Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive.

The update(i, val) function modifies nums by updating the element at index i to val.

Example:

Given nums = [1, 3, 5]

sumRange(0, 2) -> 9
update(1, 2)
sumRange(0, 2) -> 8

Note:

  1. The array is only modifiable by the update function.
  2. You may assume the number of calls to update and sumRange function is distributed evenly.

利用线段树解决动态区间求值问题、

class NumArray {

    class STreeNode {
int sum;
int start;
int end;
STreeNode left, right;
STreeNode(int start, int end) {
this.start = start;
this.end = end;
this.sum = 0;
}
} private STreeNode buildSTree(int[] nums, int start, int end) {
if (start > end)
return null;
else {
STreeNode node = new STreeNode(start, end);
if (start == end) {
node.sum = nums[start];
}
else {
int mid = start + (end - start) / 2;
node.left = buildSTree(nums, start, mid);
node.right = buildSTree(nums, mid+1, end);
if (node.left != null && node.right != null)
node.sum = node.left.sum + node.right.sum;
}
return node;
}
} private STreeNode root;
public NumArray(int[] nums) {
root = buildSTree(nums, 0, nums.length-1);
} public void update(int i, int val) {
update(root, i, val);
} private void update(STreeNode node, int pos, int val) {
// if (node == null)
// return;
if (node.start == pos && node.end == pos) {
node.sum = val;
return;
}
if (node.left != null && node.right != null) {
int mid = node.start + (node.end - node.start) / 2;
if (pos <= mid)
update(node.left, pos, val);
else
update(node.right, pos, val); node.sum = node.left.sum + node.right.sum;
} } public int sumRange(int i, int j) {
return sumRange(root, i, j);
} private int sumRange(STreeNode node, int i, int j) {
if (node == null)
return 0;
if (node.start == i && node.end == j)
return node.sum;
int mid = node.start + (node.end - node.start) / 2;
if (j <= mid)
return sumRange(node.left, i, j);
else if (i > mid)
return sumRange(node.right, i, j);
else
return sumRange(node.left, i, mid) + sumRange(node.right, mid+1, j);
} } /**
* Your NumArray object will be instantiated and called as such:
* NumArray obj = new NumArray(nums);
* obj.update(i,val);
* int param_2 = obj.sumRange(i,j);
*/

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