[HDOJ2874]Connections between cities(LCA, 离线tarjan)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2874
这题有不连通的情况,特别注意。
觉得是存query的姿势不对,用前向星存了一遍,还是T……
/*
━━━━━┒ギリギリ♂ eye!
┓┏┓┏┓┃キリキリ♂ mind!
┛┗┛┗┛┃\○/
┓┏┓┏┓┃ /
┛┗┛┗┛┃ノ)
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┃┃┃┃┃┃
┻┻┻┻┻┻
*/
#include <algorithm>
#include <iostream>
#include <iomanip>
#include <cstring>
#include <climits>
#include <complex>
#include <fstream>
#include <cassert>
#include <cstdio>
#include <bitset>
#include <vector>
#include <deque>
#include <queue>
#include <stack>
#include <ctime>
#include <set>
#include <map>
#include <cmath>
using namespace std;
#define fr first
#define sc second
#define cl clear
#define BUG puts("here!!!")
#define W(a) while(a--)
#define pb(a) push_back(a)
#define Rint(a) scanf("%d", &a)
#define Rll(a) scanf("%lld", &a)
#define Rs(a) scanf("%s", a)
#define Cin(a) cin >> a
#define FRead() freopen("in", "r", stdin)
#define FWrite() freopen("out", "w", stdout)
#define Rep(i, len) for(int i = 0; i < (len); i++)
#define For(i, a, len) for(int i = (a); i < (len); i++)
#define Cls(a) memset((a), 0, sizeof(a))
#define Clr(a, x) memset((a), (x), sizeof(a))
#define Full(a) memset((a), 0x7f7f, sizeof(a))
#define lp p << 1
#define rp p << 1 | 1
#define pi 3.14159265359
#define RT return
#define lowbit(x) x & (-x)
#define onenum(x) __builtin_popcount(x)
typedef long long LL;
typedef long double LD;
typedef unsigned long long ULL;
typedef pair<int, int> pii;
typedef pair<string, int> psi;
typedef map<string, int> msi;
typedef vector<int> vi;
typedef vector<LL> vl;
typedef vector<vl> vvl;
typedef vector<bool> vb; typedef struct Query {
int idx;
int u, v;
Query() {}
Query(int uu, int vv, int ii) : u(uu), v(vv), idx(ii) {}
}Query; typedef struct Edge {
int u, v, w, idx;
int next;
Edge() {}
Edge(int uu, int vv, int ww) : u(uu), v(vv), w(ww) {}
}Edge; typedef struct Ans {
int idx;
int ans;
Ans() {}
Ans(int aa, int ii) :ans(aa), idx(ii) {}
}Ans; const int maxn = ;
const int maxm = ;
int n, m, c, qcnt;
int depth[maxn];
bool vis[maxn];
int pre[maxn];
Ans ans[maxm];
Edge edge[maxn];
Edge q[maxm];
Query qq[maxm];
int qhead[maxm];
int head[maxn];
int ecnt;
int u, v, w; void adde(int u, int v, int w) {
edge[ecnt].u = u;
edge[ecnt].v = v;
edge[ecnt].w = w;
edge[ecnt].next = head[u];
head[u] = ecnt++;
} void addq(int u, int v, int i) {
q[qcnt].u = u;
q[qcnt].v = v;
q[qcnt].idx = i;
q[qcnt].next = qhead[u];
qhead[u] = ecnt++;
} int find(int x) {
return x == pre[x] ? x : pre[x] = find(pre[x]);
} void unite(int x, int y) {
x = find(x);
y = find(y);
if(x != y) pre[y] = x;
} void dfs(int u, int p, int d) {
depth[u] = d;
for(int i = head[u]; ~i; i=edge[i].next) {
int v = edge[i].v;
if(!vis[v] && v != p) {
