传送门

团队里的hash水题,数据小的不用hash都能过。。

也就是前缀hash,后缀hash,再比较一下就行。

——代码

 #include <cstdio>
#include <cstring>
#define ULL unsigned long long int n, m, ans;
char s1[], s2[];
ULL base[], sum1[], sum2[], bit1[], bit2[]; inline int max(int x, int y)
{
return x > y ? x : y;
} inline int min(int x, int y)
{
return x < y ? x : y;
} int main()
{
int i;
s1[] = s2[] = '';
scanf("%s %s", s1 + , s2 + );
n = strlen(s1);
m = strlen(s2);
base[] = ;
for(i = ; i < max(n, m); i++) base[i] = base[i - ] * ;
for(i = ; i < n; i++) sum1[i] = sum1[i - ] * + s1[i];
for(i = ; i < m; i++) sum2[i] = sum2[i - ] * + s2[i];
for(i = n - ; i >= ; i--) bit1[i] = bit1[i + ] + s1[i] * base[n - - i];
for(i = m - ; i >= ; i--) bit2[i] = bit2[i + ] + s2[i] * base[m - - i];
for(i = ; i < min(n, m); i++)
if(sum1[i] == bit2[m - i] || sum2[i] == bit1[n - i])
ans = i;
printf("%d\n", ans);
return ;
}

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