Description

A simple mathematical formula for e is

where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.        
 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.        
 

Sample Output

n e - -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
 
 
 
#include<iostream>
#include<iomanip>
using namespace std;
double f(int n)
{
long double a=;
for(int i=;i<=n;i++)a*=i;
return a;
}
int main()
{
cout << "n e"<<endl<<"- -----------"<<endl;
double e=;
cout<<<<" "<<e<<endl;
for(int i=;i<=;++i)
{
e+=/f(i);
cout<<i<<" ";
if(i!=) cout<<setprecision()<<e<<endl;
else cout<<setprecision()<<e<<<<endl;
}
//system("pause");
return ;
}

不难!!不要忘了long double !!!!

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