iOS 7的手势滑动返回
如今使用默认模板创建的iOS App都支持手势返回功能,假设导航栏的返回button是自己定义的那么则会失效,也能够參考这里手动设置无效。
- if ([self.navigationController respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
- self.navigationController.interactivePopGestureRecognizer.enabled = NO;
- }
假设是由于自己定义导航button而导致手势返回失效,那么能够在NavigationController的viewDidLoad函数中加入例如以下代码:
- - (void)viewDidLoad
- {
- [super viewDidLoad];
- // Do any additional setup after loading the view.
- __weak typeof (self) weakSelf = self;
- if ([self respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
- self.interactivePopGestureRecognizer.delegate = weakSelf;
- }
- }
这样写了以后就能够通过手势滑动返回上一层了,可是假设在push过程中触发手势滑动返回。会导致导航栏崩溃(从日志中能够看出)。针对这个问题,我们须要在pop过程禁用手势滑动返回功能:
- - (void)pushViewController:(UIViewController *)viewController animated:(BOOL)animated
- {
- // fix 'nested pop animation can result in corrupted navigation bar'
- if ([self respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
- self.interactivePopGestureRecognizer.enabled = NO;
- }
- [super pushViewController:viewController animated:animated];
- }
- - (void)navigationController:(UINavigationController *)navigationController
- didShowViewController:(UIViewController *)viewController
- animated:(BOOL)animated
- {
- if ([navigationController respondsToSelector:@selector(interactivePopGestureRecognizer)]) {
- navigationController.interactivePopGestureRecognizer.enabled = YES;
- }
- }
除了使用系统默认的动画,还能够使用自己定义过渡动画(丰满的文档):
- - (id<UIViewControllerAnimatedTransitioning>)navigationController:(UINavigationController *)navigationController
- animationControllerForOperation:(UINavigationControllerOperation)operation
- fromViewController:(UIViewController *)fromVC
- toViewController:(UIViewController *)toVC
- {
- if (operation == UINavigationControllerOperationPop) {
- if (self.popAnimator == nil) {
- self.popAnimator = [WQPopAnimator new];
- }
- return self.popAnimator;
- }
- return nil;
- }
- - (id<UIViewControllerInteractiveTransitioning>)navigationController:(UINavigationController *)navigationController
- interactionControllerForAnimationController:(id<UIViewControllerAnimatedTransitioning>)animationController
- {
- return self.popInteractionController;
- }
- #pragma mark -
- - (void)enablePanToPopForNavigationController:(UINavigationController *)navigationController
- {
- UIScreenEdgePanGestureRecognizer *left2rightSwipe = [[UIScreenEdgePanGestureRecognizer alloc]
- initWithTarget:self
- action:@selector(didPanToPop:)];
- //[left2rightSwipe setDelegate:self];
- [left2rightSwipe setEdges:UIRectEdgeLeft];
- [navigationController.view addGestureRecognizer:left2rightSwipe];
- self.popAnimator = [WQPopAnimator new];
- self.supportPan2Pop = YES;
- }
- - (void)didPanToPop:(UIPanGestureRecognizer *)panGesture
- {
- if (!self.supportPan2Pop) return ;
- UIView *view = self.navigationController.view;
- if (panGesture.state == UIGestureRecognizerStateBegan) {
- self.popInteractionController = [UIPercentDrivenInteractiveTransition new];
- [self.navigationController popViewControllerAnimated:YES];
- } else if (panGesture.state == UIGestureRecognizerStateChanged) {
- CGPoint translation = [panGesture translationInView:view];
- CGFloat d = fabs(translation.x / CGRectGetWidth(view.bounds));
- [self.popInteractionController updateInteractiveTransition:d];
- } else if (panGesture.state == UIGestureRecognizerStateEnded) {
- if ([panGesture velocityInView:view].x > 0) {
- [self.popInteractionController finishInteractiveTransition];
- } else {
- [self.popInteractionController cancelInteractiveTransition];
- }
