【Codeforces Round #476 (Div. 2) [Thanks, Telegram!] B】Battleship

【链接】 我是链接,点我呀:)

【题意】

在这里输入题意

【题解】

暴力枚举船的左上角。
然后统计每个点被覆盖次数就好。

【代码】

#include <bits/stdc++.h>
#define LL long long
#define rep1(i,a,b) for (int i = a;i <= b;i++)
#define rep2(i,a,b) for (int i = a;i >= b;i--)
#define all(x) x.begin(),x.end()
#define pb push_back
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
using namespace std;

const double pi = acos(-1);
const int dx[4] = {0,0,1,-1};
const int dy[4] = {1,-1,0,0};
const int N = 100;

int n,k,num[N+10][N+10];
char s[N+10][N+10];

int main(){
	#ifdef LOCAL_DEFINE
	    freopen("rush_in.txt", "r", stdin);
	#endif
	ios::sync_with_stdio(0),cin.tie(0);
    cin >> n >> k;
    for (int i = 1;i <= n;i++) cin >>(s[i]+1);
    for (int i = 1;i <= n;i++)
        for (int j = 1;j <= n;j++){
                bool ok = true;
                for (int l = 0;l < k;l++)
                    if (j+l>n||s[i][j+l]!='.'){
                            ok = false;
                            break;
                    }
                if (ok){
                    for (int l = 0;l < k;l++)
                        num[i][j+l]++;
                }

                ok = true;
                for (int l = 0;l < k;l++)
                    if (i+l>n || s[i+l][j]!='.'){
                            ok = false;
                            break;
                    }
                if (ok && k>1)
                    for (int l = 0;l < k;l++)
                        num[i+l][j]++;

            }

    int x = 1,y = 1;
    for (int i = 1;i <= n;i++)
        for (int j = 1;j <= n;j++){
            if (num[i][j]>num[x][y]){
                x = i,y = j;
            }
        }
    cout<<x<<' '<<y<<endl;
	return 0;
}