1098. Insertion or Heap Sort (25)
According to Wikipedia:
Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted list, and inserts it there. It repeats until no input elements remain.
Heap sort divides its input into a sorted and an unsorted region, and it iteratively shrinks the unsorted region by extracting the largest element and moving that to the sorted region. it involves the use of a heap data structure rather than a linear-time search to find the maximum.
Now given the initial sequence of integers, together with a sequence which is a result of several iterations of some sorting method, can you tell which sorting method we are using?
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (<=100). Then in the next line, N integers are given as the initial sequence. The last line contains the partially sorted sequence of the N numbers. It is assumed that the target sequence is always ascending. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print in the first line either "Insertion Sort" or "Heap Sort" to indicate the method used to obtain the partial result. Then run this method for one more iteration and output in the second line the resuling sequence. It is guaranteed that the answer is unique for each test case. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.
Sample Input 1:
10
3 1 2 8 7 5 9 4 6 0
1 2 3 7 8 5 9 4 6 0
/*
* 这题思路比较简单:
1.中间序列 前面有序 后面和原始序列相同 则为插入排序。
2.堆排序 后面的数 应该是原数组中从大到小的数 如果遇到不满足这个条件的数 说明堆排序即将进行到当前这个数
在走一趟堆排序即可
*/
#include "iostream"
#include "algorithm"
using namespace std;bool judge(int a[],int b[],int n) { /* 判断是不是插入排序 */
int len = ;
int i;
for ( i = ; i < n - ; i++)
if (b[i] > b[i + ]) {
len = i + ;
break;
}
for (i=len; i < n; i++) {
if (a[i] != b[i])
return false;
}
sort(b, b + len + );
return true;
}
void print(int a[], int n) {
for (int i = ; i < n; i++) {
if (i == )
cout << a[i];
else
cout << " " << a[i];
}
cout << endl;
}
void adjust(int b[], int n) {
int parent = ;
int child;
int temp = b[parent];
for (; parent * + <= n;parent = child) {
child = parent * + ;
if (child + <= n && b[child + ] > b[child])
child = child + ;
if (b[child] <= temp)
break;
b[parent] = b[child];
}
b[parent] = temp;
}
int main() {
int a[], b[];
int n;
cin >> n;
for (int i = ; i < n; i++) {
cin >> a[i];
}
for (int i = ; i < n; i++) {
cin >> b[i];
}
if (judge(a, b, n)) {
cout << "Insertion Sort" << endl;
print(b, n);
}
else {
cout << "Heap Sort" << endl;
int i;
sort(a, a + n);
for (i = n-; i >= ; i--) {
if (a[i] != b[i])
break;
}
int temp = b[];
b[] = b[i];
b[i] = temp;
adjust(b,i-); /* 剩下的元素调整为最大堆 */
print(b, n);
}
}
Sample Output 1:
Insertion Sort
1 2 3 5 7 8 9 4 6 0
Sample Input 2:
10
3 1 2 8 7 5 9 4 6 0
6 4 5 1 0 3 2 7 8 9
Sample Output 2:
Heap Sort
5 4 3 1 0 2 6 7 8 9
1098. Insertion or Heap Sort (25)的更多相关文章
- pat 甲级 1098. Insertion or Heap Sort (25)
1098. Insertion or Heap Sort (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yu ...
- PAT (Advanced Level) Practise - 1098. Insertion or Heap Sort (25)
http://www.patest.cn/contests/pat-a-practise/1098 According to Wikipedia: Insertion sort iterates, c ...
- PAT (Advanced Level) 1098. Insertion or Heap Sort (25)
简单题.判断一下是插排还是堆排. #include<cstdio> #include<cstring> #include<cmath> #include<ve ...
- PAT甲题题解1098. Insertion or Heap Sort (25)-(插入排序和堆排序)
题目就是给两个序列,第一个是排序前的,第二个是排序中的,判断它是采用插入排序还是堆排序,并且输出下一次操作后的序列. 插入排序的特点就是,前面是从小到大排列的,后面就与原序列相同. 堆排序的特点就是, ...
- 【PAT甲级】1098 Insertion or Heap Sort (25 分)
题意: 输入一个正整数N(<=100),接着输入两行N个数,表示原数组和经过一定次数排序后的数组.判断是经过插入排序还是堆排序并输出再次经过该排序后的数组(数据保证答案唯一). AAAAAcce ...
- PAT Advanced 1098 Insertion or Heap Sort (25) [heap sort(堆排序)]
题目 According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and ...
- 1098 Insertion or Heap Sort (25分)
According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and gr ...
- PAT甲级——1098 Insertion or Heap Sort (插入排序、堆排序)
本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90941941 1098 Insertion or Heap So ...
- pat1098. Insertion or Heap Sort (25)
1098. Insertion or Heap Sort (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yu ...
随机推荐
- Android:简单的开场界面
接通过ImageView创建一个全屏的图片: <?xml version="1.0" encoding="utf-8"?> <LinearLa ...
- 删除appcompat_v7会出很多错误
创建工程的时候会出现appcompat_v7这个文件夹 手贱删除后,发现出错了 说明test项目是依赖于appcompat_v7包的,所以这个appcompat_v7包是不能被删除的. appcomp ...
- Razor视图引擎的基本概念与法语
Razor 视图引擎的特点: 简洁.富于表现.流畅 尽量减少页面代码的输入,实现快速流畅的编程工作 不必明确为服务器代码标记起始与结束符,Razor 能智能判断,这样让页面看清洁,代码方便阅读 asp ...
- sqlmap批量扫描burpsuite请求日志记录
sqlmap可以批量扫描包含有request的日志文件,而request日志文件可以通过burpsuite来获取, 因此通过sqlmap结合burpsuite工具,可以更加高效的对应用程序是否存在SQ ...
- knowledge about apache
http://wenku.baidu.com/link?url=6O51BQJdtFRFWDGszKfN3aK7IY92QTCpuc7miBhRLazXvxL5gXb18B_TqIdi3EruX1o_ ...
- SOA基础
每个系统上都有多种业务逻辑,这就像在一个小超市中,一个人负责收银.清洁.摆货.咨询等各种各样的事情,当来超市的顾客多到一定程度,这个人就没办法再负责这么多的事情了,系统也同样如此. 第一个现象就是系统 ...
- 1890. Money out of Thin Air(线段树 dfs转换区间)
1890 将树的每个节点都转换为区间的形式 然后再利用线段树对结点更新 这题用了延迟标记 相对普通线段树 多了dfs的转换 把所要求的转换为某段区间 RE了N次 最后没办法了 记得有个加栈的语句 拿来 ...
- Android 之 内存管理-查看内存泄露(三)
概述 在android的开发中,要时刻主要内存的分配和垃圾回收,因为系统为每一个dalvik虚拟机分配的内存是有限的,在google的G1中,分配的最大堆大小只有16M,后来的机器一般都为24M,实在 ...
- POJ 2586 Y2K Accounting Bug(贪心)
题目连接:http://poj.org/problem?id=2586 题意:次(1-5.2-6.3-7.4-8.5-9.6-10.7-11.8-12),次统计的结果全部是亏空(盈利-亏空<0) ...
- 请用一句话概括JSONP
服务器调用客户端的函数(即回调函数),在客户端就能拿到服务端传入的参数(即返回结果)