再谈iOS 7的手势滑动返回功能
现在使用默认模板创建的iOS App都支持手势返回功能,如果导航栏的返回按钮是自定义的那么则会失效,也可以参考这里手动设置无效。
- if ([self.navigationController respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
- self.navigationController.interactivePopGestureRecognizer.enabled = NO;
- }
如果是因为自定义导航按钮而导致手势返回失效,那么可以在NavigationController的viewDidLoad函数中添加如下代码:
- - (void)viewDidLoad
- {
- [super viewDidLoad];
- // Do any additional setup after loading the view.
- __weak typeof (self) weakSelf = self;
- if ([self respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
- self.interactivePopGestureRecognizer.delegate = weakSelf;
- }
- }
这样写了以后就可以通过手势滑动返回上一层了,但是如果在push过程中触发手势滑动返回,会导致导航栏崩溃(从日志中可以看出)。针对这个问题,我们需要在pop过程禁用手势滑动返回功能:
- - (void)pushViewController:(UIViewController *)viewController animated:(BOOL)animated
- {
- // fix 'nested pop animation can result in corrupted navigation bar'
- if ([self respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
- self.interactivePopGestureRecognizer.enabled = NO;
- }
- [super pushViewController:viewController animated:animated];
- }
- - (void)navigationController:(UINavigationController *)navigationController
- didShowViewController:(UIViewController *)viewController
- animated:(BOOL)animated
- {
- if ([navigationController respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
- navigationController.interactivePopGestureRecognizer.enabled = YES;
- }
- }
除了使用系统默认的动画,还可以使用自定义过渡动画(丰满的文档):
- - (id<UIViewControllerAnimatedTransitioning>)navigationController:(UINavigationController *)navigationController
- animationControllerForOperation:(UINavigationControllerOperation)operation
- fromViewController:(UIViewController *)fromVC
- toViewController:(UIViewController *)toVC
- {
- if (operation == UINavigationControllerOperationPop) {
- if (self.popAnimator == nil) {
- self.popAnimator = [WQPopAnimator new];
- }
- return self.popAnimator;
- }
- return nil;
- }
- - (id<UIViewControllerInteractiveTransitioning>)navigationController:(UINavigationController *)navigationController
- interactionControllerForAnimationController:(id<UIViewControllerAnimatedTransitioning>)animationController
- {
- return self.popInteractionController;
- }
- #pragma mark -
- - (void)enablePanToPopForNavigationController:(UINavigationController *)navigationController
- {
- UIScreenEdgePanGestureRecognizer *left2rightSwipe = [[UIScreenEdgePanGestureRecognizer alloc]
- initWithTarget:self
- action:@selector(didPanToPop:)];
- //[left2rightSwipe setDelegate:self];
- [left2rightSwipe setEdges:UIRectEdgeLeft];
- [navigationController.view addGestureRecognizer:left2rightSwipe];
- self.popAnimator = [WQPopAnimator new];
- self.supportPan2Pop = YES;
- }
- - (void)didPanToPop:(UIPanGestureRecognizer *)panGesture
- {
- if (!self.supportPan2Pop) return ;
- UIView *view = self.navigationController.view;
- if (panGesture.state == UIGestureRecognizerStateBegan) {
- self.popInteractionController = [UIPercentDrivenInteractiveTransition new];
- [self.navigationController popViewControllerAnimated:YES];
- } else if (panGesture.state == UIGestureRecognizerStateChanged) {
- CGPoint translation = [panGesture translationInView:view];
- CGFloat d = fabs(translation.x / CGRectGetWidth(view.bounds));
- [self.popInteractionController updateInteractiveTransition:d];
- } else if (panGesture.state == UIGestureRecognizerStateEnded) {
- if ([panGesture velocityInView:view].x > 0) {
- [self.popInteractionController finishInteractiveTransition];
- } else {
- [self.popInteractionController cancelInteractiveTransition];
- }
