Werewolf(狼人杀) is a game in which the players are partitioned into two parties: the werewolves and the human beings. Suppose that in a game,

  • player #1 said: "Player #2 is a werewolf.";
  • player #2 said: "Player #3 is a human.";
  • player #3 said: "Player #4 is a werewolf.";
  • player #4 said: "Player #5 is a human."; and
  • player #5 said: "Player #4 is a human.".

Given that there were 2 werewolves among them, at least one but not all the werewolves were lying, and there were exactly 2 liars. Can you point out the werewolves?

Now you are asked to solve a harder version of this problem: given that there were N players, with 2 werewolves among them, at least one but not all the werewolves were lying, and there were exactly 2 liars. You are supposed to point out the werewolves.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (5). Then N lines follow and the i-th line gives the statement of the i-th player (1), which is represented by the index of the player with a positive sign for a human and a negative sign for a werewolf.

Output Specification:

If a solution exists, print in a line in ascending order the indices of the two werewolves. The numbers must be separated by exactly one space with no extra spaces at the beginning or the end of the line. If there are more than one solution, you must output the smallest solution sequence -- that is, for two sequences [ and [, if there exists 0 such that [ (i≤k) and [, then A is said to be smaller than B. In case there is no solution, simply print No Solution.

Sample Input 1:

5
-2
+3
-4
+5
+4
 

Sample Output 1:

1 4
 

Sample Input 2:

6
+6
+3
+1
-5
-2
+4
 

Sample Output 2 (the solution is not unique):

1 5
 

Sample Input 3:

5
-2
-3
-4
-5
-1
 

Sample Output 3:

No Solution

题意:

  有N个人,这里面有两只是狼人,一只狼人说真话,另一只狼人说假话,另外还有一个人类说假话,判断那两个人是狼人。

思路:

  看大佬写的吧~

Code:

#include<iostream>
#include<vector>
#include<cmath>
#include<set>
#include<algorithm> using namespace std; bool cmp(pair<int, int> a, pair<int, int> b) {
if (a.first == b.first) {
return a.second < b.second;
} else {
return a.first < b.first;
}
} int main() {
int n, t;
cin >> n; set<int> human;
set<int> werewolf;
vector<int> said(n+1, 0);
vector<pair<int, int> > twoWereWolf; for (int i = 1; i <= n; ++i) {
cin >> t;
said[i] = t;
} bool wrong = false;
int werewolf1, werewolf2;
bool foundWerewolf1 = false;
bool foundWerewolf2 = false;
for (int i = 1; i <= n; ++i) {
for (int j = 1; j <= n; ++j) {
if (j == i) continue;
werewolf1 = -1;
werewolf2 = -1;
wrong = false;
foundWerewolf1 = false;
foundWerewolf2 = false;
human.clear();
werewolf.clear();
for (int k = 1; k <= n; ++k) {
if (k != i && k != j) {
if (said[k] < 0)
werewolf.insert(abs(said[k]));
else
human.insert(said[k]);
}
}
for (int h : human) {
if (h == i) {
werewolf1 = j;
foundWerewolf1 = true;
}
if (h == j) {
werewolf1 = i;
foundWerewolf1 = true;
}
}
for (int w : werewolf) {
if (w != werewolf1) {
werewolf2 = w;
foundWerewolf2 = true;
}
}
if (foundWerewolf1 && foundWerewolf2) {
if (human.find(foundWerewolf1) == human.end() && human.find(foundWerewolf2) == human.end())
if (werewolf.find(werewolf1) != werewolf.end() || werewolf.find(werewolf2) != werewolf.end())
twoWereWolf.push_back({werewolf1, werewolf2});
}
}
} sort(twoWereWolf.begin(), twoWereWolf.end(), cmp); if (twoWereWolf.size() > 0) {
cout << twoWereWolf[0].first << " " << twoWereWolf[0].second << endl;
} else {
cout << "No Solution" << endl;
} return 0;
}

记得上上次考试的时候我没有做出来这道题,今天又做了一下,只通过了两组样例。


大佬的代码:https://www.liuchuo.net/archives/6494

#include <iostream>
#include <vector>
#include <cmath>
using namespace std;
int main() {
int n;
cin >> n;
vector<int> v(n+1);
for (int i = 1; i <= n; i++) cin >> v[i];
for (int i = 1; i <= n; i++) {
for (int j = i + 1; j <= n; j++) {
vector<int> lie, a(n + 1, 1);
a[i] = a[j] = -1;
for (int k = 1; k <= n; k++)
if (v[k] * a[abs(v[k])] < 0) lie.push_back(k);
if (lie.size() == 2 && a[lie[0]] + a[lie[1]] == 0) {
cout << i << " " << j;
return 0;
}
}
}
cout << "No Solution";
return 0;
}

1148 Werewolf - Simple Version的更多相关文章

  1. PAT 1148 Werewolf - Simple Version

    1148 Werewolf - Simple Version (20 分)   Werewolf(狼人杀) is a game in which the players are partitioned ...

  2. PAT 1148 Werewolf - Simple Version [难理解]

    1148 Werewolf - Simple Version (20 分) Werewolf(狼人杀) is a game in which the players are partitioned i ...

  3. PAT(A) 1148 Werewolf - Simple Version(Java)逻辑推理

    题目链接:1148 Werewolf - Simple Version (20 point(s)) Description Werewolf(狼人杀) is a game in which the p ...

