HDU 5752Sqrt Bo
Sqrt Bo
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 145 Accepted Submission(s): 72
Bo wanted to know the minimum number y which satisfies fy(n)=1.
note:f1(n)=f(n),fy(n)=f(fy−1(n))
It is a pity that Bo can only use 1 unit of time to calculate this function each time.
And Bo is impatient, he cannot stand waiting for longer than 5 units of time.
So Bo wants to know if he can solve this problem in 5 units of time.
Each test case contains a non-negative integer n(n<10100).
233333333333333333333333333333333333333333333333333333333
import java.math.*;
import java.util.*;
public class Main{ /**
* @param args
*/
public static void main(String[] args) {
Scanner cin=new Scanner(System.in);
BigDecimal n;
BigDecimal tmp=new BigDecimal("10");
BigDecimal tmpp=new BigDecimal("0");
MathContext mc = new MathContext(1000,RoundingMode.HALF_DOWN);
int ans;
while(cin.hasNext()){
ans=-1;
n=cin.nextBigDecimal();
if(n.compareTo(tmpp)==0){
System.out.println("TAT");continue;
}
for(int j=1;j<=5;j++){
BigDecimal d = new BigDecimal(Math.sqrt(n.doubleValue()),mc);
n=d;
if(n.compareTo(tmp)<0){
if(n.intValue()==1){
ans=j;break;
}
}
}
if(ans!=-1)System.out.println(ans);
else System.out.println("TAT");
}
} }
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