- self.popInteractionController = nil;
- }
- }
如下这个代理方法是用来提供一个非交互式的过渡动画的:
- - (id<UIViewControllerAnimatedTransitioning>)navigationController:(UINavigationController *)navigationController
- animationControllerForOperation:(UINavigationControllerOperation)operation
- fromViewController:(UIViewController *)fromVC
- toViewController:(UIViewController *)toVC
- {
- if (operation == UINavigationControllerOperationPop) {
- if (self.popAnimator == nil) {
- self.popAnimator = [WQPopAnimator new];
- }
- return self.popAnimator;
- }
- return nil;
- }
而下面这个代理方法则是提供交互式动画:
- - (id<UIViewControllerInteractiveTransitioning>)navigationController:(UINavigationController *)navigationController
- interactionControllerForAnimationController:(id<UIViewControllerAnimatedTransitioning>)animationController
- {
- return self.popInteractionController;
- }
这两个组合起来使用。首先,我们需要有个动画:
- @interface WQPopAnimator : NSObject <UIViewControllerAnimatedTransitioning>
- @end
- #import "WQPopAnimator.h"
- @implementation WQPopAnimator
- - (NSTimeInterval)transitionDuration:(id <UIViewControllerContextTransitioning>)transitionContext
- {
- return 0.4;
- }
- - (void)animateTransition:(id<UIViewControllerContextTransitioning>)transitionContext
- {
- UIViewController *toViewController = [transitionContext viewControllerForKey:UITransitionContextToViewControllerKey];
- UIViewController *fromViewController = [transitionContext viewControllerForKey:UITransitionContextFromViewControllerKey];
- [[transitionContext containerView] insertSubview:toViewController.view belowSubview:fromViewController.view];
- __block CGRect toRect = toViewController.view.frame;
- CGFloat originX = toRect.origin.x;
- toRect.origin.x -= toRect.size.width / 3;
- toViewController.view.frame = toRect;
- [UIView animateWithDuration:[self transitionDuration:transitionContext] animations:^{
- CGRect fromRect = fromViewController.view.frame;
- fromRect.origin.x += fromRect.size.width;
- fromViewController.view.frame = fromRect;
- toRect.origin.x = originX;
- toViewController.view.frame = toRect;
- } completion:^(BOOL finished) {
- [transitionContext completeTransition:![transitionContext transitionWasCancelled]];
- }];
- }
- @end
其次,交互式动画是通过
- UIPercentDrivenInteractiveTransition
来维护的,在滑动过程中根据滑动距离来进行更新:
- } else if (panGesture.state == UIGestureRecognizerStateChanged) {
- CGPoint translation = [panGesture translationInView:view];
- CGFloat d = fabs(translation.x / CGRectGetWidth(view.bounds));
- [self.popInteractionController updateInteractiveTransition:d];
当手势结束时要做出收尾动作:
- } else if (panGesture.state == UIGestureRecognizerStateEnded) {
- if ([panGesture velocityInView:view].x > 0) {
- [self.popInteractionController finishInteractiveTransition];
- } else {
- [self.popInteractionController cancelInteractiveTransition];
- }
- self.popInteractionController = nil;
- }
同样地,自定义的动画也会有上面提到的导航栏崩溃问题,也可以通过类似的方法来解决:
- - (void)navigationController:(UINavigationController *)navigationController
- didShowViewController:(UIViewController *)viewController
- animated:(BOOL)animated
- {
- if (viewController == self.navigationController.pushingViewController) {
- self.supportPan2Pop = YES;
- self.navigationController.pushingViewController = nil;
- }
补充:位于当前navgationController的第一个([0])viewController时需要设置手势代理,不响应。
再谈iOS 7的手势滑动返回功能的更多相关文章
- iOS 7的手势滑动返回
如今使用默认模板创建的iOS App都支持手势返回功能,假设导航栏的返回button是自己定义的那么则会失效,也能够參考这里手动设置无效. if ([self.navigationController ...
- 禁用ios7 手势滑动返回功能
禁用ios7 手势滑动返回功能 版权声明:本文为博主原创文章,未经博主允许不得转载. 在有的时候,我们不需要手势返回功能,那么可以在页面中添加以下代码: - (void)viewDidAppear:( ...
