CodeForces - 600B Queries about less or equal elements （二分查找 利用stl）

传送门：

http://codeforces.com/problemset/problem/600/B

Queries about less or equal elements

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

You are given two arrays of integers a and b. For each element of the second array b_j you should find the number of elements in array a that are less than or equal to the value b_j.

Input

The first line contains two integers n, m (1 ≤ n, m ≤ 2·10⁵) — the sizes of arrays a and b.

The second line contains n integers — the elements of array a ( - 10⁹ ≤ a_i ≤ 10⁹).

The third line contains m integers — the elements of array b ( - 10⁹ ≤ b_j ≤ 10⁹).

Output

Print m integers, separated by spaces: the j-th of which is equal to the number of such elements in array a that are less than or equal to the value b_j.

Examples

Input

Copy

5 4
1 3 5 7 9
6 4 2 8

Output

Copy

3 2 1 4

Input

Copy

5 5
1 2 1 2 5
3 1 4 1 5

Output

Copy

4 2 4 2 5

分析：
题目意思：
输入数组A和B，要求输出数组A中比B[i]小的数的个数。
做法：
暴力会超时，利用二分查找
upper_bound（A， A+N,  B[i]）- A；返回大于B[i]按照正序应存放的地址，取地址后是下标。

code：

#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
#define max_v 200005
int a[max_v],b[max_v];
int main()
{
    int n,m;
    while(cin>>n>>m)
    {
        for(int i=;i<n;i++)
            cin>>a[i];
        for(int i=;i<m;i++)
            cin>>b[i];
        sort(a,a+n);
        for(int i=;i<m;i++)
        {
            if(i==m-)
            {
                printf("%d\n",upper_bound(a,a+n,b[i])-a);
            }else
            {
                printf("%d ",upper_bound(a,a+n,b[i])-a);
            }
        }
    }
    return ;
}