Find the Clones
Time Limit: 5000MS   Memory Limit: 65536K
Total Submissions: 8490   Accepted: 3210

Description

Doubleville, a small town in Texas, was attacked by the aliens. They have abducted some of the residents and taken them to the a spaceship orbiting around earth. After some (quite unpleasant) human experiments, the aliens cloned the victims, and released multiple copies of them back in Doubleville. So now it might happen that there are 6 identical person named Hugh F. Bumblebee: the original person and its 5 copies. The Federal Bureau of Unauthorized Cloning (FBUC) charged you with the task of determining how many copies were made from each person. To help you in your task, FBUC have collected a DNA sample from each person. All copies of the same person have the same DNA sequence, and different people have different sequences (we know that there are no identical twins in the town, this is not an issue).

Input

The input contains several blocks of test cases. Each case begins with a line containing two integers: the number 1 ≤ n ≤ 20000 people, and the length 1 ≤ m ≤ 20 of the DNA sequences. The next n lines contain the DNA sequences: each line contains a sequence of m characters, where each character is either `A', `C', `G' or `T'.

The input is terminated by a block with n = m = 0 .

Output

For each test case, you have to output n lines, each line containing a single integer. The first line contains the number of different people that were not copied. The second line contains the number of people that were copied only once (i.e., there are two identical copies for each such person.) The third line contains the number of people that are present in three identical copies, and so on: the i -th line contains the number of persons that are present in i identical copies. For example, if there are 11 samples, one of them is from John Smith, and all the others are from copies of Joe Foobar, then you have to print `1' in the first andthe tenth lines, and `0' in all the other lines.

Sample Input

9 6
AAAAAA
ACACAC
GTTTTG
ACACAC
GTTTTG
ACACAC
ACACAC
TCCCCC
TCCCCC
0 0

Sample Output

1
2
0
1
0
0
0
0
0

Hint

Huge input file, 'scanf' recommended to avoid TLE. 

Source

大致题意:求1到n中有i个相同的字符串有多少种.
分析:字符串很多,直接hash或者map可能会爆掉,但是每个字符串长度很小,可以用trie,最后统计结尾标记的个数即可.
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm> using namespace std; int n, len, tot, ans[];
char s[]; struct node
{
int tr[];
int end;
void clear()
{
memset(tr, , sizeof(tr));
end = ;
}
}e[]; void insert(char *ss)
{
int u = ;
for (int i = ; i <= len; i++)
{
if (!e[u].tr[ss[i] - 'A'])
e[u].tr[ss[i] - 'A'] = ++tot;
u = e[u].tr[ss[i] - 'A'];
}
e[u].end++;
} int main()
{
while (scanf("%d%d", &n, &len) && (n || len))
{
memset(ans, , sizeof(ans));
for (int i = ; i <= tot; i++)
e[i].clear();
tot = ;
for (int i = ; i <= n; i++)
{
scanf("%s", s + );
insert(s);
}
for (int i = ; i <= tot; i++)
ans[e[i].end]++;
for (int i = ; i <= n; i++)
printf("%d\n", ans[i]);
} return ;
}

poj2945 Find the Clones的更多相关文章

  1. POJ2945 Find the Clones trie树

    建一颗$trie$树(当然你哈希也资瓷),边插边更新,看看搜到最底时有多少个字符串,然后更新. #include<cstdio> #include<iostream> #inc ...

  2. POJ2945(Find the Clones)--字典树,map

    题意:给你n个规定长度的单词,问你其中出现了1次的单词,出现两次的单词...出现n次单词分别有多少个. 当然这题map也能过,但是这里介绍字典树的做法. 首相对于n个单词存入树中,当然建树过程中遇到一 ...

  3. POJ2945:Find the Clones——题解

    http://poj.org/problem?id=2945 还是trie树……对于结束标记累加并且开个数组记录一下即可. #include<cstdio> #include<cst ...

  4. Find the Clones

    Find the Clones Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 6365   Accepted: 2375 D ...

