Description

Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them. 
 

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single line with several words. There will be at most 1000 characters in a line. 
 

Output

For each test case, you should output the text which is processed. 
 

Sample Input

3
olleh !dlrow
m'I morf .udh
I ekil .mca
 

Sample Output

 #include<iostream>
#include<cstring>
#include<cstdio>
#include<algorithm>
using namespace std;
int main()
{
char a[];
int n;
scanf("%d",&n);
getchar();
while(n--)
{
gets(a);
int len=strlen(a);
int next[],m=;
for(int i=;i<=len;i++)
{
if(a[i]==' '||i==len)
{
for(int j=i-;j>=&&a[j]!=' ';j--)
{
next[m++]=j;
}
}
if(a[i]==' ')
{
next[m++]=i;
}
}
for(int i=;i<len;i++)
{
putchar(a[next[i]]);
}
printf("\n");
}
}
hello world! I'm from hdu. I like acm.

Hint

 Remember to use getchar() to read '\n' after the interger T, then you may use gets() to read a line and process it.
         
 
 

CDZSC_2015寒假新人(1)——基础 g的更多相关文章

  1. CDZSC_2015寒假新人(2)——数学 G

    G - G Time Limit:3000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status ...

  2. CDZSC_2015寒假新人(1)——基础 e

    Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever ...

  3. CDZSC_2015寒假新人(1)——基础 i

    Description “Point, point, life of student!” This is a ballad(歌谣)well known in colleges, and you mus ...

  4. CDZSC_2015寒假新人(1)——基础 h

    Description Ignatius was born in a leap year, so he want to know when he could hold his birthday par ...

  5. CDZSC_2015寒假新人(1)——基础 f

    Description An inch worm is at the bottom of a well n inches deep. It has enough energy to climb u i ...

  6. CDZSC_2015寒假新人(1)——基础 d

    Description These days, I am thinking about a question, how can I get a problem as easy as A+B? It i ...

  7. CDZSC_2015寒假新人(1)——基础 c

    Description FatMouse prepared M pounds of cat food, ready to trade with the cats guarding the wareho ...

  8. CDZSC_2015寒假新人(1)——基础 b

    Description The highest building in our city has only one elevator. A request list is made up with N ...

  9. CDZSC_2015寒假新人(1)——基础 a

    Description Contest time again! How excited it is to see balloons floating around. But to tell you a ...

随机推荐

  1. C# txt文件读写

    //读取文件内容 (1).使用FileStream类进行文件的读取,并将它转换成char数组,然后输出. ]; ]; public void Read() { try { FileStream fil ...

  2. js 框架及uI框架

    转载自:http://www.techweb.com.cn/network/system/2015-12-23/2245809.shtml 这篇文章主要描述现今流行的一些 Javascript web ...

  3. 实现Web虚拟现实的最轻松方案—A-Frame框架

    问题 随着vr的热度那么web虚拟现实是否可行 1. 实现Web虚拟现实的最轻松方案 A-Frame A-Frame是一款开源的可通过定制HTML元素构建WebVR方案的框架.有了这个框架,Web程序 ...

  4. T4 模板自动生成带注释的实体类文件

    T4 模板自动生成带注释的实体类文件 - 只需要一个 SqlSugar.dll 生成实体就是这么简单,只要建一个T4文件和 文件夹里面放一个DLL. 使用T4模板教程 步骤1 创建T4模板 如果你没有 ...

  5. Android-5 理解context

    context -- 用来访问全局信息 Application用途 Application生命周期 深入理解 Context http://blog.csdn.net/z1074971432/arti ...

  6. 实现在线阅读pdf功能--php

    在网上找了很久,想要实现一个在线阅读word,pdf文件的功能,网上的资料很多,但是提到真正怎么实现的比较少.现在我来简单说明一下,我实现的过程. 我现在只能实现在线阅读pdf(将word等转换成pd ...

  7. 启动Tomcat一闪而过解决

    打开apache-tomcat-6.0.32/bing/catalina.bat在首行添加: set JAVA_HOME=C:\Program Files\Java\jdk1.6.0_07 就可以了.

  8. Netbeans7.4+Weblogic11g+Spring3.2.4操作JdbcTemplate

    第一步:在Weblgic11g管理界面:http://localhost:7001/console 中建立数据源,我建立的jndi名称为:sjsstjndi 第二步:需要导入spring的以下包:使用 ...

  9. sgu To xor or not to xor

    题意:从n个数中,选择一些数,使得异或最大. #include <cstdio> #include <cstring> #include <algorithm> # ...

  10. .NET 使用unity实现依赖注入

    原文地址:http://www.cnblogs.com/wujy/p/3317795.html 一:理论部分 依赖注入:这是 Ioc 模式的一种特殊情况,是一种基于改变对象的行为而不改变类的内部的接口 ...