#include <iostream>
#include <string.h>
using namespace std; template <class T>
class Heap {
public:
Heap():n(), capacity() {
this->arr = new T[capacity];
} ~Heap() {
delete[] arr;
} void insert(T v) {
if (n >= capacity) {
T* tmp = new T[capacity << ];
memcpy(tmp, arr, sizeof(T) * capacity);
capacity <<= ;
}
arr[n++] = v;
shiftUp(n - );
} void del(int index) {
if (index < || index >= n) return;
swap(arr[index], arr[n - ]);
shiftDown(index, --n);
} void shiftDown(int st, int ed) {
T tmp = arr[st];
while (st < ed) {
int next = -;
int left = st * + ; // left child node
if (left < ed) next = left;
else break;
int right = st * + ;
if (right < ed && arr[right] < arr[next]) next = right;
if (arr[next] < arr[st]) {
arr[st] = arr[next];
st = next;
} else break;
}
arr[st] = tmp;
} void shiftUp(int ed) {
T tmp = arr[ed];
while (ed > ) {
int parent = (ed - ) / ;
if (arr[ed] < arr[parent]) {
arr[ed] = arr[parent];
ed = parent;
} else break;
}
arr[ed] = tmp;
} void sort() {
for (int j = n - ; j >= ; --j) {
swap(arr[], arr[j]);
shiftDown(, j); // here should be j
}
} void print() const {
for (int i = ; i < n; ++i) {
cout << arr[i] << " ";
}
cout << endl;
} T get(int pos) {
return arr[pos];
} void update(int pos, int v) {
if (pos < || pos >= n) return;
if (arr[pos] < v) {
arr[pos] = v;
shiftDown(pos, n);
} else {
shiftUp(pos);
}
}
void increase(int pos, int v) {
if (pos < || pos >= n) return;
arr[pos] = arr[pos] + v;
shiftDown(pos, n);
} void decrease(int pos, int v) {
if (pos < || pos >= n) return;
arr[pos] = arr[pos] - v;
shiftUp(pos);
} bool empty() const {
return n <= ;
} void pop() {
if (empty()) return;
del();
} T top() {
if (empty()) return;
return arr[];
} private:
T* arr;
int n;
int capacity;
}; int main()
{
int arr[] = {, ,,,,};
Heap<int> heap;
for (int i = ; i < ; ++i) {
heap.insert(arr[i]);
}
//heap.sort();
heap.print();
heap.del();
heap.print();
heap.increase(, );
heap.print();
return ;
}

data structure | heap的更多相关文章

  1. [Algorithm] Heap data structure and heap sort algorithm

    Source, git Heap is a data structure that can fundamentally change the performance of fairly common ...

  2. Leetcode: All O`one Data Structure

    Implement a data structure supporting the following operations: Inc(Key) - Inserts a new key with va ...

  3. CDOJ 483 Data Structure Problem DFS

    Data Structure Problem Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.uestc.edu.cn/#/proble ...

  4. [转]Data Structure Recovery using PIN and PyGraphviz

    Source:http://v0ids3curity.blogspot.com/2015/04/data-structure-recovery-using-pin-and.html --------- ...

  5. [LeetCode] All O`one Data Structure 全O(1)的数据结构

    Implement a data structure supporting the following operations: Inc(Key) - Inserts a new key with va ...

  6. [LeetCode] Add and Search Word - Data structure design 添加和查找单词-数据结构设计

    Design a data structure that supports the following two operations: void addWord(word) bool search(w ...

  7. [LeetCode] Two Sum III - Data structure design 两数之和之三 - 数据结构设计

    Design and implement a TwoSum class. It should support the following operations:add and find. add - ...

  8. Finger Trees: A Simple General-purpose Data Structure

    http://staff.city.ac.uk/~ross/papers/FingerTree.html Summary We present 2-3 finger trees, a function ...

  9. Mesh Data Structure in OpenCascade

    Mesh Data Structure in OpenCascade eryar@163.com 摘要Abstract:本文对网格数据结构作简要介绍,并结合使用OpenCascade中的数据结构,将网 ...

随机推荐

  1. AJAX,JSON用户名校验

    效果 开发结构 1,src部分有两个包dao和servlet 1.1dao包下有两个数据库工具类文件 SqlHelper.java package org.guangsoft.dao; import ...

  2. openGL纹理映射参数解析

    GLuinttexture[1]; AUX_RGBImageRec *TextureImage[1]; Status=TRUE; // Set The Status To TRUE glGenText ...

  3. 失恋28天-缝补礼物(codevs 2503)

    2503 失恋28天-缝补礼物  时间限制: 1 s  空间限制: 32000 KB  题目等级 : 黄金 Gold 题解  查看运行结果     题目描述 Description 话说上回他给女孩送 ...

  4. Quartus signal tapii 的使用

    此功能原来已经试验过,没有笔记.这次复习巩固下. 使用PLL 的程序. 1.新建signaltap ii 文件 注意以下几个地方,会用到 添加采样时钟 . 添加采样信号: 完成之后,编译下载 运行 两 ...

  5. 禅道bug安装报错

    [root@lnmp src]# grep "session.save" /etc/php.ini ; http://php.net/session.save-handler se ...

  6. Java Hour 40 Maven ( 2 )

    有句名言,叫做10000小时成为某一个领域的专家.姑且不辩论这句话是否正确,让我们到达10000小时的时候再回头来看吧. Hour 40 Maven 坐标 任何一个包都需要一个全世界唯一的id, Ma ...

  7. hdu 4003 树形dp+分组背包 2011大连赛区网络赛C

    题意:求K个机器人从同一点出发,遍历所有点所需的最小花费 链接:点我 Sample Input 3 1 1 //3个点,从1出发,1个机器人 1 2 1 1 3 1 3 1 2 1 2 1 1 3 1 ...

  8. 错误解决error while loading shared libraries: libXXX.so.X: cannot open shared object file: No such file

    转自:http://blog.csdn.net/david_xtd/article/details/7625626 前提:ubuntu-debug机器上向SVN提交了pdu-IVT,想在别的普通机器上 ...

  9. 【Android】SlidingMenu属性详解(转)

    原文:http://my.eoe.cn/1169143/archive/21892.html SlidingMenu简介:SlidingMenu的是一种比较新的设置界面或配置界面效果,在主界面左滑或者 ...

  10. Windbg 双机代码同步调试设置

    Windbg的设置 Windbg的设置 Windbg本身可以直接从微软的网站上下载下载地址:http://www.microsoft.com/whdc/devtools/debugging/defau ...