- self.popInteractionController = nil;
- }
- }
例如以下这个代理方法是用来提供一个非交互式的过渡动画的:
- - (id<UIViewControllerAnimatedTransitioning>)navigationController:(UINavigationController *)navigationController
- animationControllerForOperation:(UINavigationControllerOperation)operation
- fromViewController:(UIViewController *)fromVC
- toViewController:(UIViewController *)toVC
- {
- if (operation == UINavigationControllerOperationPop) {
- if (self.popAnimator == nil) {
- self.popAnimator = [WQPopAnimator new];
- }
- return self.popAnimator;
- }
- return nil;
- }
而以下这个代理方法则是提供交互式动画:
- - (id<UIViewControllerInteractiveTransitioning>)navigationController:(UINavigationController *)navigationController
- interactionControllerForAnimationController:(id<UIViewControllerAnimatedTransitioning>)animationController
- {
- return self.popInteractionController;
- }
这两个组合起来使用。首先。我们须要有个动画:
- @interface WQPopAnimator : NSObject <UIViewControllerAnimatedTransitioning>
- @end
- #import "WQPopAnimator.h"
- @implementation WQPopAnimator
- - (NSTimeInterval)transitionDuration:(id <UIViewControllerContextTransitioning>)transitionContext
- {
- return 0.4;
- }
- - (void)animateTransition:(id<UIViewControllerContextTransitioning>)transitionContext
- {
- UIViewController *toViewController = [transitionContext viewControllerForKey:UITransitionContextToViewControllerKey];
- UIViewController *fromViewController = [transitionContext viewControllerForKey:UITransitionContextFromViewControllerKey];
- [[transitionContext containerView] insertSubview:toViewController.view belowSubview:fromViewController.view];
- __block CGRect toRect = toViewController.view.frame;
- CGFloat originX = toRect.origin.x;
- toRect.origin.x -= toRect.size.width / 3;
- toViewController.view.frame = toRect;
- [UIView animateWithDuration:[self transitionDuration:transitionContext] animations:^{
- CGRect fromRect = fromViewController.view.frame;
- fromRect.origin.x += fromRect.size.width;
- fromViewController.view.frame = fromRect;
- toRect.origin.x = originX;
- toViewController.view.frame = toRect;
- } completion:^(BOOL finished) {
- [transitionContext completeTransition:![transitionContext transitionWasCancelled]];
- }];
- }
- @end
其次。交互式动画是通过
- UIPercentDrivenInteractiveTransition
来维护的。在滑动过程中依据滑动距离来进行更新:
- } else if (panGesture.state == UIGestureRecognizerStateChanged) {
- CGPoint translation = [panGesture translationInView:view];
- CGFloat d = fabs(translation.x / CGRectGetWidth(view.bounds));
- [self.popInteractionController updateInteractiveTransition:d];
当手势结束时要做出收尾动作:
- } else if (panGesture.state == UIGestureRecognizerStateEnded) {
- if ([panGesture velocityInView:view].x > 0) {
- [self.popInteractionController finishInteractiveTransition];
- } else {
- [self.popInteractionController cancelInteractiveTransition];
- }
- self.popInteractionController = nil;
- }
相同地。自己定义的动画也会有上面提到的导航栏崩溃问题。也能够通过类似的方法来解决:
- - (void)navigationController:(UINavigationController *)navigationController
- didShowViewController:(UIViewController *)viewController
- animated:(BOOL)animated
- {
- if (viewController == self.navigationController.pushingViewController) {
- self.supportPan2Pop = YES;
- self.navigationController.pushingViewController = nil;
- }
补充:位于当前navgationController的第一个([0])viewController时须要设置手势代理,不响应。
iOS 7的手势滑动返回的更多相关文章
- 再谈iOS 7的手势滑动返回功能
本文转载至 http://blog.csdn.net/jasonblog/article/details/28282147 之前随手写过一篇<使用UIScreenEdgePanGestureR ...
- 禁用ios7 手势滑动返回功能
禁用ios7 手势滑动返回功能 版权声明:本文为博主原创文章,未经博主允许不得转载. 在有的时候,我们不需要手势返回功能,那么可以在页面中添加以下代码: - (void)viewDidAppear:( ...
