Kattis - Peragrams
Peragrams
Per recently learned about palindromes. Now he wants to tell us about it and also has more awesome scientific news to share with us.
“A palindrome is a word that is the same no matter whether you read it backward or forward”, Per recently said in an interview. He continued: “For example, add is not a palindrome, because reading it backwards gives dda and it’s actually not the same thing, you see. However, if we reorder the letters of the word, we can actually get a palindrome. Hence, we say that add is a Peragram, because it is an anagram of a palindrome”.
Per gives us a more formal definition of Peragrams: “Like I said, if a word is an anagram of at least one palindrome, we call it a Peragram. And recall that an anagram of a word ww contains exactly the same letters as ww, possibly in a different order.”
Task
Given a string, find the minimum number of letters you have to remove from it, so that the string becomes a Peragram.
Input
Input consists of a string on a single line. The string will contain at least 11 and at most 10001000 characters. The string will only contain lowercase letters a-z.
Output
Output should consist of a single integer on a single line, the minimum number of characters that have to be removed from the string to make it a Peragram.
| Sample Input 1 | Sample Output 1 |
|---|---|
abc |
2 |
| Sample Input 2 | Sample Output 2 |
|---|---|
aab |
0 |
题意
问给出的字符串需要删除多少个字母后才能组成回文串
思路
相同字母个数是偶数的话才能构成回文,奇数字母只能有一个,所以只需要统计每个字母的个数,然后,答案就是个数为奇数的字母数-1
代码
#include<bits/stdc++.h>
int vis[];
char aa[];
int main() {
while (~scanf("%s", aa))
{
memset(vis, , sizeof(vis));
int len = strlen(aa);
for (int i = ; i < len; i++)
{
vis[aa[i] - 'a']++;
}
int ans = ;
for (int i = ; i < ; i++)
{
if (vis[i] % )
{
ans++;
}
}
if (ans) ans--;
printf("%d\n", ans); }
return ;
}
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