Recursion + Memorized Search(DP). And apparently, the code below can be iterative with only 3 vars - DP.

class Solution {
unordered_map<int, bool> cache;
public:
bool go(int n)
{
if (n <=) return false;
if (n < ) return true; if(cache.find(n) == cache.end())
{
cache[n] = !go(n - ) || !go(n - );
}
return cache[n];
}
/**
* @param n: an integer
* @return: a boolean which equals to true if the first player will win
*/
bool firstWillWin(int n) {
return go(n);
}
};

LintCode "Coins in a Line"的更多相关文章

  1. LintCode: coins in a line I

    有 n 个硬币排成一条线.两个参赛者轮流从右边依次拿走 1 或 2 个硬币,直到没有硬币为止.拿到最后一枚硬币的人获胜. 请判定 第一个玩家 是输还是赢? n = 1, 返回 true.n = 2, ...

  2. [LintCode] Coins in a Line II 一条线上的硬币之二

    There are n coins with different value in a line. Two players take turns to take one or two coins fr ...

  3. [LintCode] Coins in a Line 一条线上的硬币

    There are n coins in a line. Two players take turns to take one or two coins from right side until t ...

  4. LintCode "Coins in a Line III" !!

    https://codesolutiony.wordpress.com/2015/05/24/lintcode-coins-in-a-line-iii/ A very juicy one! Deser ...

  5. LintCode "Coins in a Line II" !

    Nice one to learn: DP + Game Theoryhttps://lefttree.gitbooks.io/leetcode/content/dynamicProgramming2 ...

  6. [LeetCode] 877. Stone Game == [LintCode] 396. Coins in a Line 3_hard tag: 区间Dynamic Programming, 博弈

    Alex and Lee play a game with piles of stones.  There are an even number of piles arranged in a row, ...

  7. lintcode 394. Coins in a Line 、leetcode 292. Nim Game 、lintcode 395. Coins in a Line II

    变型:如果是最后拿走所有石子那个人输,则f[0] = true 394. Coins in a Line dp[n]表示n个石子,先手的人,是必胜还是必输.拿1个石子,2个石子之后都是必胜,则当前必败 ...

  8. Lintcode394 Coins in a Line solution 题解

    [题目描述] There are n coins in a line. Two players take turns to take one or two coins from right side ...

  9. LeetCode Coins in a Line

    There are n coins in a line. Two players take turns to take one or two coins from right side until t ...

随机推荐

  1. 【avalon源码】

    1. document.getElementsByTagName('head')[0] document.head 2. 3. var IEVersion = NaN if (window.VBArr ...

  2. 五 Servlet 技术

    一 Servlet 基础 1. 定义相关: a) 是运行在 Web 服务器上得 Java 小程序 b) 只将处理结果返回给客户 c) 是实现接口 Servlet 的 java 类,能被服务器调用. d ...

  3. Java-->利用文件指针分割文件

    --> 大体上和字节流分割的方式没什么区别,只是加入文件指针确定要开始分割的位置... package com.dragon.java.splitmp3; import java.io.File ...

  4. sql语句 优化技巧

    1.应尽量避免在 where 子句中使用!=或<>操作符,否则将引擎放弃使用索引而进行全表扫描. 2.对查询进行优化,应尽量避免全表扫描,首先应考虑在 where 及 order by 涉 ...

  5. QAQ

    贴吧怎么了最近多了一些脑残帖子 回答完问题你追我 ? 你追你mb你车费都凑不够. 答着答着你也许就哭了 我哭你mb 老子脑袋又没病 . 英国最最虐心的调查 ,我虐你mb还英国 你出过省吗? 晚上回家 ...

  6. Android.mk 文件语法详解 转:http://blog.sina.com.cn/s/blog_602f8770010148ce.html

    0. Android.mk简介: Android.mk文件用来告知NDK Build 系统关于Source的信息. Android.mk将是GNU Makefile的一部分,且将被Build Syst ...

  7. dotnetConf

    https://channel9.msdn.com/Events/dotnetConf/2016 https://channel9.msdn.com/Events/dotnetConf/2016?so ...

  8. OSGi 的核心配置、动态化及问题

    一.OSGi的核心组件Bundle,与java中jar包的差别就是元数据配置:      常用的Bundle元数据定义:     a) Bundle-Activator:定义Activator的实现全 ...

  9. NLTK中的词性

    NOUN n,VERB v ,ADJ a, ADV r, ADJ_SAT s     NOUN: [('s', ''), ('ses', 's'), ('ves', 'f'), ('xes', 'x' ...

  10. sublime安装sftp和ctags插件

    1. 安装Package Control插件 , 安装是通过Sublime Text 2控制台.这是通过按Ctrl + `快捷访问.一旦打开,粘贴以下命令到控制台. 输入以下python代码 subl ...