- Android-通过SlidingMenu高仿微信6.2最新版手势滑动返回(二)
转载请标明出处: http://blog.csdn.net/hanhailong726188/article/details/46453627 本文出自:[海龙的博客] 一.概述 在上一篇博文中,博文 ...
- Android-通过SlidingPaneLayout高仿微信6.2最新版手势滑动返回(一)
近期更新了微信版本号到6.2.发现里面有个很好的体验,就是在第二个页面Activity能手势向右滑动返回,在手势滑动的过程中能看到第一个页面,这样的体验很赞,这里高仿了一下. 这里使用的是v4包里面的 ...
- iOS之手势滑动返回功能-b
iOS中如果不自定义UINavigationBar,通过手势向右滑是可以实现返回的,这时左边的标题文字提示的是上一个ViewController的标题,如果需要把文字改为简约风格,例如弄过箭头返回啥的 ...
- iOS之手势滑动返回功能
iOS中如果不自定义UINavigationBar,通过手势向右滑是可以实现返回的,这时左边的标题文字提示的是上一个ViewController的标题,如果需要把文字改为简约风格,例如弄过箭头返回啥的 ...
- iOS 应用全部添加滑动返回
if ([self class] == [HomeViewController class]||[self class] == [ComprehensivefinanceViewControlle ...
- ios 侧边手势滑动返回 禁用/开启 功能
// 禁用 返回手势 if ([self.navigationController respondsToSelector:@selector(interactivePopGestureR ...
- iOS开发解决页面滑动返回跟scrollView左右划冲突
-(BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithG ...
随机推荐
- git删除本地所有的更改
删除本地所有为暂存的修改: git checkout -f 如果有修改以及加入暂存区的话 那么 使用如下命令: git reset --hard git clean -xdf
- UVA - 10591 Happy Number
Happy Number UVA - 10591 Let the sum of the square of the digits of a positive integer S0 be represe ...
- POJ-3481 Double Queue,Treap树和set花式水过!
Double Queue 本打算学二叉树,单纯的二叉树感觉也就那几种遍历了, 无意中看到了这个题,然后就 ...
- BZOJ 2882 工艺 ——后缀自动机 最小表示法
先说后缀自动机的做法. 直接把S串复制一遍成SS,然后建立后缀自动机,go边相当于在当前字符的后面插入,而son边可以看作在字符串前面加一个字符. 所以贪心的走字典序最小的边即可,而且根据后缀自动机的 ...
- NOI2015 荷马史诗 【k-哈夫曼树】
题目 追逐影子的人,自己就是影子 --荷马 Allison 最近迷上了文学.她喜欢在一个慵懒的午后,细细地品上一杯卡布奇诺,静静地阅读她爱不释手的<荷马史诗>.但是由<奥德赛> ...
- 刷题总结——拦截导弹(ssoj)
题目: 题目背景 NOIP1999 提高组试题 题目描述 某国为了防御敌国的导弹袭击,发展出一种导弹拦截系统.但是这种导弹拦截系统有一个缺陷:虽然它的第一发炮弹能够到达任意的高度,但是以后每一发炮弹都 ...
- hdu 2713
#include<stdio.h> #include<string.h> int map[151000][2]; int max(int a,int b) { return ...
- 【前端学习笔记】2015-09-11~~~~ js中ajax请求返回案例
<body><textarea id='a' rows=100 cols=300>result:</textarea>><script>var a ...
- 对Netflix Ribbon的Loadbalancer类源码设计合理性的一点质疑
首先,这只是我个人的一点质疑,可能是因为我自己菜没有领悟到作者的意思,也正因此,想发出来跟大家一起探讨. 在昨晚,我因为在编写自己的开源项目的负载均衡模块(这是我开源项目的介绍:https://www ...
- 理解 virbr0
virbr0 是 KVM 默认创建的一个 Bridge,其作用是为连接其上的虚机网卡提供 NAT 访问外网的功能. virbr0 默认分配了一个IP 192.168.122.1,并为连接其上的其他虚拟 ...