iOS 7的手势滑动返回
如今使用默认模板创建的iOS App都支持手势返回功能,假设导航栏的返回button是自己定义的那么则会失效,也能够參考这里手动设置无效。
- if ([self.navigationController respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
- self.navigationController.interactivePopGestureRecognizer.enabled = NO;
- }
假设是由于自己定义导航button而导致手势返回失效,那么能够在NavigationController的viewDidLoad函数中加入例如以下代码:
- - (void)viewDidLoad
- {
- [super viewDidLoad];
- // Do any additional setup after loading the view.
- __weak typeof (self) weakSelf = self;
- if ([self respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
- self.interactivePopGestureRecognizer.delegate = weakSelf;
- }
- }
这样写了以后就能够通过手势滑动返回上一层了,可是假设在push过程中触发手势滑动返回。会导致导航栏崩溃(从日志中能够看出)。针对这个问题,我们须要在pop过程禁用手势滑动返回功能:
- - (void)pushViewController:(UIViewController *)viewController animated:(BOOL)animated
- {
- // fix 'nested pop animation can result in corrupted navigation bar'
- if ([self respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
- self.interactivePopGestureRecognizer.enabled = NO;
- }
- [super pushViewController:viewController animated:animated];
- }
- - (void)navigationController:(UINavigationController *)navigationController
- didShowViewController:(UIViewController *)viewController
- animated:(BOOL)animated
- {
- if ([navigationController respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
- navigationController.interactivePopGestureRecognizer.enabled = YES;
- }
- }
除了使用系统默认的动画,还能够使用自己定义过渡动画(丰满的文档):
- - (id<UIViewControllerAnimatedTransitioning>)navigationController:(UINavigationController *)navigationController
- animationControllerForOperation:(UINavigationControllerOperation)operation
- fromViewController:(UIViewController *)fromVC
- toViewController:(UIViewController *)toVC
- {
- if (operation == UINavigationControllerOperationPop) {
- if (self.popAnimator == nil) {
- self.popAnimator = [WQPopAnimator new];
- }
- return self.popAnimator;
- }
- return nil;
- }
- - (id<UIViewControllerInteractiveTransitioning>)navigationController:(UINavigationController *)navigationController
- interactionControllerForAnimationController:(id<UIViewControllerAnimatedTransitioning>)animationController
- {
- return self.popInteractionController;
- }
- #pragma mark -
- - (void)enablePanToPopForNavigationController:(UINavigationController *)navigationController
- {
- UIScreenEdgePanGestureRecognizer *left2rightSwipe = [[UIScreenEdgePanGestureRecognizer alloc]
- initWithTarget:self
- action:@selector(didPanToPop:)];
- //[left2rightSwipe setDelegate:self];
- [left2rightSwipe setEdges:UIRectEdgeLeft];
- [navigationController.view addGestureRecognizer:left2rightSwipe];
- self.popAnimator = [WQPopAnimator new];
- self.supportPan2Pop = YES;
- }
- - (void)didPanToPop:(UIPanGestureRecognizer *)panGesture
- {
- if (!self.supportPan2Pop) return ;
- UIView *view = self.navigationController.view;
- if (panGesture.state == UIGestureRecognizerStateBegan) {
- self.popInteractionController = [UIPercentDrivenInteractiveTransition new];
- [self.navigationController popViewControllerAnimated:YES];
- } else if (panGesture.state == UIGestureRecognizerStateChanged) {
- CGPoint translation = [panGesture translationInView:view];
- CGFloat d = fabs(translation.x / CGRectGetWidth(view.bounds));
- [self.popInteractionController updateInteractiveTransition:d];
- } else if (panGesture.state == UIGestureRecognizerStateEnded) {
- if ([panGesture velocityInView:view].x > 0) {
- [self.popInteractionController finishInteractiveTransition];
- } else {
- [self.popInteractionController cancelInteractiveTransition];
- }
- self.popInteractionController = nil;
- }
- }
例如以下这个代理方法是用来提供一个非交互式的过渡动画的:
