LC 641. Design Circular Deque
Design your implementation of the circular double-ended queue (deque).
Your implementation should support following operations:
MyCircularDeque(k): Constructor, set the size of the deque to be k.insertFront(): Adds an item at the front of Deque. Return true if the operation is successful.insertLast(): Adds an item at the rear of Deque. Return true if the operation is successful.deleteFront(): Deletes an item from the front of Deque. Return true if the operation is successful.deleteLast(): Deletes an item from the rear of Deque. Return true if the operation is successful.getFront(): Gets the front item from the Deque. If the deque is empty, return -1.getRear(): Gets the last item from Deque. If the deque is empty, return -1.isEmpty(): Checks whether Deque is empty or not.isFull(): Checks whether Deque is full or not.
Example:
MyCircularDeque circularDeque = new MycircularDeque(3); // set the size to be 3
circularDeque.insertLast(1); // return true
circularDeque.insertLast(2); // return true
circularDeque.insertFront(3); // return true
circularDeque.insertFront(4); // return false, the queue is full
circularDeque.getRear(); // return 2
circularDeque.isFull(); // return true
circularDeque.deleteLast(); // return true
circularDeque.insertFront(4); // return true
circularDeque.getFront(); // return 4
Note:
- All values will be in the range of [0, 1000].
- The number of operations will be in the range of [1, 1000].
- Please do not use the built-in Deque library.
Runtime: 112 ms, faster than 32.91% of Java online submissions for Design Circular Deque.
class MyCircularDeque {
private Deque<Integer> dq = new LinkedList<>();
private int cap;
/** Initialize your data structure here. Set the size of the deque to be k. */
public MyCircularDeque(int k) {
cap = k;
}
/** Adds an item at the front of Deque. Return true if the operation is successful. */
public boolean insertFront(int value) {
if(dq.size() == cap) return false;
dq.offerFirst(value);
return true;
}
/** Adds an item at the rear of Deque. Return true if the operation is successful. */
public boolean insertLast(int value) {
if(dq.size() == cap) return false;
dq.offerLast(value);
return true;
}
/** Deletes an item from the front of Deque. Return true if the operation is successful. */
public boolean deleteFront() {
if(dq.size() == ) return false;
dq.removeFirst();
return true;
}
/** Deletes an item from the rear of Deque. Return true if the operation is successful. */
public boolean deleteLast() {
if(dq.size() == ) return false;
dq.removeLast();
return true;
}
/** Get the front item from the deque. */
public int getFront() {
if(dq.size() == ) return -;
return dq.peekFirst();
}
/** Get the last item from the deque. */
public int getRear() {
if(dq.size() == ) return -;
return dq.peekLast();
}
/** Checks whether the circular deque is empty or not. */
public boolean isEmpty() {
return dq.size() == ;
}
/** Checks whether the circular deque is full or not. */
public boolean isFull() {
return dq.size() == cap;
}
}
LC 641. Design Circular Deque的更多相关文章
- LeetCode 641. Design Circular Deque
原题链接在这里:https://leetcode.com/problems/design-circular-deque/ 题目: Design your implementation of the c ...
- [LeetCode] 641.Design Circular Deque 设计环形双向队列
Design your implementation of the circular double-ended queue (deque). Your implementation should su ...
- 【LeetCode】641. Design Circular Deque 解题报告(Python & C++)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/design-ci ...
- [Swift]LeetCode641. 设计循环双端队列 | Design Circular Deque
Design your implementation of the circular double-ended queue (deque). Your implementation should su ...
- [LeetCode] Design Circular Deque 设计环形双向队列
Design your implementation of the circular double-ended queue (deque). Your implementation should su ...
- Design Circular Deque
Design your implementation of the circular double-ended queue (deque). Your implementation should su ...
- Leetcode641.Design Circular Deque设计循环双端队列
设计实现双端队列. 你的实现需要支持以下操作: MyCircularDeque(k):构造函数,双端队列的大小为k. insertFront():将一个元素添加到双端队列头部. 如果操作成功返回 tr ...
- C#LeetCode刷题之#641-设计循环双端队列(Design Circular Deque)
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/4132 访问. 设计实现双端队列. 你的实现需要支持以下操作: M ...
- [LeetCode] 622.Design Circular Queue 设计环形队列
Design your implementation of the circular queue. The circular queue is a linear data structure in w ...
随机推荐
- Image Processing and Computer Vision_Review:A survey of recent advances in visual feature detection—2014.08
翻译 一项关于视觉特征检测的最新进展概述——http://tongtianta.site/paper/56761 摘要 -特征检测是计算机视觉和图像处理中的基础和重要问题.这是一个低级处理步骤,它是基 ...
- 【异常】azkaban.executor.ExecutorManagerException: No active executors found
1 azkaban启动异常 没有找到活动的executors,需在MySQL数据库里设置端口为12321的executors表的active为1 update azkaban.executors ...
- (2)python开发环境搭建
电脑配置:推荐i7以上处理器,8g内存就ok了,python对电脑还是稍微有点要求的 当我们编写Python代码时,我们得到的是一个包含Python代码的以.py为扩展名的文本文件.要运行代码,就需要 ...
- gitlab 错误处理
用gitolite新建项目,clone后首次push,可能会出现: $ git push No refs in common and none specified; doing nothing. Pe ...
- 对List<Map>里的map的某个属性重复的值进行处理的方法
package test; import java.util.*;import java.util.stream.Collectors; public class Test5 { public sta ...
- FlexPaper的深入了解和应用
作者:tabb_ 零下疯度 推荐:无痕客 最近做项目需要用到flexpaper,所以想借此机会好好的研究一下. 这是官方的下载地址:http://flexpaper.devaldi.com/downl ...
- vue初级尝试
为了跟上前端后台化的潮流,本少不得不开始关注vue,下列上机代码是针对App.vue进行的更改 数据渲染----一般键值对,数组,对象和对象数组 <template> <div id ...
- vue 01 练习
1.有 红.黄.蓝 三个按钮,以及一个200x200矩形框box,点击不同的按钮,box的颜色会被切换为指定的颜色 <!DOCTYPE html> <html lang=" ...
- ubuntu16.04卡死的解决办法
1.输入命令:top 找到chrome所占用的线程的pid. 2.kill pid
- 开源笔记软件Joplin
Joplin is a free, open source note taking and to-do application, which can handle a large number of ...