- iOS之手势滑动返回功能-b
iOS中如果不自定义UINavigationBar,通过手势向右滑是可以实现返回的,这时左边的标题文字提示的是上一个ViewController的标题,如果需要把文字改为简约风格,例如弄过箭头返回啥的 ...
- iOS之手势滑动返回功能
iOS中如果不自定义UINavigationBar,通过手势向右滑是可以实现返回的,这时左边的标题文字提示的是上一个ViewController的标题,如果需要把文字改为简约风格,例如弄过箭头返回啥的 ...
- iOS 应用全部添加滑动返回
if ([self class] == [HomeViewController class]||[self class] == [ComprehensivefinanceViewControlle ...
- Android-通过SlidingMenu高仿微信6.2最新版手势滑动返回(二)
转载请标明出处: http://blog.csdn.net/hanhailong726188/article/details/46453627 本文出自:[海龙的博客] 一.概述 在上一篇博文中,博文 ...
- Android-通过SlidingPaneLayout高仿微信6.2最新版手势滑动返回(一)
近期更新了微信版本号到6.2.发现里面有个很好的体验,就是在第二个页面Activity能手势向右滑动返回,在手势滑动的过程中能看到第一个页面,这样的体验很赞,这里高仿了一下. 这里使用的是v4包里面的 ...
- iOS彩票项目--第五天,新特性引导页的封装、返回按钮的自定义、导航控制器的滑动返回以及自定义滑动返回功能
一.上次实现了在AppDelegate中通过判断app版本决定是否进入新特性页面,今天将AppDelegate中的一坨进行了封装.将self.window的根控制器到底应该为新特性界面,还是主页面,封 ...
- UINavigationController实现全屏滑动返回功能
说明: UINavigationController默认在push出的控制器中都有边沿滑动返回功能,但是只能从屏幕左边滑才能返回,若从屏幕中间画并没有效果.下面实现全屏滑动功能. 探究: 系统默认能够 ...
随机推荐
- javascript 将内容复制到剪贴板
javascript 将内容复制到剪贴板 CreateTime--2017年9月19日11:36:50 Author:Marydon js 操作剪贴板 1.设置剪贴板内容 UpdateTime-- ...
- ubuntu卸载第三方库
下面以pcl和opencv为例进行说明. 参考资料: https://www.cnblogs.com/txg198955/p/5990295.html ubuntu卸载opencv并重装opencv ...
- Keepalived+nginx+redis主从+tomcat一机多实例实现会话共享
Keepalived+nginx+redis主从+tomcat一机多实例实现会话共享 2014-09-09 14:14:25 标签:会话共享 主从 原创作品,允许转载,转载时请务必以超链接形式标明文章 ...
- jq的form验证
jQuery(document).ready(function(){ $('#cform img.contact-loader').hide(); $('#cform').submit(functio ...
- java基础讲解09-----接口,继承,多态
还有什么包装类,数字类,这些简单的我就不想过去介绍,前面也大概的介绍了下,继承,多态 1.类的继承 继承的思想:基于某个父类的扩展,制定一个新的子类.子类可以继承父类原有的属性,方法,也可以重写父类的 ...
- asp.net生成视图时报错 未引用System.Runtime, Version...
这是没有添加程序集引用 在程序集中添加一条引用 <compilation debug="true" targetFramework="4.5.1"> ...
- C#面试基础问题0
传入某个属性的set方法的隐含参数的名称是什么?value,它的类型和属性所声名的类型相同. 如何在C#中实现继承?在类名后加上一个冒号,再加上基类的名称. C#支持多重继承么?不支持.可以用接口来实 ...
- ajax实现json循环输出结果
$.post("bankInfo.php",{key:jee_server,uid:jee_uid},function(data) { var strs=JSON.stringif ...
- unity, 不要用TextMesh,用图片代替
<方块鸭快跑>(见:http://www.cnblogs.com/wantnon/p/4596222.html)1.0版本开始界面中鸭子的speech bubble中的文字用的是TextM ...
- size_t详细解释
在学习sizeof运算符的时候,它的值类型为size_t,结果在使用printf函数显示的时候,凭空多了很多警告,有点不不理解,为啥搞这么复杂?直接用个int类型多省事? 经过一番搜索和阅读文档,找到 ...