LeetCode 641. Design Circular Deque
原题链接在这里:https://leetcode.com/problems/design-circular-deque/
题目:
Design your implementation of the circular double-ended queue (deque).
Your implementation should support following operations:
MyCircularDeque(k): Constructor, set the size of the deque to be k.insertFront(): Adds an item at the front of Deque. Return true if the operation is successful.insertLast(): Adds an item at the rear of Deque. Return true if the operation is successful.deleteFront(): Deletes an item from the front of Deque. Return true if the operation is successful.deleteLast(): Deletes an item from the rear of Deque. Return true if the operation is successful.getFront(): Gets the front item from the Deque. If the deque is empty, return -1.getRear(): Gets the last item from Deque. If the deque is empty, return -1.isEmpty(): Checks whether Deque is empty or not.isFull(): Checks whether Deque is full or not.
Example:
MyCircularDeque circularDeque = new MycircularDeque(3); // set the size to be 3
circularDeque.insertLast(1); // return true
circularDeque.insertLast(2); // return true
circularDeque.insertFront(3); // return true
circularDeque.insertFront(4); // return false, the queue is full
circularDeque.getRear(); // return 2
circularDeque.isFull(); // return true
circularDeque.deleteLast(); // return true
circularDeque.insertFront(4); // return true
circularDeque.getFront(); // return 4
Note:
- All values will be in the range of [0, 1000].
- The number of operations will be in the range of [1, 1000].
- Please do not use the built-in Deque library.
题解:
Use an array to maintain values.
start index pointing to queue head, initialized as -1.
end index pointing to queue tail, initialized as -1.
When insertFront, if start == -1, assign start as 0, else start = (start - 1 + k) % k. Assign new value to arr[start]. If end is -1, need to update end = start. This only happens at the beginning.
When insertLast, end = (end + 1) % k. Assign new value to arr[end]. If start is -1, need to update start = end. This only happends at the begining.
deleteFront, move start + 1.
deleteLast, move end - 1.
Time Complexity: MyCircularDeque, O(1). insertFront, O(1). insertLast, O(1). deleteFront, O(1). deleteLast, O(1). getFront, O(1). getRear, O(1). isEmpty, O(1). isEmpty, O(1).
Space: O(k).
AC Java:
class MyCircularDeque {
int [] arr;
int start;
int end;
int len;
int k;
/** Initialize your data structure here. Set the size of the deque to be k. */
public MyCircularDeque(int k) {
arr = new int[k];
start = -1;
end = -1;
len = 0;
this.k = k;
}
/** Adds an item at the front of Deque. Return true if the operation is successful. */
public boolean insertFront(int value) {
if(isFull()){
return false;
}
if(start == -1){
start = 0;
}else{
start = (start - 1 + k) % k;
}
arr[start] = value;
if(end == -1){
end = start;
}
len++;
return true;
}
/** Adds an item at the rear of Deque. Return true if the operation is successful. */
public boolean insertLast(int value) {
if(isFull()){
return false;
}
end = (end + 1) % k;
arr[end] = value;
if(start == -1){
start = end;
}
len++;
return true;
}
/** Deletes an item from the front of Deque. Return true if the operation is successful. */
public boolean deleteFront() {
if(isEmpty()){
return false;
}
start = (start + 1) % k;
len--;
return true;
}
/** Deletes an item from the rear of Deque. Return true if the operation is successful. */
public boolean deleteLast() {
if(isEmpty()){
return false;
}
end = (end - 1 + k) % k;
len--;
return true;
}
/** Get the front item from the deque. */
public int getFront() {
return isEmpty() ? -1 : arr[start];
}
/** Get the last item from the deque. */
public int getRear() {
return isEmpty() ? -1 : arr[end];
}
/** Checks whether the circular deque is empty or not. */
public boolean isEmpty() {
return len == 0;
}
/** Checks whether the circular deque is full or not. */
public boolean isFull() {
return len == k;
}
}
/**
* Your MyCircularDeque object will be instantiated and called as such:
* MyCircularDeque obj = new MyCircularDeque(k);
* boolean param_1 = obj.insertFront(value);
* boolean param_2 = obj.insertLast(value);
* boolean param_3 = obj.deleteFront();
* boolean param_4 = obj.deleteLast();
* int param_5 = obj.getFront();
* int param_6 = obj.getRear();
* boolean param_7 = obj.isEmpty();
* boolean param_8 = obj.isFull();
*/
LeetCode 641. Design Circular Deque的更多相关文章
- [LeetCode] 641.Design Circular Deque 设计环形双向队列
Design your implementation of the circular double-ended queue (deque). Your implementation should su ...
