pyhton学习，day1作业，用户名密码登录模块

要求，通过用户名密码登录，登录错误3次，锁定用户名

 # coding=utf-8
 # Author: RyAn Bi

 import os, sys  #调用系统自己的库

 accounts_file = 'E:\\homework\\user.txt'  # 存放用户名密码的位置
 lock_file = 'E:\\homework\\lock.txt'  #存放锁定用户名的位置
 print('accounts_file:', accounts_file)
 '''
 temp1 = open(accounts_file,'a') #a为加入
 temp1.write('bjb,123'+'\n')
 temp1.close()  #写入用户名密码的功能，在登录的时候不用
 '''
 user = open(accounts_file, 'r') #r为只读
 # print('user:',user)
 account_list = user.readlines()  #逐行按分隔符阅读，readline是逐字节阅读
 # print('account_list:',account_list)
 user.close()   #读取用户名和密码到内存中

 user1 = open(lock_file, "r")
 lock_list = user1.readlines()
 # print(lock_list)
 user1.close()  #读取被锁定的用户名到内存中
 loginSucess = False   #默认将loginSucess置为假
 while True:
     username = input('username:').strip()  #.strip是去除空格和\n
     lockid = 0        #锁定用户标识值为零，不锁定
     if len(username) != 0:      #假如用户名不为空
         for i in lock_list:
             # i = i.split(' ')   #i的分割符为空格
             # print(i)
             if username == i.strip():
                 print('your username %s is locked!' % username)
                 lockid = 1
                 break  # 判断该帐号是否被锁定
         for i in account_list:
             # print(i)
             if lockid == 1:  #被锁定了禁止执行
                 break
             else:
                 i = i.split(',')
                 # print(i)
                 if username == i[0]:
                     for x in range(3):
                         password = input('password:').strip()
                         if password == i[1].strip():  # 去掉空格和换行符
                             loginSucess = True
                             # print('you are right')
                             break   #验证3次密码，成功了置 loginsuccess 为真
                     else:
                         print('%s,you input wrong password 3 times,your %s is locked!' % (username, username))
                         l = open(lock_file, 'w') #w只允许写入，以写入方式打开locklist
                         if l != "":
                             l = open(lock_file, 'a') #假如是locklist中有内容，用添加方式打开locklist，避免空白行
                         l.write(username + '\n') #将用户名写入
                         l.close()
                         lockid = 1
                         # view = open(lock_file)
                         # print(view.read())
         if loginSucess is True:
             print('welcome to system')
             break
         elif lockid == 0:
             print('you input a wrong username，pls input again')
         else:
             # print('%s,you input wrong password 3 times,your %s is locked!' % (username, username))
             break
     else:  # 用户名输入为空的时候
         continue