LeetCode 238
Product of Array Except Self
Given an array of n integers where n > 1, nums,
return an array output such that output[i] is equal to the product
of all the elements of nums except nums[i].
Solve it without division and in O(n).
For example, given [1,2,3,4], return [24,12,8,6].
Follow up:
Could you solve it with constant space complexity?
(Note: The output array does not count as extra space
for the purpose of space complexity analysis.)
/*************************************************************************
> File Name: LeetCode238.c
> Author: Juntaran
> Mail: Jacinthmail@gmail.com
> Created Time: 2016年04月28日 星期四 23时40分01秒
************************************************************************/ /************************************************************************* Product of Array Except Self Given an array of n integers where n > 1, nums,
return an array output such that output[i] is equal to the product
of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2,3,4], return [24,12,8,6]. Follow up:
Could you solve it with constant space complexity?
(Note: The output array does not count as extra space
for the purpose of space complexity analysis.) ************************************************************************/ #include<stdio.h> /**
* Return an array of size *returnSize.
* Note: The returned array must be malloced, assume caller calls free().
*/
int* productExceptSelf(int* nums, int numsSize, int* returnSize)
{
if( numsSize == )
{
return ;
} int *result = malloc(numsSize*sizeof(int));
*returnSize = numsSize; /* 从左往右 */
int i;
int leftProduct = ;
int rightProduct = ; for( i=; i<numsSize; i++ ){
result[i] = leftProduct;
leftProduct *= nums[i];
}
/* 从右往左 */
for( i = numsSize - ; i>=; i-- ){
result[i] *= rightProduct;
rightProduct *= nums[i];
} return result;
} int main(){ int nums[] = {,,,,,,};
int numsSize = ;
int returnSize[numsSize];
productExceptSelf( nums, numsSize, returnSize);
return ;
}
LeetCode 238的更多相关文章
- 剑指offer 66. 构建乘积数组(Leetcode 238. Product of Array Except Self)
剑指offer 66. 构建乘积数组 题目: 给定一个数组A[0, 1, ..., n-1],请构建一个数组B[0, 1, ..., n-1],其中B中的元素B[i] = A[0] * A[1] * ...
- [LeetCode] 238. Product of Array Except Self 除本身之外的数组之积
Given an array nums of n integers where n > 1, return an array output such that output[i] is equ ...
- LeetCode 238. 除自身以外数组的乘积(Product of Array Except Self)
238. 除自身以外数组的乘积 238. Product of Array Except Self 题目描述 LeetCode LeetCode238. Product of Array Except ...
- LeetCode 238. Product of Array Except Self (去除自己的数组之积)
Given an array of n integers where n > 1, nums, return an array output such that output[i] is equ ...
- LN : leetcode 238 Product of Array Except Self
lc 238 Product of Array Except Self 238 Product of Array Except Self Given an array of n integers wh ...
- Java实现 LeetCode 238 除自身以外数组的乘积
238. 除自身以外数组的乘积 给定长度为 n 的整数数组 nums,其中 n > 1,返回输出数组 output ,其中 output[i] 等于 nums 中除 nums[i] 之外其余各元 ...
- leetcode 238 Product of Array Except Self
这题看似简单,不过两个要求很有意思: 1.不准用除法:最开始我想到的做法是全部乘起来,一项项除,可是中间要是有个0,这做法死得很惨. 2.空间复杂度O(1):题目说明了返回的那个数组不算进复杂度分析里 ...
- (medium)LeetCode 238.Product of Array Except Self
Given an array of n integers where n > 1, nums, return an array output such that output[i] is equ ...
- 【LeetCode 238】Product of Array Except Self
Given an array of n integers where n > 1, nums, return an array output such that output[i] is equ ...
- Java [Leetcode 238]Product of Array Except Self
题目描述: Given an array of n integers where n > 1, nums, return an array output such that output[i] ...
随机推荐
- 7-wonders-in-java
https://code.google.com/p/7-wonders-in-java/
- 有趣的Node爬虫,数据导出成Excel
最近一直没更新了诶,因为学习Backbone好头痛,别问我为什么不继续AngularJs~因为2.0要出来了啊,妈蛋!好,言归正传,最近帮我的好基友扒数据,他说要一些股票债券的数据.我一听,那不就是要 ...
- UVA 796 - Critical Links (求桥)
Critical Links In a computer network a link L, which interconnects two servers, is considered criti ...
- JSF 2 graphicImage example
In JSF, you can use <h:graphicImage /> tag to render a HTML "img" element. For examp ...
- UVaLive 6627 First Date (转换时间)
题意:给定两个日期,两种不同算闰年的方法,导致日期不同,给定那个慢的,求你求了那个快的. 析:因为算闰年的方法不同,所以我们就要先从1582算到当前时间,算出差了多少天,再加上就好.注意跨月,跨年的情 ...
- 12 为何使用Html5+CSS3
一:大多浏览器支持,低版本也没问题 我看点这方面的资料,是为了做手机应用网站(有三个方案,这个是备用方案),可以开发响应式网站,可以脱离开发平台进行跨平台. 在Html5网页中引入Modernizr, ...
- Object类、instanceof
一.Object 1.所有类都默认继承至Object 2.两个常用的方法 2.1.toString:返回类的字符串描述,一般子类会重写用来打印属性 2.2.equals:默认比较两个对象的引用是否相同 ...
- Unity3D之Mecanim动画系统学习笔记(四):Animation State
动画的设置 我们先看看Animation Clip的一些设置: Loop time:动画是否循环播放. 下面出现了3个大致一样的选项: Root Transform Rotation:表示为播放动画的 ...
- SQL Server 数据类型映射 (ADO.NET)
SQL Server 数据类型映射 (ADO.NET) .NET Framework 3.5 更新:November 2007 SQL Server 和 .NET Framework 基于不同的类型系 ...
- Linq to SQL 绑定 ComboBox
最近学习Linq to SQL,发现Linq是一个开发轻量数据库的好东西,大大简化了数据连接.查询过程.但是在绑定ComBoBox的时间发现了一个问题:Linq查询后得到的数据tolist后,只能实现 ...