Another Rock-Paper-Scissors Problem

题目连接:

http://codeforces.com/gym/100015/attachments

Description

Sonny uses a very peculiar pattern when it comes to playing rock-paper-scissors. He likes to vary his moves

so that his opponent can’t beat him with his own strategy.

Sonny will play rock (R) on his first game, followed by paper (P) and scissors (S) for his second and

third games, respectively. But what if someone else is using the same strategy? To thwart those opponents,

he’ll then play paper to beat rock, scissors to beat paper, and rock to beat scissors, in that order, for his 4th

through 6th games. After that, he’ll play scissors, rock, and paper for games 7–9 to beat anyone copying

his last set of moves. Now we’re back to the original order—rock, paper, scissors—but instead of being

predictable and using the same moves, do you know what would be better? You guessed it! Sonny then

plays the sequence of moves that would beat anyone trying to copy his whole strategy from his first move,

and on it goes...

To recap, in symbolic form, Sonny’s rock-paper-scissors moves look like this:

RPSPSRSRPPSRSRPRPSSRPRPSPSRPSRSRPRPSSRPRPSPSRRPSPSRSRP ...

The spaces are present only to help show Sonny’s playing pattern and do not alter what move he’ll play on

a certain game.

Naturally, your job is to beat Sonny at his own game! If you know the number of the game that you’ll

be playing against Sonny, can you figure out what move you would need to play in order to beat him?

Input

Each line of the input contains a single integer N,1 ! N ! 1012, the number of the game you’ll be playing

against Sonny. An integer N = 1 indicates it would be Sonny’s first game, N = 7 indicates it would be the

7th game, and so forth. The input terminates with a line with N = 0. For example:

1

7

33

0

Warning: N may be large enough to overflow a 32-bit integer, so be sure to use a larger data type (i.e.

long in Java or long long in C/C++) in your program.

Output

For each test case, output a single line which contains the letter corresponding to the move you would need

to play to beat Sonny on that game. For example, the correct output for the sample input above would be:

P

R

S

Sample Input

1

7

33

0

Sample Output

P

R

S

Hint

题意

剪刀石头布

初始串,RPS

每次操作如下:设现在的串为S

1、将之前的串全部击败,得到S'

2、将S'打败,然后得到S''

然后给你第i位,然后输出打败第i位的策略

题解:

找找规律之后会发现,这个串类似于3进制一样的

比如说23,他是23->14->5->2这样过来的

然后我们只用算他是从哪儿过来的,迭代了几次就好了

代码

#include<bits/stdc++.h>
using namespace std; const long long limit = 1000000000050LL;
vector<long long> three;
string solve(long long n,long long step)
{
if(n==1)
{
if(step%3==0)
return "P";
else if(step%3==1)
return "S";
else
return "R";
}
if(n==2)
{
if(step%3==0)
return "S";
else if(step%3==1)
return "R";
else
return "P";
}
if(n==3)
{
if(step%3==0)
return "R";
else if(step%3==1)
return "P";
else return "S";
}
}
int main()
{
long long k = 3;
for(int i=0;;i++)
{
three.push_back(k);
k*=3;
if(k>limit)
break;
}
long long n;
while(cin>>n)
{
if(n==0)break;
int step = 0;
while(n>3)
{
n-=*--lower_bound(three.begin(),three.end(),n);
step++;
}
cout<<solve(n,step)<<endl;
}
}

Codeforces Gym 100015A Another Rock-Paper-Scissors Problem 找规律的更多相关文章

  1. Gym 101194A / UVALive 7897 - Number Theory Problem - [找规律水题][2016 EC-Final Problem A]

    题目链接: http://codeforces.com/gym/101194/attachments https://icpcarchive.ecs.baylor.edu/index.php?opti ...

  2. 2018 ACM-ICPC 中国大学生程序设计竞赛线上赛 H题 Rock Paper Scissors Lizard Spock.(FFT字符串匹配)

    2018 ACM-ICPC 中国大学生程序设计竞赛线上赛:https://www.jisuanke.com/contest/1227 题目链接:https://nanti.jisuanke.com/t ...

  3. Gym - 101667H - Rock Paper Scissors FFT 求区间相同个数

    Gym - 101667H:https://vjudge.net/problem/Gym-101667H 参考:https://blog.csdn.net/weixin_37517391/articl ...