  5. poj 2945 Find the Clones

    https://vjudge.net/problem/POJ-2945 题意: 给出n个长度相同的DNA序列,如果一个DNA序列出现过两次,那么就有说明它被复制了一次.问被复制0次,1次,2次--n- ...

  6. Apache Tomcat 9 Installation on Linux (RHEL and clones)

    Apache Tomcat 9 is not available from the standard RHEL distributions, so this article provides info ...

  7. XVII Open Cup named after E.V. Pankratiev Stage 14, Grand Prix of Tatarstan, Sunday, April 2, 2017 Problem D. Clones and Treasures

    题目:Problem D. Clones and TreasuresInput file: standard inputOutput file: standard outputTime limit: ...

  8. 【hdu2222】【poj2945】AC自动机入门题

    HDU2222 传送门 题目分析 裸题:注意构建自动机用的是模式串,思想和kmp很类似. code: #include<iostream> #include<cstdio> # ...

  9. 用链式字典树解决POJ2945

    首先,我们的思路是用链式的字典树结构,解决poj2945这道题 题意是,统计所有的字符串出现的次数,并依次输出各个次数的数量 例如: input 9 6AAAAAAACACACGTTTTGACACAC ...

随机推荐

  1. explian使用介绍

    1).id列数字越大越先执行,如果说数字一样大,那么就从上往下依次执行,id列为null的就表是这是一个结果集,不需要使用它来进行查询. 2).select_type列常见的有:A:simple:表示 ...

  2. 最新深度ghost win7系统下载

    深度技术ghost win7系统 64位快速安装版 V2016年2月,深度技术ghost win7 64位快速安装版在不影响大多数软件和硬件运行的前提下,已经尽可能关闭非必要服务,自动安装AMD/In ...

  3. COGS 615. 韩国明星

    [问题描述] 在LazyCat同学的影响下,Roby同学开始听韩国的音乐,并且越来越喜欢H.o.T,尤其喜欢安七炫和Tony,可是,爱学习爱思考的Roby同学想,如果以后喜欢的韩星越来越多怎么办呢?R ...

  4. 如何启动Intel VT-x

    如何启动Intel VT-x 5 在64bit win7系统下安装了Vmware10,然后安装64位的UbuntuKylin 14.04,想要打开UbuntuKylin,弹出如下对话框: 请问该如何启 ...

  5. iOS 随机数(Fixed)

    ios 有如下三种随机数方法: 1.    srand((unsigned)time(0));  //不加这句每次产生的随机数不变         int i = rand() % 5; 2.     ...

  6. Failed to configure a DataSource: 'url' attribute is not specified and no embedded datasource could be configured.Reason: Failed to determine a suitable driver class

    解决方案: @SpringBootApplication(exclude = DataSourceAutoConfiguration.class) 作用://取消数据库配置 但是 在用到数据库的时候记 ...

  7. 【Linux】Ubuntu18.04镜像下载,新功能介绍

    一.Ubuntu18.04镜像下载 官方下载地址:http://releases.ubuntu.com/18.04/ 官方64位iso下载地址:http://releases.ubuntu.com/1 ...

  8. nginx “403 Forbidden” 错误 解决方法

    错误的原因是缺少index.html或者index.php文件,就是配置文件中index index.html index.htm这行中的指定的文件 只需要配置时加一句  index  index.h ...

  9. ucosii(2.89)mutex 应用要点

    mutex 的创建在于共享资源打交道是可以可以保证满足互斥条件:1,必须保证继承优先级要高于可能与相应共享资源打交道的任务中优先级最高的优先级.2,不要将占有Mutex的任务挂起,也不要让占有mute ...

  10. python基础一 day11 装饰器复习

    # 复习# 讲作业# 装饰器的进阶 # functools.wraps # 带参数的装饰器 # 多个装饰器装饰同一个函数# 周末的作业 # 文件操作 # 字符串处理 # 输入输出 # 流程控制 # 装 ...