dfs(v, u, d+edge[i].w);
unite(u, v);
}
}
vis[u] = ;
for(int i = qhead[u]; ~i; i=q[i].next) {
int uu = q[i].u;
int vv = q[i].v;
int idx = q[i].idx;
if((vis[vv] && uu == u) || (vis[uu] && vv == u)) {
ans[idx].ans = depth[vv] + depth[uu];
}
}
} bool cmp(Ans x, Ans y) {
return x.idx < y.idx;
} int ufs[maxn]; int find1(int x) {
return ufs[x] == x ? x : ufs[x] = find1(ufs[x]);
} void unite1(int x, int y) {
x = find1(x);
y = find1(y);
if(x != y) ufs[y] = x;
} inline bool scan_d(int &num) {
char in;bool IsN=false;
in=getchar();
if(in==EOF) return false;
while(in!='-'&&(in<''||in>'')) in=getchar();
if(in=='-'){ IsN=true;num=;}
else num=in-'';
while(in=getchar(),in>=''&&in<=''){
num*=,num+=in-'';
}
if(IsN) num=-num;
return true;
} int main() {
// FRead();
while(~scanf("%d%d%d",&n,&m,&c)) {
Cls(vis); Cls(depth); Cls(ans); Clr(head, -); Clr(qhead, -);
qcnt = ; Rep(i, n+) pre[i] = i, ufs[i] = i;
Rep(i, m) {
scan_d(u); scan_d(v); scan_d(w);
adde(u, v, w); adde(v, u, w);
unite1(u, v);
}
Rep(i, c) {
scan_d(u); scan_d(v);
addq(u, v, i);
qq[i] = Query(u, v, i);
}
For(i, , n+) if(!vis[i]) dfs(i, -, );
Rep(i, c) {
if(find1(qq[ans[i].idx].u) != find1(qq[ans[i].idx].v)) puts("Not connected");
else printf("%d\n", ans[i].ans);
}
}
RT ;
}
……TARJAN也T了……
/*
━━━━━┒ギリギリ♂ eye!
┓┏┓┏┓┃キリキリ♂ mind!
┛┗┛┗┛┃\○/
┓┏┓┏┓┃ /
┛┗┛┗┛┃ノ)
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┃┃┃┃┃┃
┻┻┻┻┻┻
*/
#include <algorithm>
#include <iostream>
#include <iomanip>
#include <cstring>
#include <climits>
#include <complex>
#include <fstream>
#include <cassert>
#include <cstdio>
#include <bitset>
#include <vector>
#include <deque>
#include <queue>
#include <stack>
#include <ctime>
#include <set>
#include <map>
#include <cmath>
using namespace std;
#define fr first
#define sc second
#define cl clear
#define BUG puts("here!!!")
#define W(a) while(a--)
#define pb(a) push_back(a)
#define Rint(a) scanf("%d", &a)
#define Rll(a) scanf("%lld", &a)
#define Rs(a) scanf("%s", a)
#define Cin(a) cin >> a
#define FRead() freopen("in", "r", stdin)
#define FWrite() freopen("out", "w", stdout)
#define Rep(i, len) for(int i = 0; i < (len); i++)
#define For(i, a, len) for(int i = (a); i < (len); i++)
#define Cls(a) memset((a), 0, sizeof(a))
#define Clr(a, x) memset((a), (x), sizeof(a))
#define Full(a) memset((a), 0x7f7f, sizeof(a))
#define lp p << 1
#define rp p << 1 | 1
#define pi 3.14159265359
#define RT return
#define lowbit(x) x & (-x)
#define onenum(x) __builtin_popcount(x)
typedef long long LL;
typedef long double LD;
typedef unsigned long long ULL;
typedef pair<int, int> pii;
typedef pair<string, int> psi;
typedef map<string, int> msi;
typedef vector<int> vi;
typedef vector<LL> vl;
typedef vector<vl> vvl;
typedef vector<bool> vb; typedef struct Query {
