洪水侵蚀? 解法 代码 #include <iostream> #include <cst ...
- POJ 1005 解题报告
1.题目描述 2.解题思路 好吧,这是个水题,我的目的暂时是把poj第一页刷之,所以水题也写写吧,这个题简单数学常识而已,给定坐标(x,y),易知当圆心为(0,0)时,半圆面积为0.5*PI*(x ...
- 1005 -- I Think I Need a Houseboat
I Think I Need a Houseboat Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 105186 Acc ...
随机推荐
- 浅谈学习C++时用到的【封装继承多态】三个概念
封装继承多态这三个概念不是C++特有的,而是所有OOP具有的特性. 由于C++语言支持这三个特性,所以学习C++时不可避免的要理解这些概念. 而在大部分C++教材中这些概念是作为铺垫,接下来就花大部分 ...
- [JWFD开源工作流]JWFD开源工作流官方下载内容更新
在更新版的JWFD二次开发包中,我正在实现单线程的时钟控制器,动了下引擎的源代码,这个更新包主要是升级界面,内核代码,大家就不用升级了.. 代码提示: 请修改代码包中(org.jwfd.workflo ...
- php注册登录系统(一)-极简
序 登录注册系统是日常上网最普通的操作,我设了一个分类一步步完善注册登录系统,若有哪里错误请慧教 所用语言:php 数据库 :mysql 本次实现功能: 1.用户注册 2.用户登录 主要文件: 完整代 ...
- arranging-coins
https://leetcode.com/problems/arranging-coins/ public class Solution { public int arrangeCoins(int n ...
- JavaScript判断浏览器类型及版本
JavaScript是前端开发的主要语言,我们可以通过编写JavaScript程序来判断浏览器的类型及版本.JavaScript判断浏览器类型一般有两种办法,一种是根据各种浏览器独有的属性来分辨,另一 ...
- 简单了解JAVA8的新特性
JAVA8新特性会颠覆整个JAVA程序员的编程习惯 甚至如果您坚守JAVA7之前的编程习惯,今后你看比较年轻的程序员写的JAVA代码都会无法理解 所以为了保证不脱钩,我觉得有必要学习JAVA8的新特性 ...
- 使用Less color函数创建专业网站配色方案
Less提供了很多实用的函数专门用于定义和操作色彩.本文将介绍如何使用这些函数来 帮助你控制色彩,创造合适的色彩搭配,并且保持网站的一致性和专业性 color spinning spin()函数允许我 ...
- 编写jquery插件的分享
一.类级别($.extend) 类级别你可以理解为拓展jquery类,最明显的例子是$.ajax(...),相当于静态方法. 开发扩展其方法时使用$.extend方法,即jQuery.extend(o ...
- Npoi Web 项目中(XSSFWorkbook) 导出出现无法访问已关闭的流的解决方法
原本在CS项目中用的好好的在BS项目中既然提示我导出出现无法访问已关闭的流的解决方法 比较郁闷经过研究 终于解决了先将方法发出来 让遇到此问题的筒子们以作参考 //新建类 重写Npoi流方法 publ ...
- rmmod 无法卸载模块问题
用insmod加载驱动模块成功后,用rmmod无法卸载 解决方法:在板子上建立一个空目录:lib/modules/2.6.30.4/