  4. 1148 Werewolf - Simple Version (20 分)

    Werewolf(狼人杀) is a game in which the players are partitioned into two parties: the werewolves and th ...

  5. PAT_A1148#Werewolf - Simple Version

    Source: PAT 1148 Werewolf - Simple Version (20 分) Description: Werewolf(狼人杀) is a game in which the ...

  6. PAT A1148 Werewolf - Simple Version (20 分)——暴力遍历,负负得正

    Werewolf(狼人杀) is a game in which the players are partitioned into two parties: the werewolves and th ...

  7. [Functional Programming] Write a simple version of Maybe

    Maybe has two types: Just / Nothing. Just() will just return the value that passed in. Nothing retur ...

  8. PAT 2018 秋

    A 1148 Werewolf - Simple Version 思路比较直接:模拟就行.因为需要序列号最小的两个狼人,所以以狼人为因变量进行模拟. #include <cstdio> # ...

  9. 2018.9.8pat秋季甲级考试

    第一次参加pat考试,结果很惨,只做了中间两道题,还有一个测试点错误,所以最终只得了不到50分.题目是甲级练习题的1148-1151. 考试时有些紧张,第一题第二题开始测试样例都运行不正确,但是调试程 ...

随机推荐

  1. 基于μcOS-II实时操作系统源码实现RMS和EDF调度(共享资源)

    μcOS-II多任务实验报告(RMS.EDF调度) 目录 μcOS-II多任务实验报告(RMS.EDF调度) 一.实验概述 二.环境搭建 三.代码分析 四.实验步骤 1 给TCB块添加扩展 2 创建并 ...

  2. Go语言学习之路-11-方法与接口

    目录 编程方式 go语言对象方法 自定义类型和方法 接收器: 方法作用的目标(类型和方法的绑定) go面向对象总结 方法的继承 go语言接口 为什么要用接口 接口的定义 接口的作用总结 接口的嵌套 空 ...

  3. 【Java进阶面试系列之一】哥们,你们的系统架构中为什么要引入消息中间件?

    转: [Java进阶面试系列之一]哥们,你们的系统架构中为什么要引入消息中间件? **这篇文章开始,我们把消息中间件这块高频的面试题给大家说一下,也会涵盖一些MQ中间件常见的技术问题. 这里大家可以关 ...

  4. iOS之CoreBluetooth

    思路 手机与设备间的通讯方式CoreBluetooth是比较常见且通用的.在iOS开发中需明晰以下几点 蓝牙4.0最多可联机7个设备,iPhone6以上都是蓝牙4.0 两台iPhone并不直接通过蓝牙 ...

  5. windows 下使用vargant 搭建虚拟机服务

    使用vagrant 下载 vagrant[https://www.vagrantup.com/downloads.html] 下载管理工具VirtualBox[https://www.virtualb ...

  6. 关于css垂直水平居中的几种方式

    css中元素的垂直水平居中是比较常见及较常使用的,在这里向大家介绍一下几种方式. 1.水平居中 margin: 0 auto; 效果图: 而文字的垂直水平居中也比较简单,加上line-height: ...

  7. ListView解析

    ListView通过一个Adapter来完成数据和组件的绑定.以ListActivity为例,它集成自Activity,里面包含有一个ListAdapter和一个ListView.绑定的操作通过set ...

  8. 安装JDK步骤,配置环境变量

    DK是Java语言的软件开发工具包,主要用于移动设备.嵌入式设备上的java应用程序.JDK是整个java开发的核心,它包含了JAVA的运行环境(JVM+Java系统类库)和JAVA工具.所以今天教一 ...

  9. 攻防世界 reverse babymips

    babymips   XCTF 4th-QCTF-2018 mips,ida中想要反编译的化需要安装插件,这题并不复杂直接看mips汇编也没什么难度,这里我用了ghidra,直接可以查看反编译. 1 ...

  10. Hystrix 实战经验分享

    一.背景 Hystrix是Netlifx开源的一款容错框架,防雪崩利器,具备服务降级,服务熔断,依赖隔离,监控(Hystrix Dashboard)等功能. 尽管说Hystrix官方已不再维护,且有A ...