codeforces 1287A -Angry Students(模拟)
It’s a walking tour day in SIS.Winter, so t groups of students are visiting Torzhok. Streets of Torzhok are so narrow that students have to go in a row one after another.
Initially, some students are angry. Let’s describe a group of students by a string of capital letters “A” and “P”:
“A” corresponds to an angry student
“P” corresponds to a patient student
Such string describes the row from the last to the first student.
Every minute every angry student throws a snowball at the next student. Formally, if an angry student corresponds to the character with index i in the string describing a group then they will throw a snowball at the student that corresponds to the character with index i+1 (students are given from the last to the first student). If the target student was not angry yet, they become angry. Even if the first (the rightmost in the string) student is angry, they don’t throw a snowball since there is no one in front of them.
Let’s look at the first example test. The row initially looks like this: PPAP. Then, after a minute the only single angry student will throw a snowball at the student in front of them, and they also become angry: PPAA. After that, no more students will become angry.
Your task is to help SIS.Winter teachers to determine the last moment a student becomes angry for every group.
Input
The first line contains a single integer t — the number of groups of students (1≤t≤100). The following 2t lines contain descriptions of groups of students.
The description of the group starts with an integer ki (1≤ki≤100) — the number of students in the group, followed by a string si, consisting of ki letters “A” and “P”, which describes the i-th group of students.
Output
For every group output single integer — the last moment a student becomes angry.
Examples
Input
1
4
PPAP
Output
1
Input
3
12
APPAPPPAPPPP
3
AAP
3
PPA
Output
4
1
0
Note
In the first test, after 1 minute the state of students becomes PPAA. After that, no new angry students will appear.
In the second tets, state of students in the first group is:
after 1 minute — AAPAAPPAAPPP
after 2 minutes — AAAAAAPAAAPP
after 3 minutes — AAAAAAAAAAAP
after 4 minutes all 12 students are angry
In the second group after 1 minute, all students are angry.
#include <bits/stdc++.h>
using namespace std;
template <typename t>
void read(t &x)
{
char ch = getchar();
x = 0;
t f = 1;
while (ch < '0' || ch > '9')
f = (ch == '-' ? -1 : f), ch = getchar();
while (ch >= '0' && ch <= '9')
x = x * 10 + ch - '0', ch = getchar();
x *= f;
}
#define wi(n) printf("%d ", n)
#define wl(n) printf("%lld ", n)
#define rep(m, n, i) for (int i = m; i < n; ++i)
#define rrep(m, n, i) for (int i = m; i > n; --i)
#define P puts(" ")
typedef long long ll;
#define MOD 1000000007
#define mp(a, b) make_pair(a, b)
#define N 10005
#define fil(a, n) rep(0, n, i) read(a[i])
//---------------https://lunatic.blog.csdn.net/-------------------//
string s;
int k,t;
int main()
{
read(t);
while (t--)
{
read(k);
cin >> s;
int count = 0, max = 0, flag = 0;
for (int i = 0; i < k;)
if (s[i] == 'A')
{
count = 0, i++;
while (s[i] == 'P')
count++, i++;
if (count > max)
max = count;
}
else
i++;
wi(max);
P;
}
return 0;
}
codeforces 1287A -Angry Students(模拟)的更多相关文章
- A. Angry Students
网址:http://codeforces.com/problemset/problem/1287/A It's a walking tour day in SIS.Winter, so tt grou ...
- [模拟]Codeforces Circle of Students
Circle of Students time limit per test 2 seconds memory limit per test 256 megabytes input standard ...
- Codeforces 738D. Sea Battle 模拟
D. Sea Battle time limit per test: 1 second memory limit per test :256 megabytes input: standard inp ...
- Codeforces 626A Robot Sequence(模拟)
A. Robot Sequence time limit per test:2 seconds memory limit per test:256 megabytes input:standard i ...
- CodeForces - 589D(暴力+模拟)
题目链接:http://codeforces.com/problemset/problem/589/D 题目大意:给出n个人行走的开始时刻,开始时间和结束时间,求每个人分别能跟多少人相遇打招呼(每两人 ...
