Python3 计算城市距离

利用上一篇得到的城市经纬度算城市距离

 import requests
 from math import radians, cos, sin, asin, sqrt  

 def geocode(address):
     url= 'http://api.map.baidu.com/geocoder?output=json&key=f247cdb592eb43ebac6ccd27f796e2d2&address='+str(address)
     response = requests.get(url)
     answer = response.json()
     #print(address + "的经纬度：", answer['geocodes'][0]['location'])
     if answer['status']  == 'INVALID_PARAMETERS':
         return 0,0
     else:
         lon = float(answer['result']['location']['lng'])
         lat = float(answer['result']['location']['lat'])
         return lon ,lat
 def distence(address1,address2):

     lon1, lat1 = geocode(address1)
     lon2, lat2 = geocode(address2)  

     # 将十进制度数转化为弧度
     lon1, lat1, lon2, lat2 = map(radians, [lon1, lat1, lon2, lat2])  

     # haversine公式
     dlon = lon2 - lon1
     dlat = lat2 - lat1
     a = sin(dlat/2)**2 + cos(lat1) * cos(lat2) * sin(dlon/2)**2
     c = 2 * asin(sqrt(a))
     r = 6371 # 地球平均半径，单位为公里
     return int(c * r)
 def distence_list(city_array):
     distence_array = []
     for i in range(a.shape[0]):
         distence_array.append(distence(city_array[i][0],city_array[i][1]))
     return np.array(distence_array)