- LC 641. Design Circular Deque
Design your implementation of the circular double-ended queue (deque). Your implementation should su ...
- 【LeetCode】641. Design Circular Deque 解题报告(Python & C++)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/design-ci ...
- [LeetCode] 622.Design Circular Queue 设计环形队列
Design your implementation of the circular queue. The circular queue is a linear data structure in w ...
- LeetCode 622. Design Circular Queue
原题链接在这里:https://leetcode.com/problems/design-circular-queue/ 题目: Design your implementation of the c ...
- [LeetCode] Design Circular Deque 设计环形双向队列
Design your implementation of the circular double-ended queue (deque). Your implementation should su ...
- [Swift]LeetCode641. 设计循环双端队列 | Design Circular Deque
Design your implementation of the circular double-ended queue (deque). Your implementation should su ...
- Design Circular Deque
Design your implementation of the circular double-ended queue (deque). Your implementation should su ...
- Leetcode641.Design Circular Deque设计循环双端队列
设计实现双端队列. 你的实现需要支持以下操作: MyCircularDeque(k):构造函数,双端队列的大小为k. insertFront():将一个元素添加到双端队列头部. 如果操作成功返回 tr ...
随机推荐
- .NET Core:SignalR
在Startup中的ConfigureServices方法中配置:services.AddSignalR(); 跨域设置中需要更改设置:services.AddCors(options => o ...
- [bash-shell]构建WebAPI项目并且发布到本地
:: 清理log文件 del /S *.log echo Publish parameters initializing... ::These parameters are not used for ...
- asp.net core 2.1 容器中使用 System.Drawing.Common 的问题
- nginx产生【413 request entity too large】错误的原因与解决方法
项目上在做上传文件(清单导入)的时候产生了这个错误: 从字面上看,说的是请求的实体太大的问题,那么可以联想到是HTTP请求中的Body大小被限制了的原因. Nginx中的[client_max_bod ...
- 适配器模式(Adapter Pattern)--设计模式
在生活中,想用苹果充电线给安卓的手机充电时,因为两者的接口不一样,会导致充电口无法进行匹配, 这时候,就需要适配器,将安卓的充电口转化为苹果的接口,这样就可以充电啦.已有的类与新的接口不兼容问题是很普 ...
- laravel 一些好用的GitHub项目包
链接地址:好用的GitHub包
- js 固定div 不随着滚动条滚动
css .fixed { position: fixed; top:; } javascript function my$(id) { return document.getElementById(i ...
- Python文件属性模块Os.path
Python文件属性模块Os.path介绍 os.path模块主要用于文件属性获取和判断,在编程中会经常用到,需要熟练掌握.以下是该模块的几种常用方法. os.path官方文档:http://docs ...
- 双栈(Dual Stack)
参考博客: 双栈数据结构: https://blog.csdn.net/hebtu666/article/details/83011115 https://blog.csdn.net/cainv89/ ...
- php7.3升级后CI框架session失效session不能读取的问题
php7.3升级后CI框架session失效session不能读取的问题 框架ci3.0.2,php服务器从5升级到7.x后发现session失效了ci无法设置session的问题根本原因在,libr ...