A. Robot Sequence
2 seconds
256 megabytes
standard input
standard output
Calvin the robot lies in an infinite rectangular grid. Calvin's source code contains a list of n commands, each either 'U', 'R', 'D', or 'L' — instructions to move a single square up, right, down, or left, respectively. How many ways can Calvin execute a non-empty contiguous substrings of commands and return to the same square he starts in? Two substrings are considered different if they have different starting or ending indices.
The first line of the input contains a single positive integer, n (1 ≤ n ≤ 200) — the number of commands.
The next line contains n characters, each either 'U', 'R', 'D', or 'L' — Calvin's source code.
Print a single integer — the number of contiguous substrings that Calvin can execute and return to his starting square.
6
URLLDR
2
4
DLUU
0
7
RLRLRLR
12
In the first case, the entire source code works, as well as the "RL" substring in the second and third characters.
Note that, in the third case, the substring "LR" appears three times, and is therefore counted three times to the total result.
#include<bits/stdc++.h>
using namespace std;
int ud[202];
int rl[202];
int main()
{
int n;
char a; scanf("%d",&n);getchar();
for(int i=0;i<n;i++)
{
scanf("%c",&a);
if(a=='U') ud[i]=1;
else if(a=='D') ud[i]=-1;
else if(a=='R') rl[i]=1;
else rl[i]=-1; }
int ans=0;
int cntud=0;
int cntrl=0;
for(int i=0;i<n;i++)
{
cntud=ud[i];
cntrl=rl[i];
for(int j=i+1;j<n;j++)
{ cntud+=ud[j];
cntrl+=rl[j];
if(cntud==0&&cntrl==0) ans++;
}
}
printf("%d\n",ans);
return 0;
}
A. Robot Sequence的更多相关文章
- Codeforces 626A Robot Sequence
A. Robot Sequence time limit per test 2 seconds memory limit per test 256 megabytes input standard i ...
- Codeforces 626A Robot Sequence(模拟)
A. Robot Sequence time limit per test:2 seconds memory limit per test:256 megabytes input:standard i ...
- 8VC Venture Cup 2016 - Elimination Round A. Robot Sequence 暴力
A. Robot Sequence 题目连接: http://www.codeforces.com/contest/626/problem/A Description Calvin the robot ...
- Codeforces 626 A. Robot Sequence (8VC Venture Cup 2016-Elimination Round)
A. Robot Sequence time limit per test 2 seconds memory limit per test 256 megabytes input standa ...
- 前端自动化测试工具doh学习总结(二)
一.robot简介 robot是dojo框架中用来进行前端自动化测试的工具,doh主要目的在于单元测试,而robot可以用来模仿用户操作来测试UI.总所周知,Selenium也是一款比较流行的前端自动 ...
- 8VC Venture Cup 2016 - Elimination Round
在家补补题 模拟 A - Robot Sequence #include <bits/stdc++.h> char str[202]; void move(int &x, in ...
- Codeforces-8VC Venture Cup 2016-Elimination Round-626A.暴力 626B.水题 626C.二分
A. Robot Sequence time limit per test 2 seconds memory limit per test 256 megabytes input standard i ...
- Codeforces Round #389 Div.2 C. Santa Claus and Robot
time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standa ...
- CSUFT 1002 Robot Navigation
1002: Robot Navigation Time Limit: 1 Sec Memory Limit: 128 MB Submit: 4 Solved: 2 Descript ...
随机推荐
- 第三方平台正式支持接入微信公众平台JS-SDK
之前微信公众平台面向开发者开放微信内网页开发工具包,现在第三方平台也能正式支持接入微信公众平台JS-SDK了,第三方平台可以在获得公众号的授权后,通过JS-SDK帮助公众号开发和实现网页业务. 公众号 ...
- centos安装配置nginx
1.安装gcc yum install gcc 2.安装PCRE,zlib,OpenSSL(其中devel,是develop开发包的意思) yum install -y pcre pcre-devel ...
- js实现把网页table导成Excel
//导出excel function exportExcel(DivID,strTitle){ if(DivID==null) { return false; } var jXls, myWorkbo ...
- iOS文件存储路径规定
Storing Your App’s Data Efficiently https://developer.apple.com/icloud/documentation/data-storage/in ...
- 【Redis】Redis分布式集群几点说道
Redis数据量日益增大,使用的公司越来越多,不仅用于做缓存,同时趋向于存储这一块,这样必促使集群的发展,各个公司也在收集适合自己的集群方案,目前行业用的比较多的是下面几种集群架构,大部分都是采用分片 ...
- lambda 表达式
C++0x 的语法还是比较简单.下面通过几个例子来介绍下. 先是通过 std::for_each 演示一个简单的例子: ? std::for_each 和 lambda 1 2 3 4 5 6 7 8 ...
- debian下mysql主从配置
1.确保master/slave只有一份/etc/mysql/my.cnf , 不要在其他地方再有my.cnf (如/etc/my.cnf /usr/local之类) 2.master配置: 在[m ...
- cas单点注销失败Error Sending message to url endpoint
最近在做cas单点登录时,由于是单点登录.必然会涉及到单点注销,然而在做单点注销时由于对cas注销机制不了解加之测试条件所致,所有测试都是在本机下完成(机器性能较低,没用虚拟机):导致折腾了很久.网上 ...
- 使用kettle转换中的JavaScript对密码进行加密和解密
日常开发中,为了确保账号和密码的安全,时常要对密码进行加密和解密.然而kettle是怎么对密码进行加密和解密的呢? 下面的代码需要再转换中的JavaScript中运行. var encrypted_p ...
- windows下如何对mysql进行整裤备份
通常情况下备份一个数据库,直接单裤备份即可,更完善一点的会要求做到定时单裤备份.然而很多时候又由于裤实例是在太多,这样会导致备份非常耗时,因而有时候需要对整个数据库应用进行备份.那么在windows下 ...