int idx;
int u, v;
Query() {}
Query(int uu, int vv, int ii) : u(uu), v(vv), idx(ii) {}
}Query; typedef struct Edge {
int u, v, w;
int next;
Edge() {}
Edge(int uu, int vv, int ww) : u(uu), v(vv), w(ww) {}
}Edge; typedef struct Ans {
int idx;
int ans;
Ans() {}
Ans(int aa, int ii) :ans(aa), idx(ii) {}
}Ans; const int maxn = ;
const int maxm = ;
int n, m, c, qcnt;
int depth[maxn];
bool vis[maxn];
int pre[maxn];
Query q[maxm];
Ans ans[maxm];
Edge edge[maxn];
int head[maxn];
int ecnt;
int u, v, w; void adde(int u, int v, int w) {
edge[ecnt].u = u;
edge[ecnt].v = v;
edge[ecnt].w = w;
edge[ecnt].next = head[u];
head[u] = ecnt++;
} int find(int x) {
return x == pre[x] ? x : pre[x] = find(pre[x]);
} void unite(int x, int y) {
x = find(x);
y = find(y);
if(x != y) pre[y] = x;
} void dfs(int u, int p, int d) {
depth[u] = d;
for(int i = head[u]; ~i; i=edge[i].next) {
int v = edge[i].v;
if(!vis[v] && v != p) {
dfs(v, u, d+edge[i].w);
unite(u, v);
}
}
vis[u] = ;
Rep(i, qcnt) {
int uu = q[i].u;
int vv = q[i].v;
int idx = q[i].idx;
if((vis[vv] && uu == u) || (vis[uu] && vv == u)) {
ans[idx].idx = idx;
ans[idx].ans = depth[vv] + depth[uu];
}
}
} bool cmp(Ans x, Ans y) {
return x.idx < y.idx;
} int ufs[maxn]; int find1(int x) {
return ufs[x] == x ? x : ufs[x] = find1(ufs[x]);
} void unite1(int x, int y) {
x = find1(x);
y = find1(y);
if(x != y) ufs[y] = x;
} inline bool scan_d(int &num) {
char in;bool IsN=false;
in=getchar();
if(in==EOF) return false;
while(in!='-'&&(in<''||in>'')) in=getchar();
if(in=='-'){ IsN=true;num=;}
else num=in-'';
while(in=getchar(),in>=''&&in<=''){
num*=,num+=in-'';
}
if(IsN) num=-num;
return true;
} int main() {
// FRead();
while(~scanf("%d%d%d",&n,&m,&c)) {
Cls(vis); Cls(depth); Cls(ans); Clr(head, -);
qcnt = ; Rep(i, n+) pre[i] = i, ufs[i] = i;
Rep(i, m) {
scan_d(u); scan_d(v); scan_d(w);
adde(u, v, w); adde(v, u, w);
unite1(u, v);
}
Rep(i, c) {
scan_d(u); scan_d(v);
q[qcnt++] = Query(u, v, i);
}
For(i, , n+) if(!vis[i]) dfs(i, -, );
Rep(i, c) {
if(find1(q[ans[i].idx].u) != find1(q[ans[i].idx].v)) puts("Not connected");
else printf("%d\n", ans[i].ans);
}
}
RT ;
}
在线胡搞T了,等下写个离线的。
TLE代码:
/*
━━━━━┒ギリギリ♂ eye!
┓┏┓┏┓┃キリキリ♂ mind!
┛┗┛┗┛┃\○/
┓┏┓┏┓┃ /
┛┗┛┗┛┃ノ)
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┛┗┛┗┛┃
┓┏┓┏┓┃
┃┃┃┃┃┃
┻┻┻┻┻┻
*/
#include <algorithm>
#include <iostream>
#include <iomanip>
#include <cstring>
#include <climits>
#include <complex>
#include <fstream>
#include <cassert>
#include <cstdio>
#include <bitset>
#include <vector>
#include <deque>
#include <queue>
#include <stack>
#include <ctime>
#include <set>
#include <map>
#include <cmath>
using namespace std;
#define fr first
#define sc second
#define cl clear
#define BUG puts("here!!!")
