POJ2828 Buy Tickets
题意:依次给出n个插队的情况——k,name。即标号为name的这个人插到k后,且这个过程有时间顺序。
思路:很容易想到从后往前插,也很容易想到用线段树维护个数,但是某些细节wa了很多次,代码和网上的代码似乎都大同小异——但是还是有问题….
~~自己稍微口胡了一些想法= =~~好吧纯属扯淡
挖个坑挖个坑,虽然也不打算填了> <。
POJ2828 Buy Tickets的更多相关文章
- [POJ2828] Buy Tickets(待续)
[POJ2828] Buy Tickets(待续) 题目大意:多组测试,每组给出\(n\)条信息\((a,b)\),表示\(b\)前面有\(a\)个人,顺序靠后的信息优先级高 Solution.1 由 ...
- POJ2828 Buy Tickets[树状数组第k小值 倒序]
Buy Tickets Time Limit: 4000MS Memory Limit: 65536K Total Submissions: 19012 Accepted: 9442 Desc ...
- poj-----(2828)Buy Tickets(线段树单点更新)
Buy Tickets Time Limit: 4000MS Memory Limit: 65536K Total Submissions: 12930 Accepted: 6412 Desc ...
- POJ2828 Buy Tickets 【线段树】+【单点更新】+【逆序】
Buy Tickets Time Limit: 4000MS Memory Limit: 65536K Total Submissions: 12296 Accepted: 6071 Desc ...
- poj2828 Buy Tickets (线段树 插队问题)
Buy Tickets Time Limit: 4000MS Memory Limit: 65536K Total Submissions: 22097 Accepted: 10834 Des ...
- poj-2828 Buy Tickets(经典线段树)
/* Buy Tickets Time Limit: 4000MS Memory Limit: 65536K Total Submissions: 10207 Accepted: 4919 Descr ...
- POJ2828 Buy Tickets [树状数组,二分答案]
题目传送门 Buy Tickets Time Limit: 4000MS Memory Limit: 65536K Total Submissions: 22611 Accepted: 110 ...
- POJ2828 Buy Tickets 树状数组
Description Railway tickets were difficult to buy around the Lunar New Year in China, so we must get ...
- poj-2828 Buy Tickets(线段树,排队问题,逆向思维)
题目地址:POJ 2828 Buy Tickets Description Railway tickets were difficult to buy around the Lunar New Yea ...
- [poj2828] Buy Tickets (线段树)
线段树 Description Railway tickets were difficult to buy around the Lunar New Year in China, so we must ...
随机推荐
- 序列GCD和问题(题目)
序列GCD和 题目描述 Massacc有一个序列$A_1,A_2,A_3,\dots ,A_n$. Popbab说:我要知道这个序列的和$\pmod{1\times10^9+7}$. Massacc在 ...
- linux shell 字符串操作详解 (长度,读取,替换,截取,连接,对比,删除,位置 )
在做shell批处理程序时候,经常会涉及到字符串相关操作.有很多命令语句,如:awk,sed都可以做字符串各种操作. 其实shell内置一系列操作符号,可以达到类似效果,大家知道,使用内部操作符会省略 ...
- Android Debugging
Debugging methods for Android Contents [hide] 1 Debuggers 1.1 Kernel and User co-debug with GDB on ...
- Unique Binary Search Trees I & II
Given n, how many structurally unique BSTs (binary search trees) that store values 1...n? Example Gi ...
- Android app主线程UI更新间歇性崩溃的问题
对App进行开发测试时,偶尔出现app崩溃的问题.日志如下: 10-25 18:44:52.935 15290-15290/com.zzq.cnblogs E/AndroidRuntime﹕ FATA ...
- Java入门学习知识点汇总
Java入门重要知识点在这里总结一下,以方便日后复习,这部分内容主要有:变量和常量,常用的运算符,流程控制语句,数组,方法这些内容 一.变量和常量 1.Java关键字 先贴张图: 所有关键字区分大小写 ...
- 利用runTime,实现以模型为主的字典转模型(注意与KVC的区别)
将字典转化为模型,面向模型开发,是在开发中最为常用的功能.利用KVC可以将字典转换为模型,但是前提有三个约束,一个是必须保证模型的属性个数大于等于字典个数,二是属性名称与字典的key必须相同,三是对于 ...
- C++语法 初始化列表 数组引用
只能在初始化列表initilizationlist中初始化的有: 1.const修饰的数据成员或者reference参考 2.基类的构造函数 注意,数组不能引用,亦即以下代码是不对的 void fun ...
- Controller与View之间的数据传递
1)Controller向View传递数据ViewData["message"] = "Hello";//使用ViewData传递数据ViewBag.Time ...
- Android 如何让EditText不自动获取焦点
解决之道:在EditText的父级控件中找一个,设置成 android:focusable="true" android:focusableInTouchMode=&quo ...