(栈)leetcode 946. Validate Stack Sequences
Given two sequences pushed and popped with distinct values, return true if and only if this could have been the result of a sequence of push and pop operations on an initially empty stack.
Example 1:
Input: pushed = [1,2,3,4,5], popped = [4,5,3,2,1]
Output: true
Explanation: We might do the following sequence:
push(1), push(2), push(3), push(4), pop() -> 4,
push(5), pop() -> 5, pop() -> 3, pop() -> 2, pop() -> 1
Example 2:
Input: pushed = [1,2,3,4,5], popped = [4,3,5,1,2]
Output: false
Explanation: 1 cannot be popped before 2.
Note:
0 <= pushed.length == popped.length <= 10000 <= pushed[i], popped[i] < 1000pushedis a permutation ofpopped.pushedandpoppedhave distinct values.
栈
C++代码:
class Solution {
public:
bool validateStackSequences(vector<int>& pushed, vector<int>& popped) {
stack<int> s;
int len = pushed.size();
int j = ;
for(int n : pushed){
s.push(n);
while(!s.empty() && j < len && s.top() == popped[j]){
s.pop();
j++;
}
}
return j == len;
}
};
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