#define W(a) while(a--)
#define pb(a) push_back(a)
#define Rint(a) scanf("%d", &a)
#define Rll(a) scanf("%I64d", &a)
#define Rs(a) scanf("%s", a)
#define Cin(a) cin >> a
#define FRead() freopen("in", "r", stdin)
#define FWrite() freopen("out", "w", stdout)
#define Rep(i, len) for(int i = 0; i < (len); i++)
#define For(i, a, len) for(int i = (a); i < (len); i++)
#define Cls(a) memset((a), 0, sizeof(a))
#define Clr(a, x) memset((a), (x), sizeof(a))
#define Full(a) memset((a), 0x7f7f, sizeof(a))
#define pi 3.14159265359
#define RT return
#define lowbit(x) x & (-x)
#define onenum(x) __builtin_popcount(x)
typedef long long LL;
typedef long double LD;
typedef unsigned long long ULL;
typedef pair<int, int> pii;
typedef pair<string, int> psi;
typedef map<string, int> msi;
typedef vector<int> vi;
typedef vector<LL> vl;
typedef vector<vl> vvl;
typedef vector<bool> vb; typedef struct Edge {
int u, v, w;
int next;
}Edge;
const int maxn = ;
const int maxm = ;
int n, m, c;
int depth[maxn], fa[maxn];
int pre[maxn];
Edge edge[maxm];
int head[maxn];
int ecnt;
bool vis[maxn]; void adde(int u, int v, int w) {
edge[ecnt].u = u;
edge[ecnt].v = v;
edge[ecnt].w = w;
edge[ecnt].next = head[u];
head[u] = ecnt++;
} int find(int x) {
x == pre[x] ? x : pre[x] = find(pre[x]);
} void unite(int x, int y) {
x = find(x);
y = find(y);
if(x != y) pre[y] = x;
} void dfs(int u, int p, int d) {
vis[u] = ;
depth[u] = d; fa[u] = p;
for(int i = head[u]; ~i; i=edge[i].next) {
int v = edge[i].v;
int w = edge[i].w;
if(!vis[v]) dfs(v, u, d+w);
}
} int lca(int u, int v) {
int s = ;
while(depth[u] > depth[v]) {
s += depth[u];
u = pre[u];
}
while(depth[v] > depth[u]) {
s += depth[v];
v = pre[v];
}
while(u != v) {
s += (depth[u] + depth[v]);
u = pre[u];
v = pre[v];
}
return s;
} inline bool scan_d(int &num) {
char in;bool IsN=false;
in=getchar();
if(in==EOF) return false;
while(in!='-'&&(in<''||in>'')) in=getchar();
if(in=='-'){ IsN=true;num=;}
else num=in-'';
while(in=getchar(),in>=''&&in<=''){
num*=,num+=in-'';
}
if(IsN) num=-num;
return true;
} int main() {
FRead();
int u, v, w;
while(~scanf("%d%d%d",&n,&m,&c)) {
Clr(head, -); ecnt = ;
Rep(i, n+) pre[i] = i;
Rep(i, m) {
scan_d(u); scan_d(v); scan_d(w);
adde(u, v, w); adde(v, u, w);
unite(u, v);
}
For(i, , n+) {
if(!vis[i]) {
dfs(i, -, );
}
}
W(c) {
scan_d(u); scan_d(v);
if(find(u) != find(v)) puts("Not connected");
else printf("%d\n", lca(u, v));
}
}
RT ;
}
[HDOJ2874]Connections between cities(LCA, 离线tarjan)的更多相关文章
- hdu-2874 Connections between cities(lca+tarjan+并查集)
题目链接: Connections between cities Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/327 ...
- HDU 2874 Connections between cities(LCA Tarjan)
Connections between cities [题目链接]Connections between cities [题目类型]LCA Tarjan &题意: 输入一个森林,总节点不超过N ...
- hdu 2874 Connections between cities [LCA] (lca->rmq)
Connections between cities Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (J ...
