题目意思:对两个递增链表进行归并排序

思路:没什么好说的,二路归并

 /**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
ListNode* head=new ListNode();
ListNode* p=head;
while(l1&&l2){
if(l1->val<=l2->val){
p->next=l1;
l1=l1->next;
p=p->next;
}
else{
p->next=l2;
l2=l2->next;
p=p->next;
}
}
if(l1)p->next=l1;
if(l2)p->next=l2;
return head->next; //第一个节点去掉
}
};

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