【Codeforces 979B】Treasure Hunt

【链接】 我是链接,点我呀:)

【题意】

每次你可以将一个字符变成一个不同于本身的字符.
每个人需要改变n次(且不能不改变)
设每个人的字符串中出现次数最多的字符出现的次数为cnt[0~2]
问你谁的cnt值最大
如果最大的两个cnt相同 输出draw

【题解】

模拟就好
注意这种情况(n=1)
1
aaa
aab
第一个人因为必须要改变一个,所以cnt最大为2
第二个人则为3

【代码】

import java.io.*;
import java.util.*;

public class Main {

    static InputReader in;
    static PrintWriter out;

    public static void main(String[] args) throws IOException{
        //InputStream ins = new FileInputStream("E:\\rush.txt");
        InputStream ins = System.in;
        in = new InputReader(ins);
        out = new PrintWriter(System.out);
        //code start from here
        new Task().solve(in, out);
        out.close();
    }

    static int N = 50000;
    static class Task{

        int n;
        String s[] = new String[3];
        int ma[] = new int[3];
        int cnt[][] = new int[3][500];
        int len;
        TreeMap dic = new TreeMap();

        public void solve(InputReader in,PrintWriter out) {
        	n = in.nextInt();
        	for (int i = 0;i < 3;i++) s[i] = in.next();
        	for (int i = 0;i < 3;i++) {
        		for (int j = 0;j < (int)s[i].length();j++) {
        			cnt[i][(int)s[i].charAt(j)]++;
        		}
        		for (int j = 'a';j <= 'z';j++)
        			ma[i] = Math.max(ma[i], cnt[i][j]);
        		for (int j = 'A';j <='Z';j++)
        			ma[i] = Math.max(ma[i], cnt[i][j]);
        		if (ma[i]==(int)s[i].length()) {
        			if (n%2==1) {
        				ma[i]--;
        			}
        		}else {
        			ma[i] = Math.min(ma[i]+n, s[i].length());
        		}
        	}
        	String s[] = {"Kuro","Shiro","Katie"};
    		if(ma[0]>ma[1]) {
    			int x = ma[0];ma[0] = ma[1];ma[1] = x;
    			String t = s[0];s[0] = s[1];s[1] = t;
    		}
    		if(ma[1]>ma[2]) {
    			int x = ma[1];ma[1] = ma[2];ma[2] = x;
    			String t = s[1];s[1] = s[2];s[2] = t;
    		}
    		if(ma[0]>ma[1]) {
    			int x = ma[0];ma[0] = ma[1];ma[1] = x;
    			String t = s[0];s[0] = s[1];s[1] = t;
    		}
    		if (ma[1]==ma[2]) {
    			out.println("Draw");
    		}else {
    			out.println(s[2]);
    		}
        }
    }

    static class InputReader{
        public BufferedReader br;
        public StringTokenizer tokenizer;

        public InputReader(InputStream ins) {
            br = new BufferedReader(new InputStreamReader(ins));
            tokenizer = null;
        }

        public String next(){
            while (tokenizer==null || !tokenizer.hasMoreTokens()) {
                try {
                tokenizer = new StringTokenizer(br.readLine());
                }catch(IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }
    }
}