- [POJ1330]Nearest Common Ancestors(LCA, 离线tarjan)
题目链接:http://poj.org/problem?id=1330 题意就是求一组最近公共祖先,昨晚学了离线tarjan,今天来实现一下. 个人感觉tarjan算法是利用了dfs序和节点深度的关系 ...
- 近期公共祖先(LCA)——离线Tarjan算法+并查集优化
一. 离线Tarjan算法 LCA问题(lowest common ancestors):在一个有根树T中.两个节点和 e&sig=3136f1d5fcf75709d9ac882bd8cfe0 ...
- LCA离线Tarjan,树上倍增入门题
离线Tarjian,来个JVxie大佬博客最近公共祖先LCA(Tarjan算法)的思考和算法实现,还有zhouzhendong大佬的LCA算法解析-Tarjan&倍增&RMQ(其实你们 ...
- Connections between cities LCA
Problem Description After World War X, a lot of cities have been seriously damaged, and we need to r ...
- HDU 2874 Connections between cities (LCA)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2874 题意是给你n个点,m条边(无向),q个询问.接下来m行,每行两个点一个边权,而且这个图不能有环路 ...
- [hdu2874]Connections between cities(LCA+并查集)
题意:n棵树,求任意两点的最短距离. 解题关键:并查集判断两点是否位于一棵树上,然后求最短距离即可.此题可以直接对全部区间直接进行st表,因为first数组会将连接的两点的区间表示出来. //#pra ...
随机推荐
- 20145120 《Java程序设计》实验一实验报告
20145120 <Java程序设计>实验一实验报告 实验名称:Java开发环境的熟悉 实验目的与要求: 1.使用JDK编译.运行简单的Java程序:(第1周学习总结) 2.编辑.编译.运 ...
- Android 开发 res里面的drawable(ldpi、mdpi、hdpi、xhdpi、xxhdpi)
(1)drawable-hdpi里面存放高分辨率的图片,如WVGA (480x800),FWVGA (480x854) (2)drawable-mdpi里面存放中等分辨率的图片,如HVGA (320x ...
- CentOS 大量的TIME_WAIT解决方法
CentOS 大量的TIME_WAIT解决方法 最近个人博客总是出现无法打开的现象,具体表现为,打开页面需要等待n长时间,登陆系统后发现系统存在大量TIME_WAIT状态的连接,google了一下解决 ...
- 【BZOJ】【2190】【SDOI2008】仪仗队
欧拉函数/莫比乌斯函数 Orz iwtwiioi 这个嘛……很明显在同一条线上的两个点一定是满足 x1*k=x2,y1*k=y2,(好吧这个表示方式有点傻逼,懂得就好了)那么这条线上的点只有第一个会 ...
- Unsupervised Learning: Use Cases
Unsupervised Learning: Use Cases Contents Visualization K-Means Clustering Transfer Learning K-Neare ...
- requireJS源码流程分析
- dom4j处理xml文件,读取xml字符串,格式化xml文件
1.xml文件 <?xml version="1.0" encoding="UTF-8"?> <employees> <emplo ...
- DataGrid行详细信息的绑定--DataGrid.RowDetailsTe(转载)
在Silverlight中的DataGrid控件使用中我们想点击其中一行并且看这一行的详细信息应该如何做呢?而且这个详细信息是多行的数据,而非简单的几个属性. 在这里我们使用DataGrid.RowD ...
- Oracle中关于数据库实例名与数据库服务名(转载)
今天同事,出现了数据库连接失败的问题,一起百度了一下,结果总算解决了,以下是一些转载过来的普及知识. 1.查询数据库名:select name,dbid from v$database;或者命令行:s ...
- 将集成spring的项目从tomcat上移植到weblogic下存在的问题
当在weblogic下部署时, 1.需要jersey-servlet-xx.jar,jersey-core-xx.jar,jersey-server-xx.jar: 2.在web.xml中全局参数co ...