[leetcode]387. First Unique Character in a String第一个不重复字母

Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.

Examples:

s = "leetcode"
return 0.

s = "loveleetcode",
return 2.

Note: You may assume the string contain only lowercase letters.

思路

1.  use int array to simplify a hashmap

2. one pass to mark each char's occurrence

3. second pass to check 1st index whose char's occurrence == 1

代码

 class Solution {
      public int firstUniqChar(String s) {
        int map [] = new int[256];
         for(int i = 0; i < s.length(); i ++)
             map [s.charAt(i) ] ++;
         for(int i = 0; i < s.length(); i ++)
             if(map [s.charAt(i) ] == 1)
                 return i;
         return -1;
     }
 }