- - (id<UIViewControllerAnimatedTransitioning>)navigationController:(UINavigationController *)navigationController
- animationControllerForOperation:(UINavigationControllerOperation)operation
- fromViewController:(UIViewController *)fromVC
- toViewController:(UIViewController *)toVC
- {
- if (operation == UINavigationControllerOperationPop) {
- if (self.popAnimator == nil) {
- self.popAnimator = [WQPopAnimator new];
- }
- return self.popAnimator;
- }
- return nil;
- }
而以下这个代理方法则是提供交互式动画:
- - (id<UIViewControllerInteractiveTransitioning>)navigationController:(UINavigationController *)navigationController
- interactionControllerForAnimationController:(id<UIViewControllerAnimatedTransitioning>)animationController
- {
- return self.popInteractionController;
- }
这两个组合起来使用。首先。我们须要有个动画:
- @interface WQPopAnimator : NSObject <UIViewControllerAnimatedTransitioning>
- @end
- #import "WQPopAnimator.h"
- @implementation WQPopAnimator
- - (NSTimeInterval)transitionDuration:(id <UIViewControllerContextTransitioning>)transitionContext
- {
- return 0.4;
- }
- - (void)animateTransition:(id<UIViewControllerContextTransitioning>)transitionContext
- {
- UIViewController *toViewController = [transitionContext viewControllerForKey:UITransitionContextToViewControllerKey];
- UIViewController *fromViewController = [transitionContext viewControllerForKey:UITransitionContextFromViewControllerKey];
- [[transitionContext containerView] insertSubview:toViewController.view belowSubview:fromViewController.view];
- __block CGRect toRect = toViewController.view.frame;
- CGFloat originX = toRect.origin.x;
- toRect.origin.x -= toRect.size.width / 3;
- toViewController.view.frame = toRect;
- [UIView animateWithDuration:[self transitionDuration:transitionContext] animations:^{
- CGRect fromRect = fromViewController.view.frame;
- fromRect.origin.x += fromRect.size.width;
- fromViewController.view.frame = fromRect;
- toRect.origin.x = originX;
- toViewController.view.frame = toRect;
- } completion:^(BOOL finished) {
- [transitionContext completeTransition:![transitionContext transitionWasCancelled]];
- }];
- }
- @end
其次。交互式动画是通过
- UIPercentDrivenInteractiveTransition
来维护的。在滑动过程中依据滑动距离来进行更新:
- } else if (panGesture.state == UIGestureRecognizerStateChanged) {
- CGPoint translation = [panGesture translationInView:view];
- CGFloat d = fabs(translation.x / CGRectGetWidth(view.bounds));
- [self.popInteractionController updateInteractiveTransition:d];
当手势结束时要做出收尾动作:
- } else if (panGesture.state == UIGestureRecognizerStateEnded) {
- if ([panGesture velocityInView:view].x > 0) {
- [self.popInteractionController finishInteractiveTransition];
- } else {
- [self.popInteractionController cancelInteractiveTransition];
- }
- self.popInteractionController = nil;
- }
相同地。自己定义的动画也会有上面提到的导航栏崩溃问题。也能够通过类似的方法来解决:
- - (void)navigationController:(UINavigationController *)navigationController
- didShowViewController:(UIViewController *)viewController
- animated:(BOOL)animated
- {
- if (viewController == self.navigationController.pushingViewController) {
- self.supportPan2Pop = YES;
- self.navigationController.pushingViewController = nil;
- }
补充:位于当前navgationController的第一个([0])viewController时须要设置手势代理,不响应。
iOS 7的手势滑动返回的更多相关文章
- 再谈iOS 7的手势滑动返回功能
本文转载至 http://blog.csdn.net/jasonblog/article/details/28282147 之前随手写过一篇<使用UIScreenEdgePanGestureR ...
- 禁用ios7 手势滑动返回功能
禁用ios7 手势滑动返回功能 版权声明:本文为博主原创文章,未经博主允许不得转载. 在有的时候,我们不需要手势返回功能,那么可以在页面中添加以下代码: - (void)viewDidAppear:( ...
- Android-通过SlidingMenu高仿微信6.2最新版手势滑动返回(二)
转载请标明出处: http://blog.csdn.net/hanhailong726188/article/details/46453627 本文出自:[海龙的博客] 一.概述 在上一篇博文中,博文 ...