- Codeforces 767B. The Queue 模拟题
B. The Queue time limit per test:1 second memory limit per test:256 megabytes input:standard input o ...
- Codeforces 704A Thor 队列模拟
题目大意:托尔有一部手机可执行三种操作 1.x APP产生一个新消息 2.读取x App已产生的所有消息 3.读取前t个产生的消息 问每次操作后未读取的消息的数量 题目思路: 队列模拟,坑点在于竟然卡 ...
- 【Codeforces 332C】Students' Revenge
Codeforces 332 C 我爱对拍,对拍使我快乐... 题意:有\(n\)个议题,学生们会让议会同意\(p\)个,其中主席会执行\(k\)个, 每一个议题执行后主席会掉\(a_i\)的头发,不 ...
- Vasya And The Mushrooms CodeForces - 1016C (前缀和模拟)
大意: 给定2*n的矩阵, 每个格子有权值, 走到一个格子的贡献为之前走的步数*权值, 每个格子只能走一次, 求走完所有格子最大贡献. 沙茶模拟打了一个小时总算打出来了 #include <io ...
随机推荐
- stdio.h file not found mac catalina clion 头文件 找不到
问题:mac update catalina 版本之后引发的include文件问题 近期Mac 版本升级到catalina版本,使用CLion调试c/c++程序,莫名其妙的发现,有些头文件incl ...
- Mysql大数据量问题与解决
今日格言:了解了为什么,问题就解决了一半. Mysql 单表适合的最大数据量是多少? 我们说 Mysql 单表适合存储的最大数据量,自然不是说能够存储的最大数据量,如果是说能够存储的最大量,那么,如果 ...
- matplotlib TransformWrapper
2020-04-09 23:26:53 --Edit by yangray TransformWrapper 是Transform的子类, 支持在运行中替掉一个变换(可以是不同类型, 但维度必须相同) ...
- 如何配置多个Spring的xml配置文件(多模块配置)
如何使用多个Spring的xml配置文件(多模块配置) (2009-08-22 13:42:43) 如何使用多个Spring的xml配置文件(多模块配置) 在用Struts Spring Hibe ...
- 1、2、2、3、4、5这六个数字,用java写一个main函数,打印出所有不同的排列, 如:512234、212345等. 要求:”4”不能在第三位,”3”与”5”不能相连。
private static String[] mustExistNumber = new String[] { "1", "2", "2" ...
- qad progress数据库启动出错解决
1. 启动时报:SYSTEM ERROR: Wrong dbkey in block. Found 0, should be 6342528 in area 36. (439) ** Save fi ...
- 造轮子:实现一个简易的 Spring IoC 容器
作者:DeppWang.原文地址 我通过实现一个简易的 Spring IoC 容器,算是入门了 Spring 框架.本文是对实现过程的一个总结提炼,需要配合源码阅读,源码地址. 结合本文和源码,你应该 ...
- Leetcode1353-最多可以参加的会议数目
题目描述: 给你一个数组 events,其中 events[i] = [startDayi, endDayi] ,表示会议 i 开始于startDayi ,结束于endDayi . 你可以在满足 st ...
- 详解 Arrays类
请关注本人博文--<详解 普通数组 -- Arrays类 与 浅克隆> Arrays类: 概述: 针对数组进行操作的工具类.它提供了对于数组的值的排序.查找等功能. 现在,本人来展示一下A ...
- 全网最全最细的jmeter接口测试教程以及接口测试流程详解
一.Jmeter简介 Jmeter是由Apache公司开发的一个纯Java的开源项目,即可以用于做接口测试也可以用于做性能测试. Jmeter具备高移植性,可以实现跨平台运行. Jmeter可以实 ...