我对\(Jhonson\)算法的理解:https://www.cnblogs.com/AKMer/p/9863620.html

题目传送门:https://www.luogu.org/problemnew/show/P1561

\(Jhonson\)裸题。

时间复杂度:\(O(nlogn)\)

空间复杂度:\(O(n)\)

代码如下:

#include <cstdio>
#include <algorithm>
using namespace std; const int maxn=25005; int n,ans; int read() {
int x=0,f=1;char ch=getchar();
for(;ch<'0'||ch>'9';ch=getchar())if(ch=='-')f=-1;
for(;ch>='0'&&ch<='9';ch=getchar())x=x*10+ch-'0';
return x*f;
} struct cow {
int a,b; bool operator<(const cow &tmp)const {
return min(a,tmp.b)<=min(tmp.a,b);
}
}p[maxn]; int main() {
n=read();
for(int i=1;i<=n;i++)
p[i].a=read(),p[i].b=read();
sort(p+1,p+n+1);int T=0;
for(int i=1;i<=n;i++) {
ans+=p[i].a;
T=p[i].b+max(T-p[i].a,0);
}
printf("%d\n",ans+T);
return 0;
}

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