I Think I Need a Houseboat
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 81874   Accepted: 35368

Description

Fred Mapper is considering purchasing some land in Louisiana to build his house on. In the process of investigating the land, he learned that the state of Louisiana is actually shrinking by 50 square miles each year, due to erosion caused by the Mississippi River. Since Fred is hoping to live in this house the rest of his life, he needs to know if his land is going to be lost to erosion.

After doing more research, Fred has learned that the land that is
being lost forms a semicircle. This semicircle is part of a circle
centered at (0,0), with the line that bisects the circle being the X
axis. Locations below the X axis are in the water. The semicircle has an
area of 0 at the beginning of year 1. (Semicircle illustrated in the
Figure.)

Input

The
first line of input will be a positive integer indicating how many data
sets will be included (N). Each of the next N lines will contain the X
and Y Cartesian coordinates of the land Fred is considering. These will
be floating point numbers measured in miles. The Y coordinate will be
non-negative. (0,0) will not be given.

Output

For
each data set, a single line of output should appear. This line should
take the form of: “Property N: This property will begin eroding in year
Z.” Where N is the data set (counting from 1), and Z is the first year
(start from 1) this property will be within the semicircle AT THE END OF
YEAR Z. Z must be an integer. After the last data set, this should
print out “END OF OUTPUT.”

Sample Input

2
1.0 1.0
25.0 0.0

Sample Output

Property 1: This property will begin eroding in year 1.
Property 2: This property will begin eroding in year 20.
END OF OUTPUT.

Hint

1.No property will appear exactly on the semicircle boundary: it will either be inside or outside.
2.This problem will be judged automatically. Your answer must match
exactly, including the capitalization, punctuation, and white-space.
This includes the periods at the ends of the lines.

3.All locations are given in miles.
 

解决思路

这是一道很简单的计算几何题,本质就是计算点是否在指定的半圆内。

源码

 /*
poj 1000
version:1.0
author:Knight
Email:S.Knight.Work@gmail.com
*/ #include<cstdio>
#include<cmath>
using namespace std;
const double PI = 3.1415926;
int main(void)
{
double S;//被腐蚀陆地的总面积
double r;//腐蚀陆地的半径
int i,j;
int T;
double X,Y;//Fred的坐标
double Distance;//Fred据坐标原点的距离
scanf("%d", &T);
for (i=; i<=T; i++)
{
scanf("%lf%lf", &X, &Y);
Distance = sqrt(X * X + Y * Y);
S = 0.0;
for (j=; ; j++)
{
S += 50.0;
r = sqrt( * S / PI);
if (r >= Distance)
{
break;
}
}
printf("Property %d: This property will begin eroding in year %d.\n", i, j);
}
printf("END OF OUTPUT.\n");
return ;
}
 

[POJ 1005] I Think I Need a Houseboat C++解题的更多相关文章

  1. POJ. 1005 I Think I Need a Houseboat(水 )

    POJ. 1005 I Think I Need a Houseboat(水 ) 代码总览 #include <cstdio> #include <cstring> #incl ...

  2. OpenJudge/Poj 1005 I Think I Need a Houseboat

    1.链接地址: http://bailian.openjudge.cn/practice/1005/ http://poj.org/problem?id=1005 2.题目: I Think I Ne ...

  3. poj 1005:I Think I Need a Houseboat(水题,模拟)

    I Think I Need a Houseboat Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 85149   Acce ...

  4. [POJ] #1005# I Think I Need a Houseboat : 浮点数运算

    一. 题目 I Think I Need a Houseboat Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 97512 ...

  5. poj 1005 I Think I Need a Houseboat

    #include <iostream> using namespace std; const double pi = 3.1415926535; int main() { ;; doubl ...

  6. I Think I Need a Houseboat POJ - 1005

    I Think I Need a Houseboat POJ - 1005 解题思路:水题 #include <iostream> #include <cstdio> #inc ...

  7. I Think I Need a Houseboat POJ - 1005(数学)

    题目大意 在二维坐标内选定一个点,问你当洪水以半圆形扩散且每年扩散50单位,哪一年这个点被被洪水侵蚀? 解法 代码 #include <iostream> #include <cst ...

  8. POJ 1005 解题报告

    1.题目描述   2.解题思路 好吧,这是个水题,我的目的暂时是把poj第一页刷之,所以水题也写写吧,这个题简单数学常识而已,给定坐标(x,y),易知当圆心为(0,0)时,半圆面积为0.5*PI*(x ...

  9. 1005 -- I Think I Need a Houseboat

    I Think I Need a Houseboat Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 105186   Acc ...

随机推荐

  1. intelliJ idea 激活和配置

    1. 双击打开 Intellij IDEA 桌面快捷方式图标,如下图: 2. 点击 ok 按钮,进入激活页面: 3. 他提供的三种方式激活:账号激活,激活码激活,服务器地址激活,我们选择激活码激活,去 ...

  2. 零基础逆向工程21_PE结构05_数据目录表_导出表

    数据目录 1.我们所了解的PE分为头和节,在每个节中,都包含了我们写的一些代码和数据,但还有一些非常重要 的信息是编译器替我们加到PE文件中的,这些信息可能存在在任何可以利用的地方. 2.这些信息之所 ...

  3. Centos离线安装Docker并加入到Swarm管理节点

    以root用户登录 加入Swarm前需要在Swarm上生成Token,所以需要提前将Swarm集群搭建完成后,再运行以下命令将各虚机加入到swarm节点 下载docker离线安装包,并拷贝到/root ...

  4. 初识ProgressBar

    Android FormWidget之一 实现起来很简单,大体有两种style. 怎么自定义ProgressBar? 有两种方法,一种是运用android:progressDrawable=" ...

  5. /usr/local/sbin/fping -s www.baidu.com www.google.com

    /usr/local/sbin/fping -s www.baidu.com www.google.com

  6. SharePoint 2010 缺少站点保存为模板选项

    如果您尝试在SharePoint Server 2010中保存网站,并且没有看到"将网站另存为模板"选项,则可能是因为该网站已启用发布功能.如果使用站点发布功能,则有几个选项可将网 ...

  7. 有关mybatis的动态sql

    一般地,实现动态SQL都是在xml中使用等标签实现的. 我们在这里使用SQL构造器的方式, 即由abstract sql写出sql的过程, 当然感觉本质上还是一个StringBuilder, 来手动生 ...

  8. noip模拟赛#45

    T1:n<=1e6,求最小的区间包含(1,m)的所有数. =>双指针扫一遍即可 #include<cstdio> #include<cstring> #includ ...

  9. js判断是否为app

    var ua = navigator.userAgent; var isapp = ua.match("lenovomallapp") == null ? 0 : 1;

  10. 毛毛虫组【Beta】Scrum Meeting 1

    第一天 日期:2019/6/23 前言 第一次会议: 时间:6月20日 地点:教9-C404机房 内容:此次会议主要确定组内成员具体分工,并对目标进行了初步的确定. 1.1 今日完成任务情况以及遇到的 ...