- Android-通过SlidingPaneLayout高仿微信6.2最新版手势滑动返回(一)
近期更新了微信版本号到6.2.发现里面有个很好的体验,就是在第二个页面Activity能手势向右滑动返回,在手势滑动的过程中能看到第一个页面,这样的体验很赞,这里高仿了一下. 这里使用的是v4包里面的 ...
- iOS之手势滑动返回功能-b
iOS中如果不自定义UINavigationBar,通过手势向右滑是可以实现返回的,这时左边的标题文字提示的是上一个ViewController的标题,如果需要把文字改为简约风格,例如弄过箭头返回啥的 ...
- iOS之手势滑动返回功能
iOS中如果不自定义UINavigationBar,通过手势向右滑是可以实现返回的,这时左边的标题文字提示的是上一个ViewController的标题,如果需要把文字改为简约风格,例如弄过箭头返回啥的 ...
- iOS 应用全部添加滑动返回
if ([self class] == [HomeViewController class]||[self class] == [ComprehensivefinanceViewControlle ...
- ios 侧边手势滑动返回 禁用/开启 功能
// 禁用 返回手势 if ([self.navigationController respondsToSelector:@selector(interactivePopGestureR ...
- iOS开发解决页面滑动返回跟scrollView左右划冲突
-(BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithG ...
随机推荐
- TCP内核参数
tcp_syn_retries :INTEGER默认值是5对于一个新建连接,内核要发送多少个 SYN 连接请求才决定放弃.不应该大于255,默认值是5,对应于180秒左右时间.(对于大负载而物理通信良 ...
- BZOJ 3518 点组计数 ——莫比乌斯反演
要求$ans=\sum_{i=1}^n \sum_{j=1}^m (n-i)(m-j)(gcd(i,j)-1)$ 可以看做枚举矩阵的大小,然后左下右上必须取的方案数. 这是斜率单增的情况 然后大力反演 ...
- 济南学习 Day 5 T1 am
炮(cannon)[题目描述]众所周知,双炮叠叠将是中国象棋中很厉害的一招必杀技.炮吃子时必须隔一个棋子跳吃,即俗称“炮打隔子”. 炮跟炮显然不能在一起打起来,于是rly一天借来了许多许多的炮在棋盘上 ...
- html-Span 指定宽度
html-Span 指定宽度 css: span{ display:-moz-inline-box; display:inline-block; width:150px; } 链接:如何设置HTML ...
- 转载自CSDN,结论:windows下按ENTER键应该是\r\n ascii码为 13 10
记得在Windows下学X86汇编语言时,用0DH(\r)和0AH(\n)来输出回车(跳到下一行的开始处).问题来了,在Windows下是 先回车再换行呢还是先换行再回车呢?在Unix系统下换行只有\ ...
- SGU101 求有重边的无向图欧拉迹
题意:好多木棒,俩端有数字(0--6)标记,按数字相同的端首尾相连成一条直线(木棒可以相同).即求有重边的无向图欧拉迹. 先判定是否为欧拉图,俩个条件,不说了.如果是欧拉图,输出路经. 方法:dfs遍 ...
- Unity 3D 之通过序列化来存档游戏数据
我们在使用u3d开发一些单机游戏的过程中,都会涉及到游戏数据的存单和加载.一般情况下,如果存储的数据不复杂,我们就可以用PlayerPrefs,但有时涉及到的数据更加复杂,使用PlayerPrefs难 ...
- Hadoop 学习 HDFS
1.HDFS的设计 HDFS是什么:HDFS即Hadoop分布式文件系统(Hadoop Distributed Filesystem),以流式数据访问模式来存储超大文件,运行于商用硬件集群上,是管理网 ...
- RED HAT 7 性能监控工具
https://access.redhat.com/documentation/zh-CN/Red_Hat_Enterprise_Linux/7/html/Performance_Tuning_Gui ...
- linxu下的shell脚本加密,shell生成二机制可执行文件
再安全的加密也抵不过逆向,斗智斗勇吧,持续加密持续破解 1.简单的加密:gzexe file.sh 2.使用shc加密:下载地址:http://www.datsi.fi.upm.es/~frosal/ ...