<每日一题> Day1:CodeForces.1140D.MinimumTriangulation(思维题)
参考代码:
#include <iostream>
using namespace std; int main() {
long long ans = ;
int n;
cin >> n;
for(int i = ; i <= n; i ++) {
ans += i * (i - );
}
cout << ans << endl;
return ;
}
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参考文章: https://help.aliyun.com/document_detail/92883.html