LintCode "Coins in a Line"
Recursion + Memorized Search(DP). And apparently, the code below can be iterative with only 3 vars - DP.
class Solution {
unordered_map<int, bool> cache;
public:
bool go(int n)
{
if (n <=) return false;
if (n < ) return true;
if(cache.find(n) == cache.end())
{
cache[n] = !go(n - ) || !go(n - );
}
return cache[n];
}
/**
* @param n: an integer
* @return: a boolean which equals to true if the first player will win
*/
bool firstWillWin(int n) {
return go(n);
}
};
LintCode "Coins in a Line"的更多相关文章
- LintCode: coins in a line I
有 n 个硬币排成一条线.两个参赛者轮流从右边依次拿走 1 或 2 个硬币,直到没有硬币为止.拿到最后一枚硬币的人获胜. 请判定 第一个玩家 是输还是赢? n = 1, 返回 true.n = 2, ...
- [LintCode] Coins in a Line II 一条线上的硬币之二
There are n coins with different value in a line. Two players take turns to take one or two coins fr ...
- [LintCode] Coins in a Line 一条线上的硬币
There are n coins in a line. Two players take turns to take one or two coins from right side until t ...
- LintCode "Coins in a Line III" !!
https://codesolutiony.wordpress.com/2015/05/24/lintcode-coins-in-a-line-iii/ A very juicy one! Deser ...
- LintCode "Coins in a Line II" !
Nice one to learn: DP + Game Theoryhttps://lefttree.gitbooks.io/leetcode/content/dynamicProgramming2 ...
- [LeetCode] 877. Stone Game == [LintCode] 396. Coins in a Line 3_hard tag: 区间Dynamic Programming, 博弈
Alex and Lee play a game with piles of stones. There are an even number of piles arranged in a row, ...
- lintcode 394. Coins in a Line 、leetcode 292. Nim Game 、lintcode 395. Coins in a Line II
变型:如果是最后拿走所有石子那个人输,则f[0] = true 394. Coins in a Line dp[n]表示n个石子,先手的人,是必胜还是必输.拿1个石子,2个石子之后都是必胜,则当前必败 ...
- Lintcode394 Coins in a Line solution 题解
[题目描述] There are n coins in a line. Two players take turns to take one or two coins from right side ...
- LeetCode Coins in a Line
There are n coins in a line. Two players take turns to take one or two coins from right side until t ...
随机推荐
- jellyfish K-mer analysis and genome size estimate
http://www.cbcb.umd.edu/software/jellyfish/ http://www.genome.umd.edu/jellyfish.html https://githu ...
- 获得项目的绝对地址 getRequestURI,getRequestURL的区别
java获得tomcat项目的绝对地址 String basePath = request.getScheme()+"://"+request.getServerName()+&q ...
- php 函数ignore_user_abort()
ignore_user_abort() 设置与客户机断开是否会终止脚本的执行. 工作中看到这样一个类似的方法,查资料理解了一下: 一个的ignore_user_abort()的例子,配合set_ti ...
- 今天想把iphone4刷成ios7.3beta,折腾半天,成功
今天想把iphone4刷成ios7.3beta,折腾半天,成功 总结如下 1 确认你是无锁机,要是有锁的,就先算了吧.我手里的是台版的无锁,这关过了. 2 得是干净非越狱的,一开始是4.2.1版本的越 ...
- Codeforces Round #127 (Div. 2)
A. LLPS 长度最大10,暴力枚举即可. B. Brand New Easy Problem 枚举\(n\)的全排列,按题意求最小的\(x\),即逆序对个数. C. Clear Symmetry ...
- UVa 1225 Digit Counting --- 水题
UVa 1225 题目大意:把前n(n<=10000)个整数顺次写在一起,12345678910111213...,数一数0-9各出现多少字 解题思路:用一个cnt数组记录0-9这10个数字出现 ...
- hdu1058丑数(优先队列、暴力打表)
hdu1058 题意:当一个数只有2.3.5.7这四种质因数时(也可以一种都没有或只有其中几种),这个数就是丑数,输出第 n 个丑数是多少: 其实并没有发现hdu把这道题放在 dp 专题里的意图,我的 ...
- 【BZOJ1009】【HNOI2008】GT考试
依旧看人代码写,不过我觉得自己慢慢写一个也可以写成? 原题: 阿申准备报名参加GT考试,准考证号为N位数X1X2....Xn(0<=Xi<=9),他不希望准考证号上出现不吉利的数字.他的不 ...
- What is Proguard?
When packaging an apk, all classes of all libraries used by the program will be included, this makes ...
- 翻译:Universal Image Loader
本文转载于:http://blog.csdn.net/tianxiangshan/article/details/9399183 All manipulations are held by the I ...