  4. Codeforces D. Little Elephant and Interval(思维找规律数位dp)

    题目描述: Little Elephant and Interval time limit per test 2 seconds memory limit per test 256 megabytes ...

  5. FFT(Rock Paper Scissors Gym - 101667H)

    题目链接:https://vjudge.net/problem/Gym-101667H 题目大意:首先给你两个字符串,R代表石头,P代表布,S代表剪刀,第一个字符串代表第一个人每一次出的类型,第二个字 ...

  6. SDUT 3568 Rock Paper Scissors 状压统计

    就是改成把一个字符串改成三进制状压,然后分成前5位,后5位统计, 然后直接统计 f[i][j][k]代表,后5局状压为k的,前5局比和j状态比输了5局的有多少个人 复杂度是O(T*30000*25*m ...

  7. Gym101667 H. Rock Paper Scissors

    将第二个字符串改成能赢对方时对方的字符并倒序后,字符串匹配就是卷积的过程. 那么就枚举字符做三次卷积即可. #include <bits/stdc++.h> struct Complex ...

  8. 【题解】CF1426E Rock, Paper, Scissors

    题目戳我 \(\text{Solution:}\) 考虑第二问,赢的局数最小,即输和平的局数最多. 考虑网络流,\(1,2,3\)表示\(Alice\)选择的三种可能性,\(4,5,6\)同理. 它们 ...

  9. 题解 CF1426E - Rock, Paper, Scissors

    一眼题. 第一问很简单吧,就是每个 \(\tt Alice\) 能赢的都尽量让他赢. 第二问很简单吧,就是让 \(\tt Alice\) 输的或平局的尽量多,于是跑个网络最大流.\(1 - 3\) 的 ...

随机推荐

  1. Java并发编程-可重入锁

    可重入锁,也叫做递归锁,指的是同一线程 外层函数获得锁之后 ,内层递归函数仍可以获取该锁而不受影响.在JAVA环境下 ReentrantLock 和synchronized 都是 可重入锁. publ ...

  2. xp的虚拟机如何访问本地主机上的文件

    1.选中虚拟机,右键选择Settings,在options选项卡里选择Shared Folders,然后在右边设置要共享的文件夹. 2.power on 虚拟机,然后在虚拟机的VM菜单中,选择“Ins ...

  3. ansible安装及问题解决

    本文主要用来安装ansible,在进行安装的时候,也可以使用其他的版本进行安装,本文主要讲述安装ansible的步骤,还有常用问题的解决. 1.查看python版本 由此可以看到python的版本为2 ...

  4. PHPSTORM 与 Xdebug 配合调试

    基本的配置可以参考网上的文档, 浏览器中装插件(xdebug)或直接在请求中加上如下的参数也可启动调试 ?XDEBUG_SESSION_START=PHPSTORM

  5. 开扒php内核函数,第三篇 implode

    一开始觉得implode挺容易实现,但是写着写着才发现是挺复杂的,不说啦 来看看implode的用法吧 <?php $arr = array('Hello','World!','Beautifu ...

  6. map,hash_map和unordered_map 实现比较

    map介绍 Map是STL[1]的一个关联容器,它提供一对一(其中第一个可以称为关键字,每个关键字只能在map中出现一次,第二个可能称为该关键字的值)的数据处理能力,由于这个特性,它完成有可能在我们处 ...

  7. TopFreeTheme精选免费模板【20130619】

    今天给大家推荐7款最新精选的WordPress主题和一个WooCommerce订单跟踪插件,如果你有更换自己博客主题的想法或者正要做自己的博客,不妨试试.一些是WordPress商业模板,但都可以免费 ...

  8. 【转】Hive导入10G数据的测试

    原博文出自于: http://blog.fens.me/hadoop-hive-10g/ 感谢! Hive导入10G数据的测试 让Hadoop跑在云端系列文章,介绍了如何整合虚拟化和Hadoop,让H ...

  9. 创建一个EMS 扩展包

    EMS Package 向导: File > New > Other > Delphi projects > EMS > EMS Package Empty packag ...

  10. 第三次作业之Calculator项目随笔

    附:Github的链接:https://github.com/mingyueanyao/object-oriented/tree/master/Calculator 1.初见题目: 